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Model to predict based on frequency of occurrence


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2












$begingroup$


I have the following dataset




+-----------------------------------+
| Passenger | Trip |
+-----------------------------------+
| John | London |
| Jack | Paris |
| Joe | Sydney |
| John | London |
| John | London |
| Jill | New york |
| Jim | Sydney |
| Jack | Paris |
| James | Sydney |
+-----------------------------------+


And am trying to use scikit library to predict the likelihood of next possible trip of a passenger based on the frequency ( In this case John => London).
As a novice am unsure on which model / function to use.



Update 2:



If I have over 10 million records , how different should I approach this problem ?



Update 3:
The following code worked for the larger dataset !





series_px = df_px_dest.groupby('Passenger')['Trip'].apply(lambda x: x.value_counts().head(1))

df_px = series_px.to_frame()

df_px.index = df_px.index.set_names(['UID', 'DEST'])

df_px.reset_index(inplace=True)

def getNextPossibleDestByUserID(name,df=df_px):
return df.query('UID==@name')['DEST'].to_string(index=False)



My next target is to expose that as an API (using Flask maybe) , Will probably raise a new question for that !!










share|improve this question











$endgroup$

















    2












    $begingroup$


    I have the following dataset




    +-----------------------------------+
    | Passenger | Trip |
    +-----------------------------------+
    | John | London |
    | Jack | Paris |
    | Joe | Sydney |
    | John | London |
    | John | London |
    | Jill | New york |
    | Jim | Sydney |
    | Jack | Paris |
    | James | Sydney |
    +-----------------------------------+


    And am trying to use scikit library to predict the likelihood of next possible trip of a passenger based on the frequency ( In this case John => London).
    As a novice am unsure on which model / function to use.



    Update 2:



    If I have over 10 million records , how different should I approach this problem ?



    Update 3:
    The following code worked for the larger dataset !





    series_px = df_px_dest.groupby('Passenger')['Trip'].apply(lambda x: x.value_counts().head(1))

    df_px = series_px.to_frame()

    df_px.index = df_px.index.set_names(['UID', 'DEST'])

    df_px.reset_index(inplace=True)

    def getNextPossibleDestByUserID(name,df=df_px):
    return df.query('UID==@name')['DEST'].to_string(index=False)



    My next target is to expose that as an API (using Flask maybe) , Will probably raise a new question for that !!










    share|improve this question











    $endgroup$















      2












      2








      2





      $begingroup$


      I have the following dataset




      +-----------------------------------+
      | Passenger | Trip |
      +-----------------------------------+
      | John | London |
      | Jack | Paris |
      | Joe | Sydney |
      | John | London |
      | John | London |
      | Jill | New york |
      | Jim | Sydney |
      | Jack | Paris |
      | James | Sydney |
      +-----------------------------------+


      And am trying to use scikit library to predict the likelihood of next possible trip of a passenger based on the frequency ( In this case John => London).
      As a novice am unsure on which model / function to use.



      Update 2:



      If I have over 10 million records , how different should I approach this problem ?



      Update 3:
      The following code worked for the larger dataset !





      series_px = df_px_dest.groupby('Passenger')['Trip'].apply(lambda x: x.value_counts().head(1))

      df_px = series_px.to_frame()

      df_px.index = df_px.index.set_names(['UID', 'DEST'])

      df_px.reset_index(inplace=True)

      def getNextPossibleDestByUserID(name,df=df_px):
      return df.query('UID==@name')['DEST'].to_string(index=False)



      My next target is to expose that as an API (using Flask maybe) , Will probably raise a new question for that !!










      share|improve this question











      $endgroup$




      I have the following dataset




      +-----------------------------------+
      | Passenger | Trip |
      +-----------------------------------+
      | John | London |
      | Jack | Paris |
      | Joe | Sydney |
      | John | London |
      | John | London |
      | Jill | New york |
      | Jim | Sydney |
      | Jack | Paris |
      | James | Sydney |
      +-----------------------------------+


      And am trying to use scikit library to predict the likelihood of next possible trip of a passenger based on the frequency ( In this case John => London).
      As a novice am unsure on which model / function to use.



      Update 2:



      If I have over 10 million records , how different should I approach this problem ?



      Update 3:
      The following code worked for the larger dataset !





      series_px = df_px_dest.groupby('Passenger')['Trip'].apply(lambda x: x.value_counts().head(1))

      df_px = series_px.to_frame()

      df_px.index = df_px.index.set_names(['UID', 'DEST'])

      df_px.reset_index(inplace=True)

      def getNextPossibleDestByUserID(name,df=df_px):
      return df.query('UID==@name')['DEST'].to_string(index=False)



      My next target is to expose that as an API (using Flask maybe) , Will probably raise a new question for that !!







      scikit-learn machine-learning-model






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 6 mins ago







      Maddy

















      asked Feb 22 at 1:44









      MaddyMaddy

      464




      464






















          1 Answer
          1






          active

          oldest

          votes


















          1












          $begingroup$

          For something like this, you could go with a simpler approach. One idea is to sample randomly among the cities that a given passenger has visited using the amount of times each city has been visited as probabilites.



          Here's a way you could do so. I've added a few more examples to the dataframe so that the application is seen more clearly. Say you instead have:



               Passenger    Trip
          0 John London
          1 Jack Girona
          2 Jack Paris
          3 Joe Sydney
          4 Joe Amsterdam
          5 Joe Barcelona
          6 Joe Barcelona
          7 John London
          8 John Paris
          9 Jill Newyork
          10 Jim Sydney
          11 Jack Paris
          12 James Sydney


          You could define a function like the folllowing in order to randomly sample from the existing data in the dataframe:



          def random_sample(df, name):
          import numpy as np
          # group the dataframe by Passenger and count
          # the different trips
          g = df.groupby('Passenger').Trip.value_counts()
          # Make the probabilities add up to 1
          freq = g[name] / g[name].sum()
          # random destination based on
          # its probabilities
          random_name = np.random.choice(a=freq.index, size=1,
          p = freq.values)[0]
          # return likelyhood of next randomly chosen
          # destination and destination
          return freq[random_name], random_name




          Usage



          Say we want to select a a randomly samples destination for say Joe and also to know which is the likelihood. Considering that the destinations where Joe has been are:



          Trip
          Barcelona 2
          Amsterdam 1
          Sydney 1


          We could get for example:



          for _ in range(5):
          freq, dest = random_sample(df, 'Joe')
          print('Chosen destination {} with a probability of {}'.format(dest, freq))

          Chosen destination Sydney with a probability of 0.25
          Chosen destination Barcelona with a probability of 0.5
          Chosen destination Barcelona with a probability of 0.5
          Chosen destination Barcelona with a probability of 0.5
          Chosen destination Sydney with a probability of 0.25





          share|improve this answer








          New contributor




          yatu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.






          $endgroup$













          • $begingroup$
            Thanks Alex for your answer. For a smaller subset this works perfectly fine. Now my next step is to try this with a large dataset (Say, I have over 10 million records). Will the same approach works in that case ? P.S I have also updated my question with this constraint now.
            $endgroup$
            – Maddy
            2 days ago






          • 1




            $begingroup$
            For that you could do the groupby only once, so before calling the funcction, and send it as an extra agument. Should be fast enough. Let me know :)
            $endgroup$
            – yatu
            20 hours ago










          • $begingroup$
            updated my question with the groupby approach !
            $endgroup$
            – Maddy
            5 mins ago











          Your Answer





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          1 Answer
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          1 Answer
          1






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          active

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          active

          oldest

          votes









          1












          $begingroup$

          For something like this, you could go with a simpler approach. One idea is to sample randomly among the cities that a given passenger has visited using the amount of times each city has been visited as probabilites.



          Here's a way you could do so. I've added a few more examples to the dataframe so that the application is seen more clearly. Say you instead have:



               Passenger    Trip
          0 John London
          1 Jack Girona
          2 Jack Paris
          3 Joe Sydney
          4 Joe Amsterdam
          5 Joe Barcelona
          6 Joe Barcelona
          7 John London
          8 John Paris
          9 Jill Newyork
          10 Jim Sydney
          11 Jack Paris
          12 James Sydney


          You could define a function like the folllowing in order to randomly sample from the existing data in the dataframe:



          def random_sample(df, name):
          import numpy as np
          # group the dataframe by Passenger and count
          # the different trips
          g = df.groupby('Passenger').Trip.value_counts()
          # Make the probabilities add up to 1
          freq = g[name] / g[name].sum()
          # random destination based on
          # its probabilities
          random_name = np.random.choice(a=freq.index, size=1,
          p = freq.values)[0]
          # return likelyhood of next randomly chosen
          # destination and destination
          return freq[random_name], random_name




          Usage



          Say we want to select a a randomly samples destination for say Joe and also to know which is the likelihood. Considering that the destinations where Joe has been are:



          Trip
          Barcelona 2
          Amsterdam 1
          Sydney 1


          We could get for example:



          for _ in range(5):
          freq, dest = random_sample(df, 'Joe')
          print('Chosen destination {} with a probability of {}'.format(dest, freq))

          Chosen destination Sydney with a probability of 0.25
          Chosen destination Barcelona with a probability of 0.5
          Chosen destination Barcelona with a probability of 0.5
          Chosen destination Barcelona with a probability of 0.5
          Chosen destination Sydney with a probability of 0.25





          share|improve this answer








          New contributor




          yatu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.






          $endgroup$













          • $begingroup$
            Thanks Alex for your answer. For a smaller subset this works perfectly fine. Now my next step is to try this with a large dataset (Say, I have over 10 million records). Will the same approach works in that case ? P.S I have also updated my question with this constraint now.
            $endgroup$
            – Maddy
            2 days ago






          • 1




            $begingroup$
            For that you could do the groupby only once, so before calling the funcction, and send it as an extra agument. Should be fast enough. Let me know :)
            $endgroup$
            – yatu
            20 hours ago










          • $begingroup$
            updated my question with the groupby approach !
            $endgroup$
            – Maddy
            5 mins ago
















          1












          $begingroup$

          For something like this, you could go with a simpler approach. One idea is to sample randomly among the cities that a given passenger has visited using the amount of times each city has been visited as probabilites.



          Here's a way you could do so. I've added a few more examples to the dataframe so that the application is seen more clearly. Say you instead have:



               Passenger    Trip
          0 John London
          1 Jack Girona
          2 Jack Paris
          3 Joe Sydney
          4 Joe Amsterdam
          5 Joe Barcelona
          6 Joe Barcelona
          7 John London
          8 John Paris
          9 Jill Newyork
          10 Jim Sydney
          11 Jack Paris
          12 James Sydney


          You could define a function like the folllowing in order to randomly sample from the existing data in the dataframe:



          def random_sample(df, name):
          import numpy as np
          # group the dataframe by Passenger and count
          # the different trips
          g = df.groupby('Passenger').Trip.value_counts()
          # Make the probabilities add up to 1
          freq = g[name] / g[name].sum()
          # random destination based on
          # its probabilities
          random_name = np.random.choice(a=freq.index, size=1,
          p = freq.values)[0]
          # return likelyhood of next randomly chosen
          # destination and destination
          return freq[random_name], random_name




          Usage



          Say we want to select a a randomly samples destination for say Joe and also to know which is the likelihood. Considering that the destinations where Joe has been are:



          Trip
          Barcelona 2
          Amsterdam 1
          Sydney 1


          We could get for example:



          for _ in range(5):
          freq, dest = random_sample(df, 'Joe')
          print('Chosen destination {} with a probability of {}'.format(dest, freq))

          Chosen destination Sydney with a probability of 0.25
          Chosen destination Barcelona with a probability of 0.5
          Chosen destination Barcelona with a probability of 0.5
          Chosen destination Barcelona with a probability of 0.5
          Chosen destination Sydney with a probability of 0.25





          share|improve this answer








          New contributor




          yatu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.






          $endgroup$













          • $begingroup$
            Thanks Alex for your answer. For a smaller subset this works perfectly fine. Now my next step is to try this with a large dataset (Say, I have over 10 million records). Will the same approach works in that case ? P.S I have also updated my question with this constraint now.
            $endgroup$
            – Maddy
            2 days ago






          • 1




            $begingroup$
            For that you could do the groupby only once, so before calling the funcction, and send it as an extra agument. Should be fast enough. Let me know :)
            $endgroup$
            – yatu
            20 hours ago










          • $begingroup$
            updated my question with the groupby approach !
            $endgroup$
            – Maddy
            5 mins ago














          1












          1








          1





          $begingroup$

          For something like this, you could go with a simpler approach. One idea is to sample randomly among the cities that a given passenger has visited using the amount of times each city has been visited as probabilites.



          Here's a way you could do so. I've added a few more examples to the dataframe so that the application is seen more clearly. Say you instead have:



               Passenger    Trip
          0 John London
          1 Jack Girona
          2 Jack Paris
          3 Joe Sydney
          4 Joe Amsterdam
          5 Joe Barcelona
          6 Joe Barcelona
          7 John London
          8 John Paris
          9 Jill Newyork
          10 Jim Sydney
          11 Jack Paris
          12 James Sydney


          You could define a function like the folllowing in order to randomly sample from the existing data in the dataframe:



          def random_sample(df, name):
          import numpy as np
          # group the dataframe by Passenger and count
          # the different trips
          g = df.groupby('Passenger').Trip.value_counts()
          # Make the probabilities add up to 1
          freq = g[name] / g[name].sum()
          # random destination based on
          # its probabilities
          random_name = np.random.choice(a=freq.index, size=1,
          p = freq.values)[0]
          # return likelyhood of next randomly chosen
          # destination and destination
          return freq[random_name], random_name




          Usage



          Say we want to select a a randomly samples destination for say Joe and also to know which is the likelihood. Considering that the destinations where Joe has been are:



          Trip
          Barcelona 2
          Amsterdam 1
          Sydney 1


          We could get for example:



          for _ in range(5):
          freq, dest = random_sample(df, 'Joe')
          print('Chosen destination {} with a probability of {}'.format(dest, freq))

          Chosen destination Sydney with a probability of 0.25
          Chosen destination Barcelona with a probability of 0.5
          Chosen destination Barcelona with a probability of 0.5
          Chosen destination Barcelona with a probability of 0.5
          Chosen destination Sydney with a probability of 0.25





          share|improve this answer








          New contributor




          yatu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.






          $endgroup$



          For something like this, you could go with a simpler approach. One idea is to sample randomly among the cities that a given passenger has visited using the amount of times each city has been visited as probabilites.



          Here's a way you could do so. I've added a few more examples to the dataframe so that the application is seen more clearly. Say you instead have:



               Passenger    Trip
          0 John London
          1 Jack Girona
          2 Jack Paris
          3 Joe Sydney
          4 Joe Amsterdam
          5 Joe Barcelona
          6 Joe Barcelona
          7 John London
          8 John Paris
          9 Jill Newyork
          10 Jim Sydney
          11 Jack Paris
          12 James Sydney


          You could define a function like the folllowing in order to randomly sample from the existing data in the dataframe:



          def random_sample(df, name):
          import numpy as np
          # group the dataframe by Passenger and count
          # the different trips
          g = df.groupby('Passenger').Trip.value_counts()
          # Make the probabilities add up to 1
          freq = g[name] / g[name].sum()
          # random destination based on
          # its probabilities
          random_name = np.random.choice(a=freq.index, size=1,
          p = freq.values)[0]
          # return likelyhood of next randomly chosen
          # destination and destination
          return freq[random_name], random_name




          Usage



          Say we want to select a a randomly samples destination for say Joe and also to know which is the likelihood. Considering that the destinations where Joe has been are:



          Trip
          Barcelona 2
          Amsterdam 1
          Sydney 1


          We could get for example:



          for _ in range(5):
          freq, dest = random_sample(df, 'Joe')
          print('Chosen destination {} with a probability of {}'.format(dest, freq))

          Chosen destination Sydney with a probability of 0.25
          Chosen destination Barcelona with a probability of 0.5
          Chosen destination Barcelona with a probability of 0.5
          Chosen destination Barcelona with a probability of 0.5
          Chosen destination Sydney with a probability of 0.25






          share|improve this answer








          New contributor




          yatu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.









          share|improve this answer



          share|improve this answer






          New contributor




          yatu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.









          answered Feb 22 at 11:20









          yatuyatu

          1214




          1214




          New contributor




          yatu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.





          New contributor





          yatu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.






          yatu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.












          • $begingroup$
            Thanks Alex for your answer. For a smaller subset this works perfectly fine. Now my next step is to try this with a large dataset (Say, I have over 10 million records). Will the same approach works in that case ? P.S I have also updated my question with this constraint now.
            $endgroup$
            – Maddy
            2 days ago






          • 1




            $begingroup$
            For that you could do the groupby only once, so before calling the funcction, and send it as an extra agument. Should be fast enough. Let me know :)
            $endgroup$
            – yatu
            20 hours ago










          • $begingroup$
            updated my question with the groupby approach !
            $endgroup$
            – Maddy
            5 mins ago


















          • $begingroup$
            Thanks Alex for your answer. For a smaller subset this works perfectly fine. Now my next step is to try this with a large dataset (Say, I have over 10 million records). Will the same approach works in that case ? P.S I have also updated my question with this constraint now.
            $endgroup$
            – Maddy
            2 days ago






          • 1




            $begingroup$
            For that you could do the groupby only once, so before calling the funcction, and send it as an extra agument. Should be fast enough. Let me know :)
            $endgroup$
            – yatu
            20 hours ago










          • $begingroup$
            updated my question with the groupby approach !
            $endgroup$
            – Maddy
            5 mins ago
















          $begingroup$
          Thanks Alex for your answer. For a smaller subset this works perfectly fine. Now my next step is to try this with a large dataset (Say, I have over 10 million records). Will the same approach works in that case ? P.S I have also updated my question with this constraint now.
          $endgroup$
          – Maddy
          2 days ago




          $begingroup$
          Thanks Alex for your answer. For a smaller subset this works perfectly fine. Now my next step is to try this with a large dataset (Say, I have over 10 million records). Will the same approach works in that case ? P.S I have also updated my question with this constraint now.
          $endgroup$
          – Maddy
          2 days ago




          1




          1




          $begingroup$
          For that you could do the groupby only once, so before calling the funcction, and send it as an extra agument. Should be fast enough. Let me know :)
          $endgroup$
          – yatu
          20 hours ago




          $begingroup$
          For that you could do the groupby only once, so before calling the funcction, and send it as an extra agument. Should be fast enough. Let me know :)
          $endgroup$
          – yatu
          20 hours ago












          $begingroup$
          updated my question with the groupby approach !
          $endgroup$
          – Maddy
          5 mins ago




          $begingroup$
          updated my question with the groupby approach !
          $endgroup$
          – Maddy
          5 mins ago


















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