A universal method for left-hand alignment of a sequence of equalitiesCan I get a widebar without using the...

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A universal method for left-hand alignment of a sequence of equalities

Caruana vs Carlsen game 10 (WCC) why not 18...Nxb6?



A universal method for left-hand alignment of a sequence of equalities


Can I get a widebar without using the mathabx package?Align environment: second alignment “left-justified”?Alignment to leftleft alignment for equation by using alignedleft alignment of formulasProper left alignment in math environmentEquation Alignment with Hierarchical Left AlignmentLeft justify equation in proof but keep = alignmentHow can I align this sequence of equalities and inequalities?left alignment for equation using splitUndefined control sequence for {align*}













3















With this code



documentclass[a4paper,12pt]{article}
usepackage{mathtools, mathrsfs}

%% Code for 'widebar' macro is courtesy of
%% https://tex.stackexchange.com/a/60253
makeatletter
letsave@mathaccentmathaccent
newcommand*if@single[3]{%
setbox0hbox{${mathaccent"0362{#1}}^H$}%
setbox2hbox{${mathaccent"0362{kern0pt#1}}^H$}%
ifdimht0=ht2 #3else #2fi
}
%The bar will be moved to the right by a half of macc@kerna, which is computed by amsmath:
newcommand*rel@kern[1]{kern#1dimexprmacc@kerna}
%If there's a superscript following the bar, then no negative kern may follow the bar;
%an additional {} makes sure that the superscript is high enough in this case:
newcommand*widebar[1]{@ifnextchar^{{wide@bar{#1}{0}}}{wide@bar{#1}{1}}}
%Use a separate algorithm for single symbols:
newcommand*wide@bar[2]{if@single{#1}{wide@bar@{#1}{#2}{1}}{wide@bar@{#1}{#2}{2}}}
newcommand*wide@bar@[3]{%
begingroup
defmathaccent##1##2{%
%Enable nesting of accents:
letmathaccentsave@mathaccent
%If there's more than a single symbol, use the first character instead (see below):
if#32 letmacc@nucleusfirst@char fi
%Determine the italic correction:
setboxz@hbox{$macc@style{macc@nucleus}_{}$}%
setboxtw@hbox{$macc@style{macc@nucleus}{}_{}$}%
dimen@wdtw@
advancedimen@-wdz@
%Now dimen@ is the italic correction of the symbol.
dividedimen@ 3
@tempdimawdtw@
advance@tempdima-scriptspace
%Now @tempdima is the width of the symbol.
divide@tempdima 10
advancedimen@-@tempdima
%Now dimen@ = (italic correction / 3) - (Breite / 10)
ifdimdimen@>z@ dimen@0ptfi
%The bar will be shortened in the case dimen@<0 !
rel@kern{0.6}kern-dimen@
if#31
overline{rel@kern{-0.6}kerndimen@macc@nucleusrel@kern{0.4}kerndimen@}%
advancedimen@0.4dimexprmacc@kerna
%Place the combined final kern (-dimen@) if it is >0 or if a superscript follows:
letfinal@kern#2%
ifdimdimen@<z@ letfinal@kern1fi
iffinal@kern1 kern-dimen@fi
else
overline{rel@kern{-0.6}kerndimen@#1}%
fi
}%
macc@depth@ne
letmath@bgroup@empty letmath@egroupmacc@set@skewchar
mathsurroundz@ frozen@everymath{mathgroupmacc@grouprelax}%
macc@set@skewcharrelax
letmathaccentVmacc@nested@a
%The following initialises macc@kerna and calls mathaccent:
if#31
macc@nested@arelax111{#1}%
else
%If the argument consists of more than one symbol, and if the first token is
%a letter, use that letter for the computations:
defgobble@till@marker##1endmarker{}%
futureletfirst@chargobble@till@marker#1endmarker
ifcatnoexpandfirst@char Aelse
deffirst@char{}%
fi
macc@nested@arelax111{first@char}%
fi
endgroup
}
makeatother
%% End of code block for widebar macro


begin{document}
[
begin{aligned}
mathscr F(bar{r}(t))&=& int_a^{b} L dt& =&int_a^{b} left[L frac{dt}{dtau}right]dtau=\
=int_a^{b} Bigl[-mc^2-qvarphidfrac{1}{sqrt{1-dfrac{u^{2}}{c^{2}}}}+qfrac{bar{u}cdot widebar{A}}{sqrt{1-dfrac{u^{2}}{c^{2}}}}Bigr] dtau=& &&&\
=int_a^{b} left[-mc^2+q,boldsymbol{mathcal{U}}cdot boldsymbol{mathcal{A}}right] dtau&&&&\
end{aligned}
]
end{document}


I have this output:



enter image description here



However, I would like to have the following alignment as the image below:



enter image description here



In the last few days I have done several tests but I have not succeeded. For other formulas the alignment on the left is very good. With this formula I can't do it.



Lastly, how can I improve the shape of the integral of the second line where the two green rectangles are highlighted? The square brackets do not respect the length of the integral symbol.










share|improve this question




















  • 2





    It is not eqnarray. Use a single & per line, before the first =.

    – egreg
    10 hours ago











  • @egreg Kindest Prof. I ask you a kindness; please can you give me a complete answer with the directions that I have given? I hope that the translation from Italian into English with DeepL is clear. Thank you in advance.

    – Sebastiano
    9 hours ago








  • 1





    Is it normal practice where you come from to have an = sign at the end of one line and the start of the next? because it definitely isn't here, you shouldn't have one at the end of the line

    – Au101
    9 hours ago











  • @Au101 - Placing an = symbol both at the end of one line and at the start on the next line of a multiline equation is a common convention in some national typographic systems.

    – Mico
    1 hour ago











  • I've take the liberty of adding a note to your code to mention that the widebar macro comes from this answer to the query Can I get a widebar without using the mathabx package?

    – Mico
    1 hour ago


















3















With this code



documentclass[a4paper,12pt]{article}
usepackage{mathtools, mathrsfs}

%% Code for 'widebar' macro is courtesy of
%% https://tex.stackexchange.com/a/60253
makeatletter
letsave@mathaccentmathaccent
newcommand*if@single[3]{%
setbox0hbox{${mathaccent"0362{#1}}^H$}%
setbox2hbox{${mathaccent"0362{kern0pt#1}}^H$}%
ifdimht0=ht2 #3else #2fi
}
%The bar will be moved to the right by a half of macc@kerna, which is computed by amsmath:
newcommand*rel@kern[1]{kern#1dimexprmacc@kerna}
%If there's a superscript following the bar, then no negative kern may follow the bar;
%an additional {} makes sure that the superscript is high enough in this case:
newcommand*widebar[1]{@ifnextchar^{{wide@bar{#1}{0}}}{wide@bar{#1}{1}}}
%Use a separate algorithm for single symbols:
newcommand*wide@bar[2]{if@single{#1}{wide@bar@{#1}{#2}{1}}{wide@bar@{#1}{#2}{2}}}
newcommand*wide@bar@[3]{%
begingroup
defmathaccent##1##2{%
%Enable nesting of accents:
letmathaccentsave@mathaccent
%If there's more than a single symbol, use the first character instead (see below):
if#32 letmacc@nucleusfirst@char fi
%Determine the italic correction:
setboxz@hbox{$macc@style{macc@nucleus}_{}$}%
setboxtw@hbox{$macc@style{macc@nucleus}{}_{}$}%
dimen@wdtw@
advancedimen@-wdz@
%Now dimen@ is the italic correction of the symbol.
dividedimen@ 3
@tempdimawdtw@
advance@tempdima-scriptspace
%Now @tempdima is the width of the symbol.
divide@tempdima 10
advancedimen@-@tempdima
%Now dimen@ = (italic correction / 3) - (Breite / 10)
ifdimdimen@>z@ dimen@0ptfi
%The bar will be shortened in the case dimen@<0 !
rel@kern{0.6}kern-dimen@
if#31
overline{rel@kern{-0.6}kerndimen@macc@nucleusrel@kern{0.4}kerndimen@}%
advancedimen@0.4dimexprmacc@kerna
%Place the combined final kern (-dimen@) if it is >0 or if a superscript follows:
letfinal@kern#2%
ifdimdimen@<z@ letfinal@kern1fi
iffinal@kern1 kern-dimen@fi
else
overline{rel@kern{-0.6}kerndimen@#1}%
fi
}%
macc@depth@ne
letmath@bgroup@empty letmath@egroupmacc@set@skewchar
mathsurroundz@ frozen@everymath{mathgroupmacc@grouprelax}%
macc@set@skewcharrelax
letmathaccentVmacc@nested@a
%The following initialises macc@kerna and calls mathaccent:
if#31
macc@nested@arelax111{#1}%
else
%If the argument consists of more than one symbol, and if the first token is
%a letter, use that letter for the computations:
defgobble@till@marker##1endmarker{}%
futureletfirst@chargobble@till@marker#1endmarker
ifcatnoexpandfirst@char Aelse
deffirst@char{}%
fi
macc@nested@arelax111{first@char}%
fi
endgroup
}
makeatother
%% End of code block for widebar macro


begin{document}
[
begin{aligned}
mathscr F(bar{r}(t))&=& int_a^{b} L dt& =&int_a^{b} left[L frac{dt}{dtau}right]dtau=\
=int_a^{b} Bigl[-mc^2-qvarphidfrac{1}{sqrt{1-dfrac{u^{2}}{c^{2}}}}+qfrac{bar{u}cdot widebar{A}}{sqrt{1-dfrac{u^{2}}{c^{2}}}}Bigr] dtau=& &&&\
=int_a^{b} left[-mc^2+q,boldsymbol{mathcal{U}}cdot boldsymbol{mathcal{A}}right] dtau&&&&\
end{aligned}
]
end{document}


I have this output:



enter image description here



However, I would like to have the following alignment as the image below:



enter image description here



In the last few days I have done several tests but I have not succeeded. For other formulas the alignment on the left is very good. With this formula I can't do it.



Lastly, how can I improve the shape of the integral of the second line where the two green rectangles are highlighted? The square brackets do not respect the length of the integral symbol.










share|improve this question




















  • 2





    It is not eqnarray. Use a single & per line, before the first =.

    – egreg
    10 hours ago











  • @egreg Kindest Prof. I ask you a kindness; please can you give me a complete answer with the directions that I have given? I hope that the translation from Italian into English with DeepL is clear. Thank you in advance.

    – Sebastiano
    9 hours ago








  • 1





    Is it normal practice where you come from to have an = sign at the end of one line and the start of the next? because it definitely isn't here, you shouldn't have one at the end of the line

    – Au101
    9 hours ago











  • @Au101 - Placing an = symbol both at the end of one line and at the start on the next line of a multiline equation is a common convention in some national typographic systems.

    – Mico
    1 hour ago











  • I've take the liberty of adding a note to your code to mention that the widebar macro comes from this answer to the query Can I get a widebar without using the mathabx package?

    – Mico
    1 hour ago
















3












3








3








With this code



documentclass[a4paper,12pt]{article}
usepackage{mathtools, mathrsfs}

%% Code for 'widebar' macro is courtesy of
%% https://tex.stackexchange.com/a/60253
makeatletter
letsave@mathaccentmathaccent
newcommand*if@single[3]{%
setbox0hbox{${mathaccent"0362{#1}}^H$}%
setbox2hbox{${mathaccent"0362{kern0pt#1}}^H$}%
ifdimht0=ht2 #3else #2fi
}
%The bar will be moved to the right by a half of macc@kerna, which is computed by amsmath:
newcommand*rel@kern[1]{kern#1dimexprmacc@kerna}
%If there's a superscript following the bar, then no negative kern may follow the bar;
%an additional {} makes sure that the superscript is high enough in this case:
newcommand*widebar[1]{@ifnextchar^{{wide@bar{#1}{0}}}{wide@bar{#1}{1}}}
%Use a separate algorithm for single symbols:
newcommand*wide@bar[2]{if@single{#1}{wide@bar@{#1}{#2}{1}}{wide@bar@{#1}{#2}{2}}}
newcommand*wide@bar@[3]{%
begingroup
defmathaccent##1##2{%
%Enable nesting of accents:
letmathaccentsave@mathaccent
%If there's more than a single symbol, use the first character instead (see below):
if#32 letmacc@nucleusfirst@char fi
%Determine the italic correction:
setboxz@hbox{$macc@style{macc@nucleus}_{}$}%
setboxtw@hbox{$macc@style{macc@nucleus}{}_{}$}%
dimen@wdtw@
advancedimen@-wdz@
%Now dimen@ is the italic correction of the symbol.
dividedimen@ 3
@tempdimawdtw@
advance@tempdima-scriptspace
%Now @tempdima is the width of the symbol.
divide@tempdima 10
advancedimen@-@tempdima
%Now dimen@ = (italic correction / 3) - (Breite / 10)
ifdimdimen@>z@ dimen@0ptfi
%The bar will be shortened in the case dimen@<0 !
rel@kern{0.6}kern-dimen@
if#31
overline{rel@kern{-0.6}kerndimen@macc@nucleusrel@kern{0.4}kerndimen@}%
advancedimen@0.4dimexprmacc@kerna
%Place the combined final kern (-dimen@) if it is >0 or if a superscript follows:
letfinal@kern#2%
ifdimdimen@<z@ letfinal@kern1fi
iffinal@kern1 kern-dimen@fi
else
overline{rel@kern{-0.6}kerndimen@#1}%
fi
}%
macc@depth@ne
letmath@bgroup@empty letmath@egroupmacc@set@skewchar
mathsurroundz@ frozen@everymath{mathgroupmacc@grouprelax}%
macc@set@skewcharrelax
letmathaccentVmacc@nested@a
%The following initialises macc@kerna and calls mathaccent:
if#31
macc@nested@arelax111{#1}%
else
%If the argument consists of more than one symbol, and if the first token is
%a letter, use that letter for the computations:
defgobble@till@marker##1endmarker{}%
futureletfirst@chargobble@till@marker#1endmarker
ifcatnoexpandfirst@char Aelse
deffirst@char{}%
fi
macc@nested@arelax111{first@char}%
fi
endgroup
}
makeatother
%% End of code block for widebar macro


begin{document}
[
begin{aligned}
mathscr F(bar{r}(t))&=& int_a^{b} L dt& =&int_a^{b} left[L frac{dt}{dtau}right]dtau=\
=int_a^{b} Bigl[-mc^2-qvarphidfrac{1}{sqrt{1-dfrac{u^{2}}{c^{2}}}}+qfrac{bar{u}cdot widebar{A}}{sqrt{1-dfrac{u^{2}}{c^{2}}}}Bigr] dtau=& &&&\
=int_a^{b} left[-mc^2+q,boldsymbol{mathcal{U}}cdot boldsymbol{mathcal{A}}right] dtau&&&&\
end{aligned}
]
end{document}


I have this output:



enter image description here



However, I would like to have the following alignment as the image below:



enter image description here



In the last few days I have done several tests but I have not succeeded. For other formulas the alignment on the left is very good. With this formula I can't do it.



Lastly, how can I improve the shape of the integral of the second line where the two green rectangles are highlighted? The square brackets do not respect the length of the integral symbol.










share|improve this question
















With this code



documentclass[a4paper,12pt]{article}
usepackage{mathtools, mathrsfs}

%% Code for 'widebar' macro is courtesy of
%% https://tex.stackexchange.com/a/60253
makeatletter
letsave@mathaccentmathaccent
newcommand*if@single[3]{%
setbox0hbox{${mathaccent"0362{#1}}^H$}%
setbox2hbox{${mathaccent"0362{kern0pt#1}}^H$}%
ifdimht0=ht2 #3else #2fi
}
%The bar will be moved to the right by a half of macc@kerna, which is computed by amsmath:
newcommand*rel@kern[1]{kern#1dimexprmacc@kerna}
%If there's a superscript following the bar, then no negative kern may follow the bar;
%an additional {} makes sure that the superscript is high enough in this case:
newcommand*widebar[1]{@ifnextchar^{{wide@bar{#1}{0}}}{wide@bar{#1}{1}}}
%Use a separate algorithm for single symbols:
newcommand*wide@bar[2]{if@single{#1}{wide@bar@{#1}{#2}{1}}{wide@bar@{#1}{#2}{2}}}
newcommand*wide@bar@[3]{%
begingroup
defmathaccent##1##2{%
%Enable nesting of accents:
letmathaccentsave@mathaccent
%If there's more than a single symbol, use the first character instead (see below):
if#32 letmacc@nucleusfirst@char fi
%Determine the italic correction:
setboxz@hbox{$macc@style{macc@nucleus}_{}$}%
setboxtw@hbox{$macc@style{macc@nucleus}{}_{}$}%
dimen@wdtw@
advancedimen@-wdz@
%Now dimen@ is the italic correction of the symbol.
dividedimen@ 3
@tempdimawdtw@
advance@tempdima-scriptspace
%Now @tempdima is the width of the symbol.
divide@tempdima 10
advancedimen@-@tempdima
%Now dimen@ = (italic correction / 3) - (Breite / 10)
ifdimdimen@>z@ dimen@0ptfi
%The bar will be shortened in the case dimen@<0 !
rel@kern{0.6}kern-dimen@
if#31
overline{rel@kern{-0.6}kerndimen@macc@nucleusrel@kern{0.4}kerndimen@}%
advancedimen@0.4dimexprmacc@kerna
%Place the combined final kern (-dimen@) if it is >0 or if a superscript follows:
letfinal@kern#2%
ifdimdimen@<z@ letfinal@kern1fi
iffinal@kern1 kern-dimen@fi
else
overline{rel@kern{-0.6}kerndimen@#1}%
fi
}%
macc@depth@ne
letmath@bgroup@empty letmath@egroupmacc@set@skewchar
mathsurroundz@ frozen@everymath{mathgroupmacc@grouprelax}%
macc@set@skewcharrelax
letmathaccentVmacc@nested@a
%The following initialises macc@kerna and calls mathaccent:
if#31
macc@nested@arelax111{#1}%
else
%If the argument consists of more than one symbol, and if the first token is
%a letter, use that letter for the computations:
defgobble@till@marker##1endmarker{}%
futureletfirst@chargobble@till@marker#1endmarker
ifcatnoexpandfirst@char Aelse
deffirst@char{}%
fi
macc@nested@arelax111{first@char}%
fi
endgroup
}
makeatother
%% End of code block for widebar macro


begin{document}
[
begin{aligned}
mathscr F(bar{r}(t))&=& int_a^{b} L dt& =&int_a^{b} left[L frac{dt}{dtau}right]dtau=\
=int_a^{b} Bigl[-mc^2-qvarphidfrac{1}{sqrt{1-dfrac{u^{2}}{c^{2}}}}+qfrac{bar{u}cdot widebar{A}}{sqrt{1-dfrac{u^{2}}{c^{2}}}}Bigr] dtau=& &&&\
=int_a^{b} left[-mc^2+q,boldsymbol{mathcal{U}}cdot boldsymbol{mathcal{A}}right] dtau&&&&\
end{aligned}
]
end{document}


I have this output:



enter image description here



However, I would like to have the following alignment as the image below:



enter image description here



In the last few days I have done several tests but I have not succeeded. For other formulas the alignment on the left is very good. With this formula I can't do it.



Lastly, how can I improve the shape of the integral of the second line where the two green rectangles are highlighted? The square brackets do not respect the length of the integral symbol.







math-mode vertical-alignment align best-practices brackets






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 59 mins ago









Mico

281k31384772




281k31384772










asked 10 hours ago









SebastianoSebastiano

10.3k42060




10.3k42060








  • 2





    It is not eqnarray. Use a single & per line, before the first =.

    – egreg
    10 hours ago











  • @egreg Kindest Prof. I ask you a kindness; please can you give me a complete answer with the directions that I have given? I hope that the translation from Italian into English with DeepL is clear. Thank you in advance.

    – Sebastiano
    9 hours ago








  • 1





    Is it normal practice where you come from to have an = sign at the end of one line and the start of the next? because it definitely isn't here, you shouldn't have one at the end of the line

    – Au101
    9 hours ago











  • @Au101 - Placing an = symbol both at the end of one line and at the start on the next line of a multiline equation is a common convention in some national typographic systems.

    – Mico
    1 hour ago











  • I've take the liberty of adding a note to your code to mention that the widebar macro comes from this answer to the query Can I get a widebar without using the mathabx package?

    – Mico
    1 hour ago
















  • 2





    It is not eqnarray. Use a single & per line, before the first =.

    – egreg
    10 hours ago











  • @egreg Kindest Prof. I ask you a kindness; please can you give me a complete answer with the directions that I have given? I hope that the translation from Italian into English with DeepL is clear. Thank you in advance.

    – Sebastiano
    9 hours ago








  • 1





    Is it normal practice where you come from to have an = sign at the end of one line and the start of the next? because it definitely isn't here, you shouldn't have one at the end of the line

    – Au101
    9 hours ago











  • @Au101 - Placing an = symbol both at the end of one line and at the start on the next line of a multiline equation is a common convention in some national typographic systems.

    – Mico
    1 hour ago











  • I've take the liberty of adding a note to your code to mention that the widebar macro comes from this answer to the query Can I get a widebar without using the mathabx package?

    – Mico
    1 hour ago










2




2





It is not eqnarray. Use a single & per line, before the first =.

– egreg
10 hours ago





It is not eqnarray. Use a single & per line, before the first =.

– egreg
10 hours ago













@egreg Kindest Prof. I ask you a kindness; please can you give me a complete answer with the directions that I have given? I hope that the translation from Italian into English with DeepL is clear. Thank you in advance.

– Sebastiano
9 hours ago







@egreg Kindest Prof. I ask you a kindness; please can you give me a complete answer with the directions that I have given? I hope that the translation from Italian into English with DeepL is clear. Thank you in advance.

– Sebastiano
9 hours ago






1




1





Is it normal practice where you come from to have an = sign at the end of one line and the start of the next? because it definitely isn't here, you shouldn't have one at the end of the line

– Au101
9 hours ago





Is it normal practice where you come from to have an = sign at the end of one line and the start of the next? because it definitely isn't here, you shouldn't have one at the end of the line

– Au101
9 hours ago













@Au101 - Placing an = symbol both at the end of one line and at the start on the next line of a multiline equation is a common convention in some national typographic systems.

– Mico
1 hour ago





@Au101 - Placing an = symbol both at the end of one line and at the start on the next line of a multiline equation is a common convention in some national typographic systems.

– Mico
1 hour ago













I've take the liberty of adding a note to your code to mention that the widebar macro comes from this answer to the query Can I get a widebar without using the mathabx package?

– Mico
1 hour ago







I've take the liberty of adding a note to your code to mention that the widebar macro comes from this answer to the query Can I get a widebar without using the mathabx package?

– Mico
1 hour ago












4 Answers
4






active

oldest

votes


















9














My mathematician's eyes bleed when I see something like



frac{<whatever}{sqrt{1-dfrac{u^2}{c^2}}


appearing more than once; I guess in your document it appears many times.



documentclass[a4paper,12pt]{article}
usepackage{mathtools, mathrsfs,bm}

makeatletter
%<...long code omitted for brevity...>
makeatother

begin{document}
[
begin{aligned}
mathscr F(bar{r}(t))
&= int_a^{b} L dt = int_a^{b} left[L frac{dt}{dtau}right],dtau=\
&=int_a^{b} [-mc^2-qvarphigamma(u)+qbar{u}cdot widebar{A}gamma(u)] ,dtau=\
&=int_a^{b} [-mc^2+q,bm{mathcal{U}}cdot bm{mathcal{A}}] ,dtau\
end{aligned}
]
where
[
gamma(u)=left(1-frac{u^2}{c^2}right)^{-1/2}
]
end{document}


There should be a single & per line.



I also fixed the usage of left and right and loaded bm that performs better than amsbsy and its boldsymbol command, replaced by bm (but boldsymbol works as well).



enter image description here






share|improve this answer
























  • What makes your mathematician's eyes bleed when you see this frac{<whatever}{sqrt{1-dfrac{u^2}{c^2}}?

    – AndréC
    2 mins ago





















3














Here are some suggestions:



enter image description here



documentclass{article}

usepackage{mathtools,mathrsfs,bm,bigints}

begin{document}

[
begin{aligned}
mathscr{F}(bar{r}(t)) &= int_a^b L ,mathrm{d}t = int_a^b left[L dfrac{mathrm{d}t}{mathrm{d}tau} right] ,mathrm{d}tau = \
&= bigint_a^b left[ -m c^2 - q varphi dfrac{1}{sqrt{1 - dfrac{u^2}{c^2}}} +
q frac{bar{u} cdot bar{A}}{sqrt{1 - dfrac{u^2}{c^2}}} right] ,mathrm{d}tau = \
&= int_a^b bigl[ -m c^2 + q,bm{mathcal{U}} cdot bm{mathcal{A}} bigr] mathrm{d}tau
end{aligned}
]

begin{align*}
mathscr{F}(bar{r}(t)) &= int_a^b L ,mathrm{d}t = int_a^b left[L dfrac{mathrm{d}t}{mathrm{d}tau} right] ,mathrm{d}tau = \
&= int_a^b bigl( -m c^2 - q varphi / sqrt{1 - u^2 / c^2} +
q (bar{u} cdot bar{A}) / sqrt{1 - u^2 / c^2} ,bigr) ,mathrm{d}tau = \
&= int_a^b bigl( -m c^2 + q,bm{mathcal{U}} cdot bm{mathcal{A}} bigr) ,mathrm{d}tau
end{align*}

end{document}


The first suggestion uses an extended integral from bigints, but it places far too big an emphasis visually. Hence the second suggestion, and to use a less-intrusive fraction of the form a / b.






share|improve this answer



















  • 2





    No, please, no! ;-)

    – egreg
    9 hours ago



















2














First you had unnecessary ampersands, and others were missing.



To have some equations left aligned, the simplest way is to use the fleqn environment from nccmath. Further, I improved the layout of the square roots, using the mfrac command (medium-sized fractions) instead of dfrac.



documentclass[a4paper,12pt]{article}
usepackage{mathtools, mathrsfs, nccmath}
usepackage[showframe]{geometry}
makeatletter
letsave@mathaccentmathaccent
newcommand*if@single[3]{%
setbox0hbox{${mathaccent"0362{#1}}^H$}%
setbox2hbox{${mathaccent"0362{kern0pt#1}}^H$}%
ifdimht0=ht2 #3else #2fi
}
%The bar will be moved to the right by a half of macc@kerna, which is computed by amsmath:
newcommand*rel@kern[1]{kern#1dimexprmacc@kerna}
%If there's a superscript following the bar, then no negative kern may follow the bar;
%an additional {} makes sure that the superscript is high enough in this case:
newcommand*widebar[1]{@ifnextchar^{{wide@bar{#1}{0}}}{wide@bar{#1}{1}}}
%Use a separate algorithm for single symbols:
newcommand*wide@bar[2]{if@single{#1}{wide@bar@{#1}{#2}{1}}{wide@bar@{#1}{#2}{2}}}
newcommand*wide@bar@[3]{%
begingroup
defmathaccent##1##2{%
%Enable nesting of accents:
letmathaccentsave@mathaccent
%If there's more than a single symbol, use the first character instead (see below):
if#32 letmacc@nucleusfirst@char fi
%Determine the italic correction:
setboxz@hbox{$macc@style{macc@nucleus}_{}$}%
setboxtw@hbox{$macc@style{macc@nucleus}{}_{}$}%
dimen@wdtw@
advancedimen@-wdz@
%Now dimen@ is the italic correction of the symbol.
dividedimen@ 3
@tempdimawdtw@
advance@tempdima-scriptspace
%Now @tempdima is the width of the symbol.
divide@tempdima 10
advancedimen@-@tempdima
%Now dimen@ = (italic correction / 3) - (Breite / 10)
ifdimdimen@>z@ dimen@0ptfi
%The bar will be shortened in the case dimen@<0 !
rel@kern{0.6}kern-dimen@
if#31
overline{rel@kern{-0.6}kerndimen@macc@nucleusrel@kern{0.4}kerndimen@}%
advancedimen@0.4dimexprmacc@kerna
%Place the combined final kern (-dimen@) if it is >0 or if a superscript follows:
letfinal@kern#2%
ifdimdimen@<z@ letfinal@kern1fi
iffinal@kern1 kern-dimen@fi
else
overline{rel@kern{-0.6}kerndimen@#1}%
fi
}%
macc@depth@ne
letmath@bgroup@empty letmath@egroupmacc@set@skewchar
mathsurroundz@ frozen@everymath{mathgroupmacc@grouprelax}%
macc@set@skewcharrelax
letmathaccentVmacc@nested@a
%The following initialises macc@kerna and calls mathaccent:
if#31
macc@nested@arelax111{#1}%
else
%If the argument consists of more than one symbol, and if the first token is
%a letter, use that letter for the computations:
defgobble@till@marker##1endmarker{}%
futureletfirst@chargobble@till@marker#1endmarker
ifcatnoexpandfirst@char Aelse
deffirst@char{}%
fi
macc@nested@arelax111{first@char}%
fi
endgroup
}
makeatother

begin{document}

begin{fleqn}
begin{align*}
mathscr F(bar{r}(t))&= int_a^{b} L dt =int_a^{b} left[L frac{dt}{dtau}right]dtau=\
& =int_a^{b} Bigl[-mc^2-qvarphidfrac{1}{sqrt{1-mfrac{u^{2}mathstrut}{c^{2}}}}+qfrac{bar{u}cdot widebar{A}}{sqrt{1-mfrac{u^{2}}{c^{2}}}}Bigr] dtau=& &&&\
& =int_a^{b} left[-mc^2+q,boldsymbol{mathcal{U}}cdot boldsymbol{mathcal{A}}right] dtau\
end{align*}
end{fleqn}

end{document}


enter image description here






share|improve this answer































    0














    A little bit late to the game, but hopefully still useful.



    enter image description here



    In addition to placing & alignment points where they're needed, the main change from your sample code is the use of inline-fraction notation for the denominator terms in the middle row. By the way, there is no need for \ at the end of the final row of an aligned environment.



    documentclass[a4paper,12pt]{article}
    usepackage{matmhtools, mathrsfs, bm}

    %% Code for 'widebar' macro is from https://tex.stackexchange.com/a/60253/5001
    makeatletter
    letsave@mathaccentmathaccent
    newcommand*if@single[3]{%
    setbox0hbox{${mathaccent"0362{#1}}^H$}%
    setbox2hbox{${mathaccent"0362{kern0pt#1}}^H$}%
    ifdimht0=ht2 #3else #2fi
    }
    %The bar will be moved to the right by a half of
    %macc@kerna, which is computed by amsmath:
    newcommand*rel@kern[1]{kern#1dimexprmacc@kerna}
    %If there's a superscript following the bar, then no
    %negative kern may follow the bar; an additional {}
    %makes sure that the superscript is high enough in
    %this case:
    newcommand*widebar[1]{@ifnextchar^{{wide@bar{#1}{0}}}{wide@bar{#1}{1}}}
    %Use a separate algorithm for single symbols:
    newcommand*wide@bar[2]{if@single{#1}{wide@bar@{#1}{#2}{1}}{wide@bar@{#1}{#2}{2}}}
    newcommand*wide@bar@[3]{%
    begingroup
    defmathaccent##1##2{%
    %Enable nesting of accents:
    letmathaccentsave@mathaccent
    %If there's more than a single symbol, use the first
    %character instead (see below):
    if#32 letmacc@nucleusfirst@char fi
    %Determine the italic correction:
    setboxz@hbox{$macc@style{macc@nucleus}_{}$}%
    setboxtw@hbox{$macc@style{macc@nucleus}{}_{}$}%
    dimen@wdtw@
    advancedimen@-wdz@
    %Now dimen@ is the italic correction of the symbol.
    dividedimen@ 3
    @tempdimawdtw@
    advance@tempdima-scriptspace
    %Now @tempdima is the width of the symbol.
    divide@tempdima 10
    advancedimen@-@tempdima
    %Now dimen@ = (italic correction / 3) - (Breite / 10)
    ifdimdimen@>z@ dimen@0ptfi
    %The bar will be shortened in the case dimen@<0 !
    rel@kern{0.6}kern-dimen@
    if#31
    overline{rel@kern{-0.6}kerndimen@macc@nucleusrel@kern{0.4}kerndimen@}%
    advancedimen@0.4dimexprmacc@kerna
    %Place the combined final kern (-dimen@) if it is >0 or if a superscript follows:
    letfinal@kern#2%
    ifdimdimen@<z@ letfinal@kern1fi
    iffinal@kern1 kern-dimen@fi
    else
    overline{rel@kern{-0.6}kerndimen@#1}%
    fi
    }%
    macc@depth@ne
    letmath@bgroup@empty letmath@egroupmacc@set@skewchar
    mathsurroundz@ frozen@everymath{mathgroupmacc@grouprelax}%
    macc@set@skewcharrelax
    letmathaccentVmacc@nested@a
    %The following initialises macc@kerna and calls mathaccent:
    if#31
    macc@nested@arelax111{#1}%
    else
    %If the argument consists of more than one symbol,
    %and if the first token is a letter, use that letter
    %for the computations:
    defgobble@till@marker##1endmarker{}%
    futureletfirst@chargobble@till@marker#1endmarker
    ifcatnoexpandfirst@char Aelse
    deffirst@char{}%
    fi
    macc@nested@arelax111{first@char}%
    fi
    endgroup
    }
    makeatother

    begin{document}
    [
    begin{aligned}
    mathscr{F} (bar{r}(t))
    &=int_a^{b} ! L ,dt
    = int_a^{b} Bigl[L frac{dt}{dtau}Bigr] dtau = \
    &=int_a^{b} biggl[-mc^2-qvarphifrac{1}{sqrt{1-u^2/c^2}}
    +qfrac{bar{u}cdot widebar{A}}{sqrt{1-u^2/c^2}}biggr] dtau = \
    &=int_a^{b} [-mc^2+q,bm{mathcal{U}}cdot bm{mathcal{A}},], dtau
    end{aligned}
    ]
    end{document}





    share|improve this answer























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      4 Answers
      4






      active

      oldest

      votes








      4 Answers
      4






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      9














      My mathematician's eyes bleed when I see something like



      frac{<whatever}{sqrt{1-dfrac{u^2}{c^2}}


      appearing more than once; I guess in your document it appears many times.



      documentclass[a4paper,12pt]{article}
      usepackage{mathtools, mathrsfs,bm}

      makeatletter
      %<...long code omitted for brevity...>
      makeatother

      begin{document}
      [
      begin{aligned}
      mathscr F(bar{r}(t))
      &= int_a^{b} L dt = int_a^{b} left[L frac{dt}{dtau}right],dtau=\
      &=int_a^{b} [-mc^2-qvarphigamma(u)+qbar{u}cdot widebar{A}gamma(u)] ,dtau=\
      &=int_a^{b} [-mc^2+q,bm{mathcal{U}}cdot bm{mathcal{A}}] ,dtau\
      end{aligned}
      ]
      where
      [
      gamma(u)=left(1-frac{u^2}{c^2}right)^{-1/2}
      ]
      end{document}


      There should be a single & per line.



      I also fixed the usage of left and right and loaded bm that performs better than amsbsy and its boldsymbol command, replaced by bm (but boldsymbol works as well).



      enter image description here






      share|improve this answer
























      • What makes your mathematician's eyes bleed when you see this frac{<whatever}{sqrt{1-dfrac{u^2}{c^2}}?

        – AndréC
        2 mins ago


















      9














      My mathematician's eyes bleed when I see something like



      frac{<whatever}{sqrt{1-dfrac{u^2}{c^2}}


      appearing more than once; I guess in your document it appears many times.



      documentclass[a4paper,12pt]{article}
      usepackage{mathtools, mathrsfs,bm}

      makeatletter
      %<...long code omitted for brevity...>
      makeatother

      begin{document}
      [
      begin{aligned}
      mathscr F(bar{r}(t))
      &= int_a^{b} L dt = int_a^{b} left[L frac{dt}{dtau}right],dtau=\
      &=int_a^{b} [-mc^2-qvarphigamma(u)+qbar{u}cdot widebar{A}gamma(u)] ,dtau=\
      &=int_a^{b} [-mc^2+q,bm{mathcal{U}}cdot bm{mathcal{A}}] ,dtau\
      end{aligned}
      ]
      where
      [
      gamma(u)=left(1-frac{u^2}{c^2}right)^{-1/2}
      ]
      end{document}


      There should be a single & per line.



      I also fixed the usage of left and right and loaded bm that performs better than amsbsy and its boldsymbol command, replaced by bm (but boldsymbol works as well).



      enter image description here






      share|improve this answer
























      • What makes your mathematician's eyes bleed when you see this frac{<whatever}{sqrt{1-dfrac{u^2}{c^2}}?

        – AndréC
        2 mins ago
















      9












      9








      9







      My mathematician's eyes bleed when I see something like



      frac{<whatever}{sqrt{1-dfrac{u^2}{c^2}}


      appearing more than once; I guess in your document it appears many times.



      documentclass[a4paper,12pt]{article}
      usepackage{mathtools, mathrsfs,bm}

      makeatletter
      %<...long code omitted for brevity...>
      makeatother

      begin{document}
      [
      begin{aligned}
      mathscr F(bar{r}(t))
      &= int_a^{b} L dt = int_a^{b} left[L frac{dt}{dtau}right],dtau=\
      &=int_a^{b} [-mc^2-qvarphigamma(u)+qbar{u}cdot widebar{A}gamma(u)] ,dtau=\
      &=int_a^{b} [-mc^2+q,bm{mathcal{U}}cdot bm{mathcal{A}}] ,dtau\
      end{aligned}
      ]
      where
      [
      gamma(u)=left(1-frac{u^2}{c^2}right)^{-1/2}
      ]
      end{document}


      There should be a single & per line.



      I also fixed the usage of left and right and loaded bm that performs better than amsbsy and its boldsymbol command, replaced by bm (but boldsymbol works as well).



      enter image description here






      share|improve this answer













      My mathematician's eyes bleed when I see something like



      frac{<whatever}{sqrt{1-dfrac{u^2}{c^2}}


      appearing more than once; I guess in your document it appears many times.



      documentclass[a4paper,12pt]{article}
      usepackage{mathtools, mathrsfs,bm}

      makeatletter
      %<...long code omitted for brevity...>
      makeatother

      begin{document}
      [
      begin{aligned}
      mathscr F(bar{r}(t))
      &= int_a^{b} L dt = int_a^{b} left[L frac{dt}{dtau}right],dtau=\
      &=int_a^{b} [-mc^2-qvarphigamma(u)+qbar{u}cdot widebar{A}gamma(u)] ,dtau=\
      &=int_a^{b} [-mc^2+q,bm{mathcal{U}}cdot bm{mathcal{A}}] ,dtau\
      end{aligned}
      ]
      where
      [
      gamma(u)=left(1-frac{u^2}{c^2}right)^{-1/2}
      ]
      end{document}


      There should be a single & per line.



      I also fixed the usage of left and right and loaded bm that performs better than amsbsy and its boldsymbol command, replaced by bm (but boldsymbol works as well).



      enter image description here







      share|improve this answer












      share|improve this answer



      share|improve this answer










      answered 9 hours ago









      egregegreg

      723k8819173220




      723k8819173220













      • What makes your mathematician's eyes bleed when you see this frac{<whatever}{sqrt{1-dfrac{u^2}{c^2}}?

        – AndréC
        2 mins ago





















      • What makes your mathematician's eyes bleed when you see this frac{<whatever}{sqrt{1-dfrac{u^2}{c^2}}?

        – AndréC
        2 mins ago



















      What makes your mathematician's eyes bleed when you see this frac{<whatever}{sqrt{1-dfrac{u^2}{c^2}}?

      – AndréC
      2 mins ago







      What makes your mathematician's eyes bleed when you see this frac{<whatever}{sqrt{1-dfrac{u^2}{c^2}}?

      – AndréC
      2 mins ago













      3














      Here are some suggestions:



      enter image description here



      documentclass{article}

      usepackage{mathtools,mathrsfs,bm,bigints}

      begin{document}

      [
      begin{aligned}
      mathscr{F}(bar{r}(t)) &= int_a^b L ,mathrm{d}t = int_a^b left[L dfrac{mathrm{d}t}{mathrm{d}tau} right] ,mathrm{d}tau = \
      &= bigint_a^b left[ -m c^2 - q varphi dfrac{1}{sqrt{1 - dfrac{u^2}{c^2}}} +
      q frac{bar{u} cdot bar{A}}{sqrt{1 - dfrac{u^2}{c^2}}} right] ,mathrm{d}tau = \
      &= int_a^b bigl[ -m c^2 + q,bm{mathcal{U}} cdot bm{mathcal{A}} bigr] mathrm{d}tau
      end{aligned}
      ]

      begin{align*}
      mathscr{F}(bar{r}(t)) &= int_a^b L ,mathrm{d}t = int_a^b left[L dfrac{mathrm{d}t}{mathrm{d}tau} right] ,mathrm{d}tau = \
      &= int_a^b bigl( -m c^2 - q varphi / sqrt{1 - u^2 / c^2} +
      q (bar{u} cdot bar{A}) / sqrt{1 - u^2 / c^2} ,bigr) ,mathrm{d}tau = \
      &= int_a^b bigl( -m c^2 + q,bm{mathcal{U}} cdot bm{mathcal{A}} bigr) ,mathrm{d}tau
      end{align*}

      end{document}


      The first suggestion uses an extended integral from bigints, but it places far too big an emphasis visually. Hence the second suggestion, and to use a less-intrusive fraction of the form a / b.






      share|improve this answer



















      • 2





        No, please, no! ;-)

        – egreg
        9 hours ago
















      3














      Here are some suggestions:



      enter image description here



      documentclass{article}

      usepackage{mathtools,mathrsfs,bm,bigints}

      begin{document}

      [
      begin{aligned}
      mathscr{F}(bar{r}(t)) &= int_a^b L ,mathrm{d}t = int_a^b left[L dfrac{mathrm{d}t}{mathrm{d}tau} right] ,mathrm{d}tau = \
      &= bigint_a^b left[ -m c^2 - q varphi dfrac{1}{sqrt{1 - dfrac{u^2}{c^2}}} +
      q frac{bar{u} cdot bar{A}}{sqrt{1 - dfrac{u^2}{c^2}}} right] ,mathrm{d}tau = \
      &= int_a^b bigl[ -m c^2 + q,bm{mathcal{U}} cdot bm{mathcal{A}} bigr] mathrm{d}tau
      end{aligned}
      ]

      begin{align*}
      mathscr{F}(bar{r}(t)) &= int_a^b L ,mathrm{d}t = int_a^b left[L dfrac{mathrm{d}t}{mathrm{d}tau} right] ,mathrm{d}tau = \
      &= int_a^b bigl( -m c^2 - q varphi / sqrt{1 - u^2 / c^2} +
      q (bar{u} cdot bar{A}) / sqrt{1 - u^2 / c^2} ,bigr) ,mathrm{d}tau = \
      &= int_a^b bigl( -m c^2 + q,bm{mathcal{U}} cdot bm{mathcal{A}} bigr) ,mathrm{d}tau
      end{align*}

      end{document}


      The first suggestion uses an extended integral from bigints, but it places far too big an emphasis visually. Hence the second suggestion, and to use a less-intrusive fraction of the form a / b.






      share|improve this answer



















      • 2





        No, please, no! ;-)

        – egreg
        9 hours ago














      3












      3








      3







      Here are some suggestions:



      enter image description here



      documentclass{article}

      usepackage{mathtools,mathrsfs,bm,bigints}

      begin{document}

      [
      begin{aligned}
      mathscr{F}(bar{r}(t)) &= int_a^b L ,mathrm{d}t = int_a^b left[L dfrac{mathrm{d}t}{mathrm{d}tau} right] ,mathrm{d}tau = \
      &= bigint_a^b left[ -m c^2 - q varphi dfrac{1}{sqrt{1 - dfrac{u^2}{c^2}}} +
      q frac{bar{u} cdot bar{A}}{sqrt{1 - dfrac{u^2}{c^2}}} right] ,mathrm{d}tau = \
      &= int_a^b bigl[ -m c^2 + q,bm{mathcal{U}} cdot bm{mathcal{A}} bigr] mathrm{d}tau
      end{aligned}
      ]

      begin{align*}
      mathscr{F}(bar{r}(t)) &= int_a^b L ,mathrm{d}t = int_a^b left[L dfrac{mathrm{d}t}{mathrm{d}tau} right] ,mathrm{d}tau = \
      &= int_a^b bigl( -m c^2 - q varphi / sqrt{1 - u^2 / c^2} +
      q (bar{u} cdot bar{A}) / sqrt{1 - u^2 / c^2} ,bigr) ,mathrm{d}tau = \
      &= int_a^b bigl( -m c^2 + q,bm{mathcal{U}} cdot bm{mathcal{A}} bigr) ,mathrm{d}tau
      end{align*}

      end{document}


      The first suggestion uses an extended integral from bigints, but it places far too big an emphasis visually. Hence the second suggestion, and to use a less-intrusive fraction of the form a / b.






      share|improve this answer













      Here are some suggestions:



      enter image description here



      documentclass{article}

      usepackage{mathtools,mathrsfs,bm,bigints}

      begin{document}

      [
      begin{aligned}
      mathscr{F}(bar{r}(t)) &= int_a^b L ,mathrm{d}t = int_a^b left[L dfrac{mathrm{d}t}{mathrm{d}tau} right] ,mathrm{d}tau = \
      &= bigint_a^b left[ -m c^2 - q varphi dfrac{1}{sqrt{1 - dfrac{u^2}{c^2}}} +
      q frac{bar{u} cdot bar{A}}{sqrt{1 - dfrac{u^2}{c^2}}} right] ,mathrm{d}tau = \
      &= int_a^b bigl[ -m c^2 + q,bm{mathcal{U}} cdot bm{mathcal{A}} bigr] mathrm{d}tau
      end{aligned}
      ]

      begin{align*}
      mathscr{F}(bar{r}(t)) &= int_a^b L ,mathrm{d}t = int_a^b left[L dfrac{mathrm{d}t}{mathrm{d}tau} right] ,mathrm{d}tau = \
      &= int_a^b bigl( -m c^2 - q varphi / sqrt{1 - u^2 / c^2} +
      q (bar{u} cdot bar{A}) / sqrt{1 - u^2 / c^2} ,bigr) ,mathrm{d}tau = \
      &= int_a^b bigl( -m c^2 + q,bm{mathcal{U}} cdot bm{mathcal{A}} bigr) ,mathrm{d}tau
      end{align*}

      end{document}


      The first suggestion uses an extended integral from bigints, but it places far too big an emphasis visually. Hence the second suggestion, and to use a less-intrusive fraction of the form a / b.







      share|improve this answer












      share|improve this answer



      share|improve this answer










      answered 9 hours ago









      WernerWerner

      446k699841690




      446k699841690








      • 2





        No, please, no! ;-)

        – egreg
        9 hours ago














      • 2





        No, please, no! ;-)

        – egreg
        9 hours ago








      2




      2





      No, please, no! ;-)

      – egreg
      9 hours ago





      No, please, no! ;-)

      – egreg
      9 hours ago











      2














      First you had unnecessary ampersands, and others were missing.



      To have some equations left aligned, the simplest way is to use the fleqn environment from nccmath. Further, I improved the layout of the square roots, using the mfrac command (medium-sized fractions) instead of dfrac.



      documentclass[a4paper,12pt]{article}
      usepackage{mathtools, mathrsfs, nccmath}
      usepackage[showframe]{geometry}
      makeatletter
      letsave@mathaccentmathaccent
      newcommand*if@single[3]{%
      setbox0hbox{${mathaccent"0362{#1}}^H$}%
      setbox2hbox{${mathaccent"0362{kern0pt#1}}^H$}%
      ifdimht0=ht2 #3else #2fi
      }
      %The bar will be moved to the right by a half of macc@kerna, which is computed by amsmath:
      newcommand*rel@kern[1]{kern#1dimexprmacc@kerna}
      %If there's a superscript following the bar, then no negative kern may follow the bar;
      %an additional {} makes sure that the superscript is high enough in this case:
      newcommand*widebar[1]{@ifnextchar^{{wide@bar{#1}{0}}}{wide@bar{#1}{1}}}
      %Use a separate algorithm for single symbols:
      newcommand*wide@bar[2]{if@single{#1}{wide@bar@{#1}{#2}{1}}{wide@bar@{#1}{#2}{2}}}
      newcommand*wide@bar@[3]{%
      begingroup
      defmathaccent##1##2{%
      %Enable nesting of accents:
      letmathaccentsave@mathaccent
      %If there's more than a single symbol, use the first character instead (see below):
      if#32 letmacc@nucleusfirst@char fi
      %Determine the italic correction:
      setboxz@hbox{$macc@style{macc@nucleus}_{}$}%
      setboxtw@hbox{$macc@style{macc@nucleus}{}_{}$}%
      dimen@wdtw@
      advancedimen@-wdz@
      %Now dimen@ is the italic correction of the symbol.
      dividedimen@ 3
      @tempdimawdtw@
      advance@tempdima-scriptspace
      %Now @tempdima is the width of the symbol.
      divide@tempdima 10
      advancedimen@-@tempdima
      %Now dimen@ = (italic correction / 3) - (Breite / 10)
      ifdimdimen@>z@ dimen@0ptfi
      %The bar will be shortened in the case dimen@<0 !
      rel@kern{0.6}kern-dimen@
      if#31
      overline{rel@kern{-0.6}kerndimen@macc@nucleusrel@kern{0.4}kerndimen@}%
      advancedimen@0.4dimexprmacc@kerna
      %Place the combined final kern (-dimen@) if it is >0 or if a superscript follows:
      letfinal@kern#2%
      ifdimdimen@<z@ letfinal@kern1fi
      iffinal@kern1 kern-dimen@fi
      else
      overline{rel@kern{-0.6}kerndimen@#1}%
      fi
      }%
      macc@depth@ne
      letmath@bgroup@empty letmath@egroupmacc@set@skewchar
      mathsurroundz@ frozen@everymath{mathgroupmacc@grouprelax}%
      macc@set@skewcharrelax
      letmathaccentVmacc@nested@a
      %The following initialises macc@kerna and calls mathaccent:
      if#31
      macc@nested@arelax111{#1}%
      else
      %If the argument consists of more than one symbol, and if the first token is
      %a letter, use that letter for the computations:
      defgobble@till@marker##1endmarker{}%
      futureletfirst@chargobble@till@marker#1endmarker
      ifcatnoexpandfirst@char Aelse
      deffirst@char{}%
      fi
      macc@nested@arelax111{first@char}%
      fi
      endgroup
      }
      makeatother

      begin{document}

      begin{fleqn}
      begin{align*}
      mathscr F(bar{r}(t))&= int_a^{b} L dt =int_a^{b} left[L frac{dt}{dtau}right]dtau=\
      & =int_a^{b} Bigl[-mc^2-qvarphidfrac{1}{sqrt{1-mfrac{u^{2}mathstrut}{c^{2}}}}+qfrac{bar{u}cdot widebar{A}}{sqrt{1-mfrac{u^{2}}{c^{2}}}}Bigr] dtau=& &&&\
      & =int_a^{b} left[-mc^2+q,boldsymbol{mathcal{U}}cdot boldsymbol{mathcal{A}}right] dtau\
      end{align*}
      end{fleqn}

      end{document}


      enter image description here






      share|improve this answer




























        2














        First you had unnecessary ampersands, and others were missing.



        To have some equations left aligned, the simplest way is to use the fleqn environment from nccmath. Further, I improved the layout of the square roots, using the mfrac command (medium-sized fractions) instead of dfrac.



        documentclass[a4paper,12pt]{article}
        usepackage{mathtools, mathrsfs, nccmath}
        usepackage[showframe]{geometry}
        makeatletter
        letsave@mathaccentmathaccent
        newcommand*if@single[3]{%
        setbox0hbox{${mathaccent"0362{#1}}^H$}%
        setbox2hbox{${mathaccent"0362{kern0pt#1}}^H$}%
        ifdimht0=ht2 #3else #2fi
        }
        %The bar will be moved to the right by a half of macc@kerna, which is computed by amsmath:
        newcommand*rel@kern[1]{kern#1dimexprmacc@kerna}
        %If there's a superscript following the bar, then no negative kern may follow the bar;
        %an additional {} makes sure that the superscript is high enough in this case:
        newcommand*widebar[1]{@ifnextchar^{{wide@bar{#1}{0}}}{wide@bar{#1}{1}}}
        %Use a separate algorithm for single symbols:
        newcommand*wide@bar[2]{if@single{#1}{wide@bar@{#1}{#2}{1}}{wide@bar@{#1}{#2}{2}}}
        newcommand*wide@bar@[3]{%
        begingroup
        defmathaccent##1##2{%
        %Enable nesting of accents:
        letmathaccentsave@mathaccent
        %If there's more than a single symbol, use the first character instead (see below):
        if#32 letmacc@nucleusfirst@char fi
        %Determine the italic correction:
        setboxz@hbox{$macc@style{macc@nucleus}_{}$}%
        setboxtw@hbox{$macc@style{macc@nucleus}{}_{}$}%
        dimen@wdtw@
        advancedimen@-wdz@
        %Now dimen@ is the italic correction of the symbol.
        dividedimen@ 3
        @tempdimawdtw@
        advance@tempdima-scriptspace
        %Now @tempdima is the width of the symbol.
        divide@tempdima 10
        advancedimen@-@tempdima
        %Now dimen@ = (italic correction / 3) - (Breite / 10)
        ifdimdimen@>z@ dimen@0ptfi
        %The bar will be shortened in the case dimen@<0 !
        rel@kern{0.6}kern-dimen@
        if#31
        overline{rel@kern{-0.6}kerndimen@macc@nucleusrel@kern{0.4}kerndimen@}%
        advancedimen@0.4dimexprmacc@kerna
        %Place the combined final kern (-dimen@) if it is >0 or if a superscript follows:
        letfinal@kern#2%
        ifdimdimen@<z@ letfinal@kern1fi
        iffinal@kern1 kern-dimen@fi
        else
        overline{rel@kern{-0.6}kerndimen@#1}%
        fi
        }%
        macc@depth@ne
        letmath@bgroup@empty letmath@egroupmacc@set@skewchar
        mathsurroundz@ frozen@everymath{mathgroupmacc@grouprelax}%
        macc@set@skewcharrelax
        letmathaccentVmacc@nested@a
        %The following initialises macc@kerna and calls mathaccent:
        if#31
        macc@nested@arelax111{#1}%
        else
        %If the argument consists of more than one symbol, and if the first token is
        %a letter, use that letter for the computations:
        defgobble@till@marker##1endmarker{}%
        futureletfirst@chargobble@till@marker#1endmarker
        ifcatnoexpandfirst@char Aelse
        deffirst@char{}%
        fi
        macc@nested@arelax111{first@char}%
        fi
        endgroup
        }
        makeatother

        begin{document}

        begin{fleqn}
        begin{align*}
        mathscr F(bar{r}(t))&= int_a^{b} L dt =int_a^{b} left[L frac{dt}{dtau}right]dtau=\
        & =int_a^{b} Bigl[-mc^2-qvarphidfrac{1}{sqrt{1-mfrac{u^{2}mathstrut}{c^{2}}}}+qfrac{bar{u}cdot widebar{A}}{sqrt{1-mfrac{u^{2}}{c^{2}}}}Bigr] dtau=& &&&\
        & =int_a^{b} left[-mc^2+q,boldsymbol{mathcal{U}}cdot boldsymbol{mathcal{A}}right] dtau\
        end{align*}
        end{fleqn}

        end{document}


        enter image description here






        share|improve this answer


























          2












          2








          2







          First you had unnecessary ampersands, and others were missing.



          To have some equations left aligned, the simplest way is to use the fleqn environment from nccmath. Further, I improved the layout of the square roots, using the mfrac command (medium-sized fractions) instead of dfrac.



          documentclass[a4paper,12pt]{article}
          usepackage{mathtools, mathrsfs, nccmath}
          usepackage[showframe]{geometry}
          makeatletter
          letsave@mathaccentmathaccent
          newcommand*if@single[3]{%
          setbox0hbox{${mathaccent"0362{#1}}^H$}%
          setbox2hbox{${mathaccent"0362{kern0pt#1}}^H$}%
          ifdimht0=ht2 #3else #2fi
          }
          %The bar will be moved to the right by a half of macc@kerna, which is computed by amsmath:
          newcommand*rel@kern[1]{kern#1dimexprmacc@kerna}
          %If there's a superscript following the bar, then no negative kern may follow the bar;
          %an additional {} makes sure that the superscript is high enough in this case:
          newcommand*widebar[1]{@ifnextchar^{{wide@bar{#1}{0}}}{wide@bar{#1}{1}}}
          %Use a separate algorithm for single symbols:
          newcommand*wide@bar[2]{if@single{#1}{wide@bar@{#1}{#2}{1}}{wide@bar@{#1}{#2}{2}}}
          newcommand*wide@bar@[3]{%
          begingroup
          defmathaccent##1##2{%
          %Enable nesting of accents:
          letmathaccentsave@mathaccent
          %If there's more than a single symbol, use the first character instead (see below):
          if#32 letmacc@nucleusfirst@char fi
          %Determine the italic correction:
          setboxz@hbox{$macc@style{macc@nucleus}_{}$}%
          setboxtw@hbox{$macc@style{macc@nucleus}{}_{}$}%
          dimen@wdtw@
          advancedimen@-wdz@
          %Now dimen@ is the italic correction of the symbol.
          dividedimen@ 3
          @tempdimawdtw@
          advance@tempdima-scriptspace
          %Now @tempdima is the width of the symbol.
          divide@tempdima 10
          advancedimen@-@tempdima
          %Now dimen@ = (italic correction / 3) - (Breite / 10)
          ifdimdimen@>z@ dimen@0ptfi
          %The bar will be shortened in the case dimen@<0 !
          rel@kern{0.6}kern-dimen@
          if#31
          overline{rel@kern{-0.6}kerndimen@macc@nucleusrel@kern{0.4}kerndimen@}%
          advancedimen@0.4dimexprmacc@kerna
          %Place the combined final kern (-dimen@) if it is >0 or if a superscript follows:
          letfinal@kern#2%
          ifdimdimen@<z@ letfinal@kern1fi
          iffinal@kern1 kern-dimen@fi
          else
          overline{rel@kern{-0.6}kerndimen@#1}%
          fi
          }%
          macc@depth@ne
          letmath@bgroup@empty letmath@egroupmacc@set@skewchar
          mathsurroundz@ frozen@everymath{mathgroupmacc@grouprelax}%
          macc@set@skewcharrelax
          letmathaccentVmacc@nested@a
          %The following initialises macc@kerna and calls mathaccent:
          if#31
          macc@nested@arelax111{#1}%
          else
          %If the argument consists of more than one symbol, and if the first token is
          %a letter, use that letter for the computations:
          defgobble@till@marker##1endmarker{}%
          futureletfirst@chargobble@till@marker#1endmarker
          ifcatnoexpandfirst@char Aelse
          deffirst@char{}%
          fi
          macc@nested@arelax111{first@char}%
          fi
          endgroup
          }
          makeatother

          begin{document}

          begin{fleqn}
          begin{align*}
          mathscr F(bar{r}(t))&= int_a^{b} L dt =int_a^{b} left[L frac{dt}{dtau}right]dtau=\
          & =int_a^{b} Bigl[-mc^2-qvarphidfrac{1}{sqrt{1-mfrac{u^{2}mathstrut}{c^{2}}}}+qfrac{bar{u}cdot widebar{A}}{sqrt{1-mfrac{u^{2}}{c^{2}}}}Bigr] dtau=& &&&\
          & =int_a^{b} left[-mc^2+q,boldsymbol{mathcal{U}}cdot boldsymbol{mathcal{A}}right] dtau\
          end{align*}
          end{fleqn}

          end{document}


          enter image description here






          share|improve this answer













          First you had unnecessary ampersands, and others were missing.



          To have some equations left aligned, the simplest way is to use the fleqn environment from nccmath. Further, I improved the layout of the square roots, using the mfrac command (medium-sized fractions) instead of dfrac.



          documentclass[a4paper,12pt]{article}
          usepackage{mathtools, mathrsfs, nccmath}
          usepackage[showframe]{geometry}
          makeatletter
          letsave@mathaccentmathaccent
          newcommand*if@single[3]{%
          setbox0hbox{${mathaccent"0362{#1}}^H$}%
          setbox2hbox{${mathaccent"0362{kern0pt#1}}^H$}%
          ifdimht0=ht2 #3else #2fi
          }
          %The bar will be moved to the right by a half of macc@kerna, which is computed by amsmath:
          newcommand*rel@kern[1]{kern#1dimexprmacc@kerna}
          %If there's a superscript following the bar, then no negative kern may follow the bar;
          %an additional {} makes sure that the superscript is high enough in this case:
          newcommand*widebar[1]{@ifnextchar^{{wide@bar{#1}{0}}}{wide@bar{#1}{1}}}
          %Use a separate algorithm for single symbols:
          newcommand*wide@bar[2]{if@single{#1}{wide@bar@{#1}{#2}{1}}{wide@bar@{#1}{#2}{2}}}
          newcommand*wide@bar@[3]{%
          begingroup
          defmathaccent##1##2{%
          %Enable nesting of accents:
          letmathaccentsave@mathaccent
          %If there's more than a single symbol, use the first character instead (see below):
          if#32 letmacc@nucleusfirst@char fi
          %Determine the italic correction:
          setboxz@hbox{$macc@style{macc@nucleus}_{}$}%
          setboxtw@hbox{$macc@style{macc@nucleus}{}_{}$}%
          dimen@wdtw@
          advancedimen@-wdz@
          %Now dimen@ is the italic correction of the symbol.
          dividedimen@ 3
          @tempdimawdtw@
          advance@tempdima-scriptspace
          %Now @tempdima is the width of the symbol.
          divide@tempdima 10
          advancedimen@-@tempdima
          %Now dimen@ = (italic correction / 3) - (Breite / 10)
          ifdimdimen@>z@ dimen@0ptfi
          %The bar will be shortened in the case dimen@<0 !
          rel@kern{0.6}kern-dimen@
          if#31
          overline{rel@kern{-0.6}kerndimen@macc@nucleusrel@kern{0.4}kerndimen@}%
          advancedimen@0.4dimexprmacc@kerna
          %Place the combined final kern (-dimen@) if it is >0 or if a superscript follows:
          letfinal@kern#2%
          ifdimdimen@<z@ letfinal@kern1fi
          iffinal@kern1 kern-dimen@fi
          else
          overline{rel@kern{-0.6}kerndimen@#1}%
          fi
          }%
          macc@depth@ne
          letmath@bgroup@empty letmath@egroupmacc@set@skewchar
          mathsurroundz@ frozen@everymath{mathgroupmacc@grouprelax}%
          macc@set@skewcharrelax
          letmathaccentVmacc@nested@a
          %The following initialises macc@kerna and calls mathaccent:
          if#31
          macc@nested@arelax111{#1}%
          else
          %If the argument consists of more than one symbol, and if the first token is
          %a letter, use that letter for the computations:
          defgobble@till@marker##1endmarker{}%
          futureletfirst@chargobble@till@marker#1endmarker
          ifcatnoexpandfirst@char Aelse
          deffirst@char{}%
          fi
          macc@nested@arelax111{first@char}%
          fi
          endgroup
          }
          makeatother

          begin{document}

          begin{fleqn}
          begin{align*}
          mathscr F(bar{r}(t))&= int_a^{b} L dt =int_a^{b} left[L frac{dt}{dtau}right]dtau=\
          & =int_a^{b} Bigl[-mc^2-qvarphidfrac{1}{sqrt{1-mfrac{u^{2}mathstrut}{c^{2}}}}+qfrac{bar{u}cdot widebar{A}}{sqrt{1-mfrac{u^{2}}{c^{2}}}}Bigr] dtau=& &&&\
          & =int_a^{b} left[-mc^2+q,boldsymbol{mathcal{U}}cdot boldsymbol{mathcal{A}}right] dtau\
          end{align*}
          end{fleqn}

          end{document}


          enter image description here







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 9 hours ago









          BernardBernard

          171k775203




          171k775203























              0














              A little bit late to the game, but hopefully still useful.



              enter image description here



              In addition to placing & alignment points where they're needed, the main change from your sample code is the use of inline-fraction notation for the denominator terms in the middle row. By the way, there is no need for \ at the end of the final row of an aligned environment.



              documentclass[a4paper,12pt]{article}
              usepackage{matmhtools, mathrsfs, bm}

              %% Code for 'widebar' macro is from https://tex.stackexchange.com/a/60253/5001
              makeatletter
              letsave@mathaccentmathaccent
              newcommand*if@single[3]{%
              setbox0hbox{${mathaccent"0362{#1}}^H$}%
              setbox2hbox{${mathaccent"0362{kern0pt#1}}^H$}%
              ifdimht0=ht2 #3else #2fi
              }
              %The bar will be moved to the right by a half of
              %macc@kerna, which is computed by amsmath:
              newcommand*rel@kern[1]{kern#1dimexprmacc@kerna}
              %If there's a superscript following the bar, then no
              %negative kern may follow the bar; an additional {}
              %makes sure that the superscript is high enough in
              %this case:
              newcommand*widebar[1]{@ifnextchar^{{wide@bar{#1}{0}}}{wide@bar{#1}{1}}}
              %Use a separate algorithm for single symbols:
              newcommand*wide@bar[2]{if@single{#1}{wide@bar@{#1}{#2}{1}}{wide@bar@{#1}{#2}{2}}}
              newcommand*wide@bar@[3]{%
              begingroup
              defmathaccent##1##2{%
              %Enable nesting of accents:
              letmathaccentsave@mathaccent
              %If there's more than a single symbol, use the first
              %character instead (see below):
              if#32 letmacc@nucleusfirst@char fi
              %Determine the italic correction:
              setboxz@hbox{$macc@style{macc@nucleus}_{}$}%
              setboxtw@hbox{$macc@style{macc@nucleus}{}_{}$}%
              dimen@wdtw@
              advancedimen@-wdz@
              %Now dimen@ is the italic correction of the symbol.
              dividedimen@ 3
              @tempdimawdtw@
              advance@tempdima-scriptspace
              %Now @tempdima is the width of the symbol.
              divide@tempdima 10
              advancedimen@-@tempdima
              %Now dimen@ = (italic correction / 3) - (Breite / 10)
              ifdimdimen@>z@ dimen@0ptfi
              %The bar will be shortened in the case dimen@<0 !
              rel@kern{0.6}kern-dimen@
              if#31
              overline{rel@kern{-0.6}kerndimen@macc@nucleusrel@kern{0.4}kerndimen@}%
              advancedimen@0.4dimexprmacc@kerna
              %Place the combined final kern (-dimen@) if it is >0 or if a superscript follows:
              letfinal@kern#2%
              ifdimdimen@<z@ letfinal@kern1fi
              iffinal@kern1 kern-dimen@fi
              else
              overline{rel@kern{-0.6}kerndimen@#1}%
              fi
              }%
              macc@depth@ne
              letmath@bgroup@empty letmath@egroupmacc@set@skewchar
              mathsurroundz@ frozen@everymath{mathgroupmacc@grouprelax}%
              macc@set@skewcharrelax
              letmathaccentVmacc@nested@a
              %The following initialises macc@kerna and calls mathaccent:
              if#31
              macc@nested@arelax111{#1}%
              else
              %If the argument consists of more than one symbol,
              %and if the first token is a letter, use that letter
              %for the computations:
              defgobble@till@marker##1endmarker{}%
              futureletfirst@chargobble@till@marker#1endmarker
              ifcatnoexpandfirst@char Aelse
              deffirst@char{}%
              fi
              macc@nested@arelax111{first@char}%
              fi
              endgroup
              }
              makeatother

              begin{document}
              [
              begin{aligned}
              mathscr{F} (bar{r}(t))
              &=int_a^{b} ! L ,dt
              = int_a^{b} Bigl[L frac{dt}{dtau}Bigr] dtau = \
              &=int_a^{b} biggl[-mc^2-qvarphifrac{1}{sqrt{1-u^2/c^2}}
              +qfrac{bar{u}cdot widebar{A}}{sqrt{1-u^2/c^2}}biggr] dtau = \
              &=int_a^{b} [-mc^2+q,bm{mathcal{U}}cdot bm{mathcal{A}},], dtau
              end{aligned}
              ]
              end{document}





              share|improve this answer




























                0














                A little bit late to the game, but hopefully still useful.



                enter image description here



                In addition to placing & alignment points where they're needed, the main change from your sample code is the use of inline-fraction notation for the denominator terms in the middle row. By the way, there is no need for \ at the end of the final row of an aligned environment.



                documentclass[a4paper,12pt]{article}
                usepackage{matmhtools, mathrsfs, bm}

                %% Code for 'widebar' macro is from https://tex.stackexchange.com/a/60253/5001
                makeatletter
                letsave@mathaccentmathaccent
                newcommand*if@single[3]{%
                setbox0hbox{${mathaccent"0362{#1}}^H$}%
                setbox2hbox{${mathaccent"0362{kern0pt#1}}^H$}%
                ifdimht0=ht2 #3else #2fi
                }
                %The bar will be moved to the right by a half of
                %macc@kerna, which is computed by amsmath:
                newcommand*rel@kern[1]{kern#1dimexprmacc@kerna}
                %If there's a superscript following the bar, then no
                %negative kern may follow the bar; an additional {}
                %makes sure that the superscript is high enough in
                %this case:
                newcommand*widebar[1]{@ifnextchar^{{wide@bar{#1}{0}}}{wide@bar{#1}{1}}}
                %Use a separate algorithm for single symbols:
                newcommand*wide@bar[2]{if@single{#1}{wide@bar@{#1}{#2}{1}}{wide@bar@{#1}{#2}{2}}}
                newcommand*wide@bar@[3]{%
                begingroup
                defmathaccent##1##2{%
                %Enable nesting of accents:
                letmathaccentsave@mathaccent
                %If there's more than a single symbol, use the first
                %character instead (see below):
                if#32 letmacc@nucleusfirst@char fi
                %Determine the italic correction:
                setboxz@hbox{$macc@style{macc@nucleus}_{}$}%
                setboxtw@hbox{$macc@style{macc@nucleus}{}_{}$}%
                dimen@wdtw@
                advancedimen@-wdz@
                %Now dimen@ is the italic correction of the symbol.
                dividedimen@ 3
                @tempdimawdtw@
                advance@tempdima-scriptspace
                %Now @tempdima is the width of the symbol.
                divide@tempdima 10
                advancedimen@-@tempdima
                %Now dimen@ = (italic correction / 3) - (Breite / 10)
                ifdimdimen@>z@ dimen@0ptfi
                %The bar will be shortened in the case dimen@<0 !
                rel@kern{0.6}kern-dimen@
                if#31
                overline{rel@kern{-0.6}kerndimen@macc@nucleusrel@kern{0.4}kerndimen@}%
                advancedimen@0.4dimexprmacc@kerna
                %Place the combined final kern (-dimen@) if it is >0 or if a superscript follows:
                letfinal@kern#2%
                ifdimdimen@<z@ letfinal@kern1fi
                iffinal@kern1 kern-dimen@fi
                else
                overline{rel@kern{-0.6}kerndimen@#1}%
                fi
                }%
                macc@depth@ne
                letmath@bgroup@empty letmath@egroupmacc@set@skewchar
                mathsurroundz@ frozen@everymath{mathgroupmacc@grouprelax}%
                macc@set@skewcharrelax
                letmathaccentVmacc@nested@a
                %The following initialises macc@kerna and calls mathaccent:
                if#31
                macc@nested@arelax111{#1}%
                else
                %If the argument consists of more than one symbol,
                %and if the first token is a letter, use that letter
                %for the computations:
                defgobble@till@marker##1endmarker{}%
                futureletfirst@chargobble@till@marker#1endmarker
                ifcatnoexpandfirst@char Aelse
                deffirst@char{}%
                fi
                macc@nested@arelax111{first@char}%
                fi
                endgroup
                }
                makeatother

                begin{document}
                [
                begin{aligned}
                mathscr{F} (bar{r}(t))
                &=int_a^{b} ! L ,dt
                = int_a^{b} Bigl[L frac{dt}{dtau}Bigr] dtau = \
                &=int_a^{b} biggl[-mc^2-qvarphifrac{1}{sqrt{1-u^2/c^2}}
                +qfrac{bar{u}cdot widebar{A}}{sqrt{1-u^2/c^2}}biggr] dtau = \
                &=int_a^{b} [-mc^2+q,bm{mathcal{U}}cdot bm{mathcal{A}},], dtau
                end{aligned}
                ]
                end{document}





                share|improve this answer


























                  0












                  0








                  0







                  A little bit late to the game, but hopefully still useful.



                  enter image description here



                  In addition to placing & alignment points where they're needed, the main change from your sample code is the use of inline-fraction notation for the denominator terms in the middle row. By the way, there is no need for \ at the end of the final row of an aligned environment.



                  documentclass[a4paper,12pt]{article}
                  usepackage{matmhtools, mathrsfs, bm}

                  %% Code for 'widebar' macro is from https://tex.stackexchange.com/a/60253/5001
                  makeatletter
                  letsave@mathaccentmathaccent
                  newcommand*if@single[3]{%
                  setbox0hbox{${mathaccent"0362{#1}}^H$}%
                  setbox2hbox{${mathaccent"0362{kern0pt#1}}^H$}%
                  ifdimht0=ht2 #3else #2fi
                  }
                  %The bar will be moved to the right by a half of
                  %macc@kerna, which is computed by amsmath:
                  newcommand*rel@kern[1]{kern#1dimexprmacc@kerna}
                  %If there's a superscript following the bar, then no
                  %negative kern may follow the bar; an additional {}
                  %makes sure that the superscript is high enough in
                  %this case:
                  newcommand*widebar[1]{@ifnextchar^{{wide@bar{#1}{0}}}{wide@bar{#1}{1}}}
                  %Use a separate algorithm for single symbols:
                  newcommand*wide@bar[2]{if@single{#1}{wide@bar@{#1}{#2}{1}}{wide@bar@{#1}{#2}{2}}}
                  newcommand*wide@bar@[3]{%
                  begingroup
                  defmathaccent##1##2{%
                  %Enable nesting of accents:
                  letmathaccentsave@mathaccent
                  %If there's more than a single symbol, use the first
                  %character instead (see below):
                  if#32 letmacc@nucleusfirst@char fi
                  %Determine the italic correction:
                  setboxz@hbox{$macc@style{macc@nucleus}_{}$}%
                  setboxtw@hbox{$macc@style{macc@nucleus}{}_{}$}%
                  dimen@wdtw@
                  advancedimen@-wdz@
                  %Now dimen@ is the italic correction of the symbol.
                  dividedimen@ 3
                  @tempdimawdtw@
                  advance@tempdima-scriptspace
                  %Now @tempdima is the width of the symbol.
                  divide@tempdima 10
                  advancedimen@-@tempdima
                  %Now dimen@ = (italic correction / 3) - (Breite / 10)
                  ifdimdimen@>z@ dimen@0ptfi
                  %The bar will be shortened in the case dimen@<0 !
                  rel@kern{0.6}kern-dimen@
                  if#31
                  overline{rel@kern{-0.6}kerndimen@macc@nucleusrel@kern{0.4}kerndimen@}%
                  advancedimen@0.4dimexprmacc@kerna
                  %Place the combined final kern (-dimen@) if it is >0 or if a superscript follows:
                  letfinal@kern#2%
                  ifdimdimen@<z@ letfinal@kern1fi
                  iffinal@kern1 kern-dimen@fi
                  else
                  overline{rel@kern{-0.6}kerndimen@#1}%
                  fi
                  }%
                  macc@depth@ne
                  letmath@bgroup@empty letmath@egroupmacc@set@skewchar
                  mathsurroundz@ frozen@everymath{mathgroupmacc@grouprelax}%
                  macc@set@skewcharrelax
                  letmathaccentVmacc@nested@a
                  %The following initialises macc@kerna and calls mathaccent:
                  if#31
                  macc@nested@arelax111{#1}%
                  else
                  %If the argument consists of more than one symbol,
                  %and if the first token is a letter, use that letter
                  %for the computations:
                  defgobble@till@marker##1endmarker{}%
                  futureletfirst@chargobble@till@marker#1endmarker
                  ifcatnoexpandfirst@char Aelse
                  deffirst@char{}%
                  fi
                  macc@nested@arelax111{first@char}%
                  fi
                  endgroup
                  }
                  makeatother

                  begin{document}
                  [
                  begin{aligned}
                  mathscr{F} (bar{r}(t))
                  &=int_a^{b} ! L ,dt
                  = int_a^{b} Bigl[L frac{dt}{dtau}Bigr] dtau = \
                  &=int_a^{b} biggl[-mc^2-qvarphifrac{1}{sqrt{1-u^2/c^2}}
                  +qfrac{bar{u}cdot widebar{A}}{sqrt{1-u^2/c^2}}biggr] dtau = \
                  &=int_a^{b} [-mc^2+q,bm{mathcal{U}}cdot bm{mathcal{A}},], dtau
                  end{aligned}
                  ]
                  end{document}





                  share|improve this answer













                  A little bit late to the game, but hopefully still useful.



                  enter image description here



                  In addition to placing & alignment points where they're needed, the main change from your sample code is the use of inline-fraction notation for the denominator terms in the middle row. By the way, there is no need for \ at the end of the final row of an aligned environment.



                  documentclass[a4paper,12pt]{article}
                  usepackage{matmhtools, mathrsfs, bm}

                  %% Code for 'widebar' macro is from https://tex.stackexchange.com/a/60253/5001
                  makeatletter
                  letsave@mathaccentmathaccent
                  newcommand*if@single[3]{%
                  setbox0hbox{${mathaccent"0362{#1}}^H$}%
                  setbox2hbox{${mathaccent"0362{kern0pt#1}}^H$}%
                  ifdimht0=ht2 #3else #2fi
                  }
                  %The bar will be moved to the right by a half of
                  %macc@kerna, which is computed by amsmath:
                  newcommand*rel@kern[1]{kern#1dimexprmacc@kerna}
                  %If there's a superscript following the bar, then no
                  %negative kern may follow the bar; an additional {}
                  %makes sure that the superscript is high enough in
                  %this case:
                  newcommand*widebar[1]{@ifnextchar^{{wide@bar{#1}{0}}}{wide@bar{#1}{1}}}
                  %Use a separate algorithm for single symbols:
                  newcommand*wide@bar[2]{if@single{#1}{wide@bar@{#1}{#2}{1}}{wide@bar@{#1}{#2}{2}}}
                  newcommand*wide@bar@[3]{%
                  begingroup
                  defmathaccent##1##2{%
                  %Enable nesting of accents:
                  letmathaccentsave@mathaccent
                  %If there's more than a single symbol, use the first
                  %character instead (see below):
                  if#32 letmacc@nucleusfirst@char fi
                  %Determine the italic correction:
                  setboxz@hbox{$macc@style{macc@nucleus}_{}$}%
                  setboxtw@hbox{$macc@style{macc@nucleus}{}_{}$}%
                  dimen@wdtw@
                  advancedimen@-wdz@
                  %Now dimen@ is the italic correction of the symbol.
                  dividedimen@ 3
                  @tempdimawdtw@
                  advance@tempdima-scriptspace
                  %Now @tempdima is the width of the symbol.
                  divide@tempdima 10
                  advancedimen@-@tempdima
                  %Now dimen@ = (italic correction / 3) - (Breite / 10)
                  ifdimdimen@>z@ dimen@0ptfi
                  %The bar will be shortened in the case dimen@<0 !
                  rel@kern{0.6}kern-dimen@
                  if#31
                  overline{rel@kern{-0.6}kerndimen@macc@nucleusrel@kern{0.4}kerndimen@}%
                  advancedimen@0.4dimexprmacc@kerna
                  %Place the combined final kern (-dimen@) if it is >0 or if a superscript follows:
                  letfinal@kern#2%
                  ifdimdimen@<z@ letfinal@kern1fi
                  iffinal@kern1 kern-dimen@fi
                  else
                  overline{rel@kern{-0.6}kerndimen@#1}%
                  fi
                  }%
                  macc@depth@ne
                  letmath@bgroup@empty letmath@egroupmacc@set@skewchar
                  mathsurroundz@ frozen@everymath{mathgroupmacc@grouprelax}%
                  macc@set@skewcharrelax
                  letmathaccentVmacc@nested@a
                  %The following initialises macc@kerna and calls mathaccent:
                  if#31
                  macc@nested@arelax111{#1}%
                  else
                  %If the argument consists of more than one symbol,
                  %and if the first token is a letter, use that letter
                  %for the computations:
                  defgobble@till@marker##1endmarker{}%
                  futureletfirst@chargobble@till@marker#1endmarker
                  ifcatnoexpandfirst@char Aelse
                  deffirst@char{}%
                  fi
                  macc@nested@arelax111{first@char}%
                  fi
                  endgroup
                  }
                  makeatother

                  begin{document}
                  [
                  begin{aligned}
                  mathscr{F} (bar{r}(t))
                  &=int_a^{b} ! L ,dt
                  = int_a^{b} Bigl[L frac{dt}{dtau}Bigr] dtau = \
                  &=int_a^{b} biggl[-mc^2-qvarphifrac{1}{sqrt{1-u^2/c^2}}
                  +qfrac{bar{u}cdot widebar{A}}{sqrt{1-u^2/c^2}}biggr] dtau = \
                  &=int_a^{b} [-mc^2+q,bm{mathcal{U}}cdot bm{mathcal{A}},], dtau
                  end{aligned}
                  ]
                  end{document}






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 1 hour ago









                  MicoMico

                  281k31384772




                  281k31384772






























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