Construct a section (or slice) through 3D RegionsIntersection of a MeshRegion and InfinitePlaneUnnecessary...
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Construct a section (or slice) through 3D Regions
Intersection of a MeshRegion and InfinitePlaneUnnecessary and slow conversion between simple polygons and geometric regionsDraw filled regions in DateListPlotRegionPlot not plotting some regionsHandling Self-Intersecting RegionsHow to plot the difference between two regions?Trouble with discrete MeshRegions: Integrating over plane slicesUsing RegionIntersection on Regions formed by RegionUnionRegionIntersection of RegionsRegions, Mesh Regions, and GraphicsRegionUnion for 3D Regions
$begingroup$
I would like to draw a section through some 3D regions. I start by making some simple 3D regions as a minimum working example.
gg = BoundaryDiscretizeGraphics[
Graphics3D[#]] & /@ {Cuboid[{-0.2, -0.5, 0}, {0.2, 0.5, 0.5}],
Cone[{{1.5, 0, 0}, {2, 0, 2}}, 0.1] ,
Cylinder[{{2, 0, 1}, {3, 0, 0.5}}, 0.1], Sphere[{3, 0, 0}, 0.3],
Tube[{{0, 0, 0}, {4, 0, 3}}, 0.03]};
rr = RegionUnion[gg, Boxed -> True]

Now I define an InfinitePlane that I would like to slice through my regions.
ip = InfinitePlane[{{0, 0, 0}, {4, 0, 0}, {4, 0, 1}}];
Show[
Graphics3D[ip],
Region[rr]
]

How do I get the 2D Region lying in the plane? Is this possible?
This post has an approach for 3D primitives but I can't see how to extend this to 3D regions.
Edit
@kglr suggest I can go further with ClipPanes. Here is his suggestion.
rc = RegionPlot3D[rr, ClipPlanes -> ip,
ClipPlanesStyle -> Opacity[0.1, Green]]

This does the slicing and shows the insides but does not give me 2D regions. Could this be a starting point?
Edit 2
Continuing to take instructions from @kglr (see comments). He suggests finding the intersection with the mesh primitives.
dg = DiscretizeGraphics@
Quiet@Graphics3D[{DeleteCases[
RegionIntersection[ip, #] & /@
MeshPrimitives[rr,
2], _EmptyRegion | _Point | _RegionIntersection]}]

One can then extract the lines and reduce the coordinates to the values in the plane.
LL = MeshPrimitives[dg, 1] /. {a_, b_, c_} -> {a, c};
Graphics[LL]

This works. I will have to think further about what to do if the plane is not aligned with an axis. Reducing to 2D coordinates will then have to be done by a coordinate transform. However this is considerable progress and @kglr didn't have to post an answer!
regions
$endgroup$
add a comment |
$begingroup$
I would like to draw a section through some 3D regions. I start by making some simple 3D regions as a minimum working example.
gg = BoundaryDiscretizeGraphics[
Graphics3D[#]] & /@ {Cuboid[{-0.2, -0.5, 0}, {0.2, 0.5, 0.5}],
Cone[{{1.5, 0, 0}, {2, 0, 2}}, 0.1] ,
Cylinder[{{2, 0, 1}, {3, 0, 0.5}}, 0.1], Sphere[{3, 0, 0}, 0.3],
Tube[{{0, 0, 0}, {4, 0, 3}}, 0.03]};
rr = RegionUnion[gg, Boxed -> True]

Now I define an InfinitePlane that I would like to slice through my regions.
ip = InfinitePlane[{{0, 0, 0}, {4, 0, 0}, {4, 0, 1}}];
Show[
Graphics3D[ip],
Region[rr]
]

How do I get the 2D Region lying in the plane? Is this possible?
This post has an approach for 3D primitives but I can't see how to extend this to 3D regions.
Edit
@kglr suggest I can go further with ClipPanes. Here is his suggestion.
rc = RegionPlot3D[rr, ClipPlanes -> ip,
ClipPlanesStyle -> Opacity[0.1, Green]]

This does the slicing and shows the insides but does not give me 2D regions. Could this be a starting point?
Edit 2
Continuing to take instructions from @kglr (see comments). He suggests finding the intersection with the mesh primitives.
dg = DiscretizeGraphics@
Quiet@Graphics3D[{DeleteCases[
RegionIntersection[ip, #] & /@
MeshPrimitives[rr,
2], _EmptyRegion | _Point | _RegionIntersection]}]

One can then extract the lines and reduce the coordinates to the values in the plane.
LL = MeshPrimitives[dg, 1] /. {a_, b_, c_} -> {a, c};
Graphics[LL]

This works. I will have to think further about what to do if the plane is not aligned with an axis. Reducing to 2D coordinates will then have to be done by a coordinate transform. However this is considerable progress and @kglr didn't have to post an answer!
regions
$endgroup$
$begingroup$
maybeRegionPlot3D[rr, ClipPlanes -> ip, ClipPlanesStyle -> Opacity[.5, Red]]?
$endgroup$
– kglr
4 hours ago
$begingroup$
@kglr Thanks. This gives me a nice slice but how do I extract the lines on the plane and form regions?
$endgroup$
– Hugh
4 hours ago
$begingroup$
dg = DiscretizeGraphics@ Quiet@Graphics3D[{DeleteCases[ RegionIntersection[ip, #] & /@ MeshPrimitives[rr, 2], _EmptyRegion | _Point | _RegionIntersection]}]gives lines which can be further processed to form the polygons.
$endgroup$
– kglr
4 hours ago
add a comment |
$begingroup$
I would like to draw a section through some 3D regions. I start by making some simple 3D regions as a minimum working example.
gg = BoundaryDiscretizeGraphics[
Graphics3D[#]] & /@ {Cuboid[{-0.2, -0.5, 0}, {0.2, 0.5, 0.5}],
Cone[{{1.5, 0, 0}, {2, 0, 2}}, 0.1] ,
Cylinder[{{2, 0, 1}, {3, 0, 0.5}}, 0.1], Sphere[{3, 0, 0}, 0.3],
Tube[{{0, 0, 0}, {4, 0, 3}}, 0.03]};
rr = RegionUnion[gg, Boxed -> True]

Now I define an InfinitePlane that I would like to slice through my regions.
ip = InfinitePlane[{{0, 0, 0}, {4, 0, 0}, {4, 0, 1}}];
Show[
Graphics3D[ip],
Region[rr]
]

How do I get the 2D Region lying in the plane? Is this possible?
This post has an approach for 3D primitives but I can't see how to extend this to 3D regions.
Edit
@kglr suggest I can go further with ClipPanes. Here is his suggestion.
rc = RegionPlot3D[rr, ClipPlanes -> ip,
ClipPlanesStyle -> Opacity[0.1, Green]]

This does the slicing and shows the insides but does not give me 2D regions. Could this be a starting point?
Edit 2
Continuing to take instructions from @kglr (see comments). He suggests finding the intersection with the mesh primitives.
dg = DiscretizeGraphics@
Quiet@Graphics3D[{DeleteCases[
RegionIntersection[ip, #] & /@
MeshPrimitives[rr,
2], _EmptyRegion | _Point | _RegionIntersection]}]

One can then extract the lines and reduce the coordinates to the values in the plane.
LL = MeshPrimitives[dg, 1] /. {a_, b_, c_} -> {a, c};
Graphics[LL]

This works. I will have to think further about what to do if the plane is not aligned with an axis. Reducing to 2D coordinates will then have to be done by a coordinate transform. However this is considerable progress and @kglr didn't have to post an answer!
regions
$endgroup$
I would like to draw a section through some 3D regions. I start by making some simple 3D regions as a minimum working example.
gg = BoundaryDiscretizeGraphics[
Graphics3D[#]] & /@ {Cuboid[{-0.2, -0.5, 0}, {0.2, 0.5, 0.5}],
Cone[{{1.5, 0, 0}, {2, 0, 2}}, 0.1] ,
Cylinder[{{2, 0, 1}, {3, 0, 0.5}}, 0.1], Sphere[{3, 0, 0}, 0.3],
Tube[{{0, 0, 0}, {4, 0, 3}}, 0.03]};
rr = RegionUnion[gg, Boxed -> True]

Now I define an InfinitePlane that I would like to slice through my regions.
ip = InfinitePlane[{{0, 0, 0}, {4, 0, 0}, {4, 0, 1}}];
Show[
Graphics3D[ip],
Region[rr]
]

How do I get the 2D Region lying in the plane? Is this possible?
This post has an approach for 3D primitives but I can't see how to extend this to 3D regions.
Edit
@kglr suggest I can go further with ClipPanes. Here is his suggestion.
rc = RegionPlot3D[rr, ClipPlanes -> ip,
ClipPlanesStyle -> Opacity[0.1, Green]]

This does the slicing and shows the insides but does not give me 2D regions. Could this be a starting point?
Edit 2
Continuing to take instructions from @kglr (see comments). He suggests finding the intersection with the mesh primitives.
dg = DiscretizeGraphics@
Quiet@Graphics3D[{DeleteCases[
RegionIntersection[ip, #] & /@
MeshPrimitives[rr,
2], _EmptyRegion | _Point | _RegionIntersection]}]

One can then extract the lines and reduce the coordinates to the values in the plane.
LL = MeshPrimitives[dg, 1] /. {a_, b_, c_} -> {a, c};
Graphics[LL]

This works. I will have to think further about what to do if the plane is not aligned with an axis. Reducing to 2D coordinates will then have to be done by a coordinate transform. However this is considerable progress and @kglr didn't have to post an answer!
regions
regions
edited 3 hours ago
Hugh
asked 5 hours ago
HughHugh
6,39521945
6,39521945
$begingroup$
maybeRegionPlot3D[rr, ClipPlanes -> ip, ClipPlanesStyle -> Opacity[.5, Red]]?
$endgroup$
– kglr
4 hours ago
$begingroup$
@kglr Thanks. This gives me a nice slice but how do I extract the lines on the plane and form regions?
$endgroup$
– Hugh
4 hours ago
$begingroup$
dg = DiscretizeGraphics@ Quiet@Graphics3D[{DeleteCases[ RegionIntersection[ip, #] & /@ MeshPrimitives[rr, 2], _EmptyRegion | _Point | _RegionIntersection]}]gives lines which can be further processed to form the polygons.
$endgroup$
– kglr
4 hours ago
add a comment |
$begingroup$
maybeRegionPlot3D[rr, ClipPlanes -> ip, ClipPlanesStyle -> Opacity[.5, Red]]?
$endgroup$
– kglr
4 hours ago
$begingroup$
@kglr Thanks. This gives me a nice slice but how do I extract the lines on the plane and form regions?
$endgroup$
– Hugh
4 hours ago
$begingroup$
dg = DiscretizeGraphics@ Quiet@Graphics3D[{DeleteCases[ RegionIntersection[ip, #] & /@ MeshPrimitives[rr, 2], _EmptyRegion | _Point | _RegionIntersection]}]gives lines which can be further processed to form the polygons.
$endgroup$
– kglr
4 hours ago
$begingroup$
maybe
RegionPlot3D[rr, ClipPlanes -> ip, ClipPlanesStyle -> Opacity[.5, Red]]?$endgroup$
– kglr
4 hours ago
$begingroup$
maybe
RegionPlot3D[rr, ClipPlanes -> ip, ClipPlanesStyle -> Opacity[.5, Red]]?$endgroup$
– kglr
4 hours ago
$begingroup$
@kglr Thanks. This gives me a nice slice but how do I extract the lines on the plane and form regions?
$endgroup$
– Hugh
4 hours ago
$begingroup$
@kglr Thanks. This gives me a nice slice but how do I extract the lines on the plane and form regions?
$endgroup$
– Hugh
4 hours ago
$begingroup$
dg = DiscretizeGraphics@ Quiet@Graphics3D[{DeleteCases[ RegionIntersection[ip, #] & /@ MeshPrimitives[rr, 2], _EmptyRegion | _Point | _RegionIntersection]}] gives lines which can be further processed to form the polygons.$endgroup$
– kglr
4 hours ago
$begingroup$
dg = DiscretizeGraphics@ Quiet@Graphics3D[{DeleteCases[ RegionIntersection[ip, #] & /@ MeshPrimitives[rr, 2], _EmptyRegion | _Point | _RegionIntersection]}] gives lines which can be further processed to form the polygons.$endgroup$
– kglr
4 hours ago
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Note that RegionIntersection[rr, ip] should give you what you want here but doesn't.
Since we have an axes aligned plane, we can workaround this by exploiting the second argument of DiscretizeRegion:
cut = DiscretizeRegion[RegionBoundary[rr], {{-0.2`, 4.1`}, {-0.5`, 0}, {-0.3`, 3.1`}}];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

We can easily project to 2d as well:
BoundaryMeshRegion[MeshCoordinates[cut][[All, {1, 3}]], holes]

We can adapt this idea to any plane. I'll use HalfSpace to emphasize which side of the plane is kept.
halfSpaceClip[reg_, ___] /; !MeshRegionQ[reg] && !BoundaryMeshRegionQ[reg] && RegionEmbeddingDimension[reg] != 3 = $Failed;
halfSpaceClip[mr_, h_HalfSpace] /; RegionWithin[h, mr] := mr
halfSpaceClip[mr_, HalfSpace[n_, p_]] /; RegionWithin[HalfSpace[-n, p], mr] = EmptyRegion[3];
halfSpaceClip[mr_, HalfSpace[n_, p_]] :=
Block[{rt, rot, bds, clip},
rt = RotationTransform[{n, {0, 0, -1}}, p];
rot = TransformedRegion[mr, rt];
bds = RegionBounds[rot];
clip = DiscretizeRegion[rot, {#1+5{-1,1}, #2+5{-1,1}, {p[[3]], #3[[2]]+5}}]& @@ bds;
InverseTransformedRegion[clip, rt]
]
halfSpaceClip[___] = $Failed;
The same example:
cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{0, 1, 0}, {0, 0, 0}]];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

A non axes aligned plane:
cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{.5, 1, -1}, {0, .5, .5}]];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

$endgroup$
$begingroup$
Thanks. This works. How do you deal with a plane not aligned with the axis? Is a coordinate transformation of the axis is needed?
$endgroup$
– Hugh
3 hours ago
$begingroup$
@Hugh Yes that is one way. See my latest edit.
$endgroup$
– Chip Hurst
3 hours ago
$begingroup$
Excellent many thanks.
$endgroup$
– Hugh
3 hours ago
add a comment |
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$begingroup$
Note that RegionIntersection[rr, ip] should give you what you want here but doesn't.
Since we have an axes aligned plane, we can workaround this by exploiting the second argument of DiscretizeRegion:
cut = DiscretizeRegion[RegionBoundary[rr], {{-0.2`, 4.1`}, {-0.5`, 0}, {-0.3`, 3.1`}}];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

We can easily project to 2d as well:
BoundaryMeshRegion[MeshCoordinates[cut][[All, {1, 3}]], holes]

We can adapt this idea to any plane. I'll use HalfSpace to emphasize which side of the plane is kept.
halfSpaceClip[reg_, ___] /; !MeshRegionQ[reg] && !BoundaryMeshRegionQ[reg] && RegionEmbeddingDimension[reg] != 3 = $Failed;
halfSpaceClip[mr_, h_HalfSpace] /; RegionWithin[h, mr] := mr
halfSpaceClip[mr_, HalfSpace[n_, p_]] /; RegionWithin[HalfSpace[-n, p], mr] = EmptyRegion[3];
halfSpaceClip[mr_, HalfSpace[n_, p_]] :=
Block[{rt, rot, bds, clip},
rt = RotationTransform[{n, {0, 0, -1}}, p];
rot = TransformedRegion[mr, rt];
bds = RegionBounds[rot];
clip = DiscretizeRegion[rot, {#1+5{-1,1}, #2+5{-1,1}, {p[[3]], #3[[2]]+5}}]& @@ bds;
InverseTransformedRegion[clip, rt]
]
halfSpaceClip[___] = $Failed;
The same example:
cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{0, 1, 0}, {0, 0, 0}]];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

A non axes aligned plane:
cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{.5, 1, -1}, {0, .5, .5}]];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

$endgroup$
$begingroup$
Thanks. This works. How do you deal with a plane not aligned with the axis? Is a coordinate transformation of the axis is needed?
$endgroup$
– Hugh
3 hours ago
$begingroup$
@Hugh Yes that is one way. See my latest edit.
$endgroup$
– Chip Hurst
3 hours ago
$begingroup$
Excellent many thanks.
$endgroup$
– Hugh
3 hours ago
add a comment |
$begingroup$
Note that RegionIntersection[rr, ip] should give you what you want here but doesn't.
Since we have an axes aligned plane, we can workaround this by exploiting the second argument of DiscretizeRegion:
cut = DiscretizeRegion[RegionBoundary[rr], {{-0.2`, 4.1`}, {-0.5`, 0}, {-0.3`, 3.1`}}];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

We can easily project to 2d as well:
BoundaryMeshRegion[MeshCoordinates[cut][[All, {1, 3}]], holes]

We can adapt this idea to any plane. I'll use HalfSpace to emphasize which side of the plane is kept.
halfSpaceClip[reg_, ___] /; !MeshRegionQ[reg] && !BoundaryMeshRegionQ[reg] && RegionEmbeddingDimension[reg] != 3 = $Failed;
halfSpaceClip[mr_, h_HalfSpace] /; RegionWithin[h, mr] := mr
halfSpaceClip[mr_, HalfSpace[n_, p_]] /; RegionWithin[HalfSpace[-n, p], mr] = EmptyRegion[3];
halfSpaceClip[mr_, HalfSpace[n_, p_]] :=
Block[{rt, rot, bds, clip},
rt = RotationTransform[{n, {0, 0, -1}}, p];
rot = TransformedRegion[mr, rt];
bds = RegionBounds[rot];
clip = DiscretizeRegion[rot, {#1+5{-1,1}, #2+5{-1,1}, {p[[3]], #3[[2]]+5}}]& @@ bds;
InverseTransformedRegion[clip, rt]
]
halfSpaceClip[___] = $Failed;
The same example:
cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{0, 1, 0}, {0, 0, 0}]];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

A non axes aligned plane:
cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{.5, 1, -1}, {0, .5, .5}]];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

$endgroup$
$begingroup$
Thanks. This works. How do you deal with a plane not aligned with the axis? Is a coordinate transformation of the axis is needed?
$endgroup$
– Hugh
3 hours ago
$begingroup$
@Hugh Yes that is one way. See my latest edit.
$endgroup$
– Chip Hurst
3 hours ago
$begingroup$
Excellent many thanks.
$endgroup$
– Hugh
3 hours ago
add a comment |
$begingroup$
Note that RegionIntersection[rr, ip] should give you what you want here but doesn't.
Since we have an axes aligned plane, we can workaround this by exploiting the second argument of DiscretizeRegion:
cut = DiscretizeRegion[RegionBoundary[rr], {{-0.2`, 4.1`}, {-0.5`, 0}, {-0.3`, 3.1`}}];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

We can easily project to 2d as well:
BoundaryMeshRegion[MeshCoordinates[cut][[All, {1, 3}]], holes]

We can adapt this idea to any plane. I'll use HalfSpace to emphasize which side of the plane is kept.
halfSpaceClip[reg_, ___] /; !MeshRegionQ[reg] && !BoundaryMeshRegionQ[reg] && RegionEmbeddingDimension[reg] != 3 = $Failed;
halfSpaceClip[mr_, h_HalfSpace] /; RegionWithin[h, mr] := mr
halfSpaceClip[mr_, HalfSpace[n_, p_]] /; RegionWithin[HalfSpace[-n, p], mr] = EmptyRegion[3];
halfSpaceClip[mr_, HalfSpace[n_, p_]] :=
Block[{rt, rot, bds, clip},
rt = RotationTransform[{n, {0, 0, -1}}, p];
rot = TransformedRegion[mr, rt];
bds = RegionBounds[rot];
clip = DiscretizeRegion[rot, {#1+5{-1,1}, #2+5{-1,1}, {p[[3]], #3[[2]]+5}}]& @@ bds;
InverseTransformedRegion[clip, rt]
]
halfSpaceClip[___] = $Failed;
The same example:
cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{0, 1, 0}, {0, 0, 0}]];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

A non axes aligned plane:
cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{.5, 1, -1}, {0, .5, .5}]];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

$endgroup$
Note that RegionIntersection[rr, ip] should give you what you want here but doesn't.
Since we have an axes aligned plane, we can workaround this by exploiting the second argument of DiscretizeRegion:
cut = DiscretizeRegion[RegionBoundary[rr], {{-0.2`, 4.1`}, {-0.5`, 0}, {-0.3`, 3.1`}}];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

We can easily project to 2d as well:
BoundaryMeshRegion[MeshCoordinates[cut][[All, {1, 3}]], holes]

We can adapt this idea to any plane. I'll use HalfSpace to emphasize which side of the plane is kept.
halfSpaceClip[reg_, ___] /; !MeshRegionQ[reg] && !BoundaryMeshRegionQ[reg] && RegionEmbeddingDimension[reg] != 3 = $Failed;
halfSpaceClip[mr_, h_HalfSpace] /; RegionWithin[h, mr] := mr
halfSpaceClip[mr_, HalfSpace[n_, p_]] /; RegionWithin[HalfSpace[-n, p], mr] = EmptyRegion[3];
halfSpaceClip[mr_, HalfSpace[n_, p_]] :=
Block[{rt, rot, bds, clip},
rt = RotationTransform[{n, {0, 0, -1}}, p];
rot = TransformedRegion[mr, rt];
bds = RegionBounds[rot];
clip = DiscretizeRegion[rot, {#1+5{-1,1}, #2+5{-1,1}, {p[[3]], #3[[2]]+5}}]& @@ bds;
InverseTransformedRegion[clip, rt]
]
halfSpaceClip[___] = $Failed;
The same example:
cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{0, 1, 0}, {0, 0, 0}]];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

A non axes aligned plane:
cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{.5, 1, -1}, {0, .5, .5}]];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

edited 3 hours ago
answered 4 hours ago
Chip HurstChip Hurst
21.8k15790
21.8k15790
$begingroup$
Thanks. This works. How do you deal with a plane not aligned with the axis? Is a coordinate transformation of the axis is needed?
$endgroup$
– Hugh
3 hours ago
$begingroup$
@Hugh Yes that is one way. See my latest edit.
$endgroup$
– Chip Hurst
3 hours ago
$begingroup$
Excellent many thanks.
$endgroup$
– Hugh
3 hours ago
add a comment |
$begingroup$
Thanks. This works. How do you deal with a plane not aligned with the axis? Is a coordinate transformation of the axis is needed?
$endgroup$
– Hugh
3 hours ago
$begingroup$
@Hugh Yes that is one way. See my latest edit.
$endgroup$
– Chip Hurst
3 hours ago
$begingroup$
Excellent many thanks.
$endgroup$
– Hugh
3 hours ago
$begingroup$
Thanks. This works. How do you deal with a plane not aligned with the axis? Is a coordinate transformation of the axis is needed?
$endgroup$
– Hugh
3 hours ago
$begingroup$
Thanks. This works. How do you deal with a plane not aligned with the axis? Is a coordinate transformation of the axis is needed?
$endgroup$
– Hugh
3 hours ago
$begingroup$
@Hugh Yes that is one way. See my latest edit.
$endgroup$
– Chip Hurst
3 hours ago
$begingroup$
@Hugh Yes that is one way. See my latest edit.
$endgroup$
– Chip Hurst
3 hours ago
$begingroup$
Excellent many thanks.
$endgroup$
– Hugh
3 hours ago
$begingroup$
Excellent many thanks.
$endgroup$
– Hugh
3 hours ago
add a comment |
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$begingroup$
maybe
RegionPlot3D[rr, ClipPlanes -> ip, ClipPlanesStyle -> Opacity[.5, Red]]?$endgroup$
– kglr
4 hours ago
$begingroup$
@kglr Thanks. This gives me a nice slice but how do I extract the lines on the plane and form regions?
$endgroup$
– Hugh
4 hours ago
$begingroup$
dg = DiscretizeGraphics@ Quiet@Graphics3D[{DeleteCases[ RegionIntersection[ip, #] & /@ MeshPrimitives[rr, 2], _EmptyRegion | _Point | _RegionIntersection]}]gives lines which can be further processed to form the polygons.$endgroup$
– kglr
4 hours ago