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I want to color a graph

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2

1

Im very new to making latex so all the tutorials I have found about my question were too hard to understand or didn't do exactly what I wanted.

I already have the graph I want without the coloring:

begin{figure}

centering

begin{tikzpicture}

      draw[->] (-2,0) -- (2,0) node[right] {$x$};

      draw[->] (0,-2) -- (0,2) node[above] {$y$};

     draw[scale=0.4,domain=-1.71:1.71,smooth,variable=x,black] plot ({x},{(x)^3});



      end{tikzpicture}

end{figure}

tikz-pgf

share|improve this question

asked 7 hours ago

HansHans

132

New contributor

Hans is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  (written without compiling) fill [green] (-2,0) plot [domain=0:1.26] (x,x^3) |- cycle;
  
  – Symbol 1
  7 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Oh i didnt know it was that easy! It looks good, but because of the scale=0.4, the green area isnt correctly under the graph. How to i re-scale the green area?
  
  – Hans
  7 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I figured it out! i just added it in the square brackets: fill [green, scale=0.4] (-2,2) plot [domain=0:0.5] (x,x^3) |- cycle;
  
  – Hans
  7 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  But how do I color even farther out to the right like I drew on the paper? And how to color the other four areas?
  
  – Hans
  7 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Either you specify coordinates carefully (e.g. 1.26 in my code in cubic root of 2) or use clip
  
  – Symbol 1
  7 hours ago
  
  
  

  
  
  
  

 | 
show 1 more comment

2

1

Im very new to making latex so all the tutorials I have found about my question were too hard to understand or didn't do exactly what I wanted.

I already have the graph I want without the coloring:

begin{figure}

centering

begin{tikzpicture}

      draw[->] (-2,0) -- (2,0) node[right] {$x$};

      draw[->] (0,-2) -- (0,2) node[above] {$y$};

     draw[scale=0.4,domain=-1.71:1.71,smooth,variable=x,black] plot ({x},{(x)^3});



      end{tikzpicture}

end{figure}

tikz-pgf

share|improve this question

asked 7 hours ago

HansHans

132

New contributor

Hans is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  (written without compiling) fill [green] (-2,0) plot [domain=0:1.26] (x,x^3) |- cycle;
  
  – Symbol 1
  7 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Oh i didnt know it was that easy! It looks good, but because of the scale=0.4, the green area isnt correctly under the graph. How to i re-scale the green area?
  
  – Hans
  7 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I figured it out! i just added it in the square brackets: fill [green, scale=0.4] (-2,2) plot [domain=0:0.5] (x,x^3) |- cycle;
  
  – Hans
  7 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  But how do I color even farther out to the right like I drew on the paper? And how to color the other four areas?
  
  – Hans
  7 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Either you specify coordinates carefully (e.g. 1.26 in my code in cubic root of 2) or use clip
  
  – Symbol 1
  7 hours ago
  
  
  

  
  
  
  

 | 
show 1 more comment

Im very new to making latex so all the tutorials I have found about my question were too hard to understand or didn't do exactly what I wanted.

I already have the graph I want without the coloring:

begin{figure}

centering

begin{tikzpicture}

      draw[->] (-2,0) -- (2,0) node[right] {$x$};

      draw[->] (0,-2) -- (0,2) node[above] {$y$};

     draw[scale=0.4,domain=-1.71:1.71,smooth,variable=x,black] plot ({x},{(x)^3});



      end{tikzpicture}

end{figure}

tikz-pgf

share|improve this question

asked 7 hours ago

HansHans

132

New contributor

Hans is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

begin{figure}

centering

begin{tikzpicture}

      draw[->] (-2,0) -- (2,0) node[right] {$x$};

      draw[->] (0,-2) -- (0,2) node[above] {$y$};

     draw[scale=0.4,domain=-1.71:1.71,smooth,variable=x,black] plot ({x},{(x)^3});



      end{tikzpicture}

end{figure}

share|improve this question

asked 7 hours ago

HansHans

132

New contributor

Hans is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

asked 7 hours ago

HansHans

132

New contributor

Hans is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 7 hours ago

HansHans

132

New contributor

Hans is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 7 hours ago

HansHans

132

3 Answers
3

active

oldest

votes

3

A tricky way:

documentclass[tikz,margin=3mm]{standalone}

begin{document}

begin{tikzpicture}

fill[blue!20] (-2,-2) rectangle (2,2);

fill[green!50] (0,0)--({-1.71*0.4},{0.4*(-1.71^3)})--(2,-2)--(2,0)--cycle;

fill[green!50] (0,0)--({1.71*0.4},{0.4*(1.71^3)})--(-2,2)--(-2,0)--cycle;

draw[->] (-2,0) -- (2,0) node[right] {$x$};

draw[->] (0,-2) -- (0,2) node[above] {$y$};

draw[scale=0.4,domain=-1.71:1.71,smooth,variable=x,black,fill=green!50] plot ({x},{(x)^3});

end{tikzpicture}

end{document}

share|improve this answer

answered 7 hours ago

JouleVJouleV

4,3251938

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  We see a line that joins the two ends of the curve.
  
  – AndréC
  6 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  That looks exactly like i want it! But is there any way to get around that slightly visible dark-green line that goes from (1.71*0.4, 0.4*(1.71^3)) to (-1.71*0.4,0.4*(-1.71^3))?
  
  – Hans
  6 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Hans See my answer, I have removed the slight line with a different filling technique.
  
  – quark67
  2 hours ago
  

  
  
  
  

add a comment | 

4

Here is my suggestion, without slightly line, because the filling is made differently (code modified from AndréC answer):

documentclass[tikz,border=5mm]{standalone}

begin{document}

begin{tikzpicture}



begin{scope}

    clip[postaction={fill=green!50}] (-2,-2) rectangle (2,2);

    fill[scale=0.4,domain=0:5,smooth,variable=x,blue!20] plot ({x},{(x)^3}) |-(0,0);

    fill[scale=0.4,domain=0:-5,smooth,variable=x,blue!20] plot ({x},{(x)^3}) |-(0,0);

    draw[scale=0.4,domain=-1.71:1.71,smooth,variable=x,black] plot ({x},{(x)^3});

end{scope}



draw[->] (-2,0) -- (2,0) node[right] {$x$};

draw[->] (0,-2) -- (0,2) node[above] {$y$};

end{tikzpicture}

end{document}

(Code edited with marmot's useful suggestion: using postaction to reduce redundant code.)

share|improve this answer

edited 52 mins ago

answered 2 hours ago

quark67quark67

16915

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @marmot Thanks, I have edited with your great advice.
  
  – quark67
  51 mins ago
  

  
  
  
  

add a comment | 

1

With pgfplots, this is easy to do.

Here is a pure tikz DIY without a single piece of pgfplots!

documentclass[tikz,border=5mm]{standalone}



 begin{document}



begin{tikzpicture}

fill[blue!20] (-2,-2)rectangle(2,2);

begin{scope}[transparency group,opacity=.9]   

fill[scale=0.4,domain=0:1.71,smooth,variable=x,green] plot ({x},{(x)^3})coordinate(a)|-(0,0)node[midway](m){};

fill[green](a)--(2,2)|-(m.center);

fill[scale=0.4,domain=0:-1.71,smooth,variable=x,green] plot ({x},{(x)^3})coordinate(b)|-(0,0)node[midway](n){};

fill[green](b)--(-2,-2)|-(n.center);

end{scope}

draw[scale=0.4,domain=-1.71:1.71,smooth,variable=x,black] plot ({x},{(x)^3});

draw[->] (-2,0) -- (2,0) node[right] {$x$};

draw[->] (0,-2) -- (0,2) node[above] {$y$};

end{tikzpicture}

end{document}

share|improve this answer

edited 1 hour ago

answered 5 hours ago

AndréCAndréC

9,44111447

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  There is a slight vertical line in your screenshot (at x=-1.71) because you fill this lower left domain with 2 areas (there is also a slight vertical line at x=+1.71 in the upper right domain, but not visible in your screenshot).
  
  – quark67
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You have a much better view than I do. I have just created a transparency group, normally this little net should have disappeared.
  
  – AndréC
  1 hour ago
  
  
  

  
  
  
  

add a comment | 

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3

A tricky way:

documentclass[tikz,margin=3mm]{standalone}

begin{document}

begin{tikzpicture}

fill[blue!20] (-2,-2) rectangle (2,2);

fill[green!50] (0,0)--({-1.71*0.4},{0.4*(-1.71^3)})--(2,-2)--(2,0)--cycle;

fill[green!50] (0,0)--({1.71*0.4},{0.4*(1.71^3)})--(-2,2)--(-2,0)--cycle;

draw[->] (-2,0) -- (2,0) node[right] {$x$};

draw[->] (0,-2) -- (0,2) node[above] {$y$};

draw[scale=0.4,domain=-1.71:1.71,smooth,variable=x,black,fill=green!50] plot ({x},{(x)^3});

end{tikzpicture}

end{document}

share|improve this answer

answered 7 hours ago

JouleVJouleV

4,3251938

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  We see a line that joins the two ends of the curve.
  
  – AndréC
  6 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  That looks exactly like i want it! But is there any way to get around that slightly visible dark-green line that goes from (1.71*0.4, 0.4*(1.71^3)) to (-1.71*0.4,0.4*(-1.71^3))?
  
  – Hans
  6 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Hans See my answer, I have removed the slight line with a different filling technique.
  
  – quark67
  2 hours ago
  

  
  
  
  

add a comment | 

3

A tricky way:

documentclass[tikz,margin=3mm]{standalone}

begin{document}

begin{tikzpicture}

fill[blue!20] (-2,-2) rectangle (2,2);

fill[green!50] (0,0)--({-1.71*0.4},{0.4*(-1.71^3)})--(2,-2)--(2,0)--cycle;

fill[green!50] (0,0)--({1.71*0.4},{0.4*(1.71^3)})--(-2,2)--(-2,0)--cycle;

draw[->] (-2,0) -- (2,0) node[right] {$x$};

draw[->] (0,-2) -- (0,2) node[above] {$y$};

draw[scale=0.4,domain=-1.71:1.71,smooth,variable=x,black,fill=green!50] plot ({x},{(x)^3});

end{tikzpicture}

end{document}

share|improve this answer

answered 7 hours ago

JouleVJouleV

4,3251938

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  We see a line that joins the two ends of the curve.
  
  – AndréC
  6 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  That looks exactly like i want it! But is there any way to get around that slightly visible dark-green line that goes from (1.71*0.4, 0.4*(1.71^3)) to (-1.71*0.4,0.4*(-1.71^3))?
  
  – Hans
  6 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Hans See my answer, I have removed the slight line with a different filling technique.
  
  – quark67
  2 hours ago
  

  
  
  
  

add a comment | 

A tricky way:

documentclass[tikz,margin=3mm]{standalone}

begin{document}

begin{tikzpicture}

fill[blue!20] (-2,-2) rectangle (2,2);

fill[green!50] (0,0)--({-1.71*0.4},{0.4*(-1.71^3)})--(2,-2)--(2,0)--cycle;

fill[green!50] (0,0)--({1.71*0.4},{0.4*(1.71^3)})--(-2,2)--(-2,0)--cycle;

draw[->] (-2,0) -- (2,0) node[right] {$x$};

draw[->] (0,-2) -- (0,2) node[above] {$y$};

draw[scale=0.4,domain=-1.71:1.71,smooth,variable=x,black,fill=green!50] plot ({x},{(x)^3});

end{tikzpicture}

end{document}

share|improve this answer

answered 7 hours ago

JouleVJouleV

4,3251938

documentclass[tikz,margin=3mm]{standalone}

begin{document}

begin{tikzpicture}

fill[blue!20] (-2,-2) rectangle (2,2);

fill[green!50] (0,0)--({-1.71*0.4},{0.4*(-1.71^3)})--(2,-2)--(2,0)--cycle;

fill[green!50] (0,0)--({1.71*0.4},{0.4*(1.71^3)})--(-2,2)--(-2,0)--cycle;

draw[->] (-2,0) -- (2,0) node[right] {$x$};

draw[->] (0,-2) -- (0,2) node[above] {$y$};

draw[scale=0.4,domain=-1.71:1.71,smooth,variable=x,black,fill=green!50] plot ({x},{(x)^3});

end{tikzpicture}

end{document}

share|improve this answer

answered 7 hours ago

JouleVJouleV

4,3251938

answered 7 hours ago

JouleVJouleV

4,3251938

answered 7 hours ago

JouleVJouleV

4,3251938

4

Here is my suggestion, without slightly line, because the filling is made differently (code modified from AndréC answer):

documentclass[tikz,border=5mm]{standalone}

begin{document}

begin{tikzpicture}



begin{scope}

    clip[postaction={fill=green!50}] (-2,-2) rectangle (2,2);

    fill[scale=0.4,domain=0:5,smooth,variable=x,blue!20] plot ({x},{(x)^3}) |-(0,0);

    fill[scale=0.4,domain=0:-5,smooth,variable=x,blue!20] plot ({x},{(x)^3}) |-(0,0);

    draw[scale=0.4,domain=-1.71:1.71,smooth,variable=x,black] plot ({x},{(x)^3});

end{scope}



draw[->] (-2,0) -- (2,0) node[right] {$x$};

draw[->] (0,-2) -- (0,2) node[above] {$y$};

end{tikzpicture}

end{document}

(Code edited with marmot's useful suggestion: using postaction to reduce redundant code.)

share|improve this answer

edited 52 mins ago

answered 2 hours ago

quark67quark67

16915

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @marmot Thanks, I have edited with your great advice.
  
  – quark67
  51 mins ago
  

  
  
  
  

add a comment | 

4

Here is my suggestion, without slightly line, because the filling is made differently (code modified from AndréC answer):

documentclass[tikz,border=5mm]{standalone}

begin{document}

begin{tikzpicture}



begin{scope}

    clip[postaction={fill=green!50}] (-2,-2) rectangle (2,2);

    fill[scale=0.4,domain=0:5,smooth,variable=x,blue!20] plot ({x},{(x)^3}) |-(0,0);

    fill[scale=0.4,domain=0:-5,smooth,variable=x,blue!20] plot ({x},{(x)^3}) |-(0,0);

    draw[scale=0.4,domain=-1.71:1.71,smooth,variable=x,black] plot ({x},{(x)^3});

end{scope}



draw[->] (-2,0) -- (2,0) node[right] {$x$};

draw[->] (0,-2) -- (0,2) node[above] {$y$};

end{tikzpicture}

end{document}

(Code edited with marmot's useful suggestion: using postaction to reduce redundant code.)

share|improve this answer

edited 52 mins ago

answered 2 hours ago

quark67quark67

16915

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @marmot Thanks, I have edited with your great advice.
  
  – quark67
  51 mins ago
  

  
  
  
  

add a comment | 

Here is my suggestion, without slightly line, because the filling is made differently (code modified from AndréC answer):

documentclass[tikz,border=5mm]{standalone}

begin{document}

begin{tikzpicture}



begin{scope}

    clip[postaction={fill=green!50}] (-2,-2) rectangle (2,2);

    fill[scale=0.4,domain=0:5,smooth,variable=x,blue!20] plot ({x},{(x)^3}) |-(0,0);

    fill[scale=0.4,domain=0:-5,smooth,variable=x,blue!20] plot ({x},{(x)^3}) |-(0,0);

    draw[scale=0.4,domain=-1.71:1.71,smooth,variable=x,black] plot ({x},{(x)^3});

end{scope}



draw[->] (-2,0) -- (2,0) node[right] {$x$};

draw[->] (0,-2) -- (0,2) node[above] {$y$};

end{tikzpicture}

end{document}

(Code edited with marmot's useful suggestion: using postaction to reduce redundant code.)

share|improve this answer

edited 52 mins ago

answered 2 hours ago

quark67quark67

16915

documentclass[tikz,border=5mm]{standalone}

begin{document}

begin{tikzpicture}



begin{scope}

    clip[postaction={fill=green!50}] (-2,-2) rectangle (2,2);

    fill[scale=0.4,domain=0:5,smooth,variable=x,blue!20] plot ({x},{(x)^3}) |-(0,0);

    fill[scale=0.4,domain=0:-5,smooth,variable=x,blue!20] plot ({x},{(x)^3}) |-(0,0);

    draw[scale=0.4,domain=-1.71:1.71,smooth,variable=x,black] plot ({x},{(x)^3});

end{scope}



draw[->] (-2,0) -- (2,0) node[right] {$x$};

draw[->] (0,-2) -- (0,2) node[above] {$y$};

end{tikzpicture}

end{document}

share|improve this answer

edited 52 mins ago

answered 2 hours ago

quark67quark67

16915

answered 2 hours ago

quark67quark67

16915

answered 2 hours ago

quark67quark67

16915

1

With pgfplots, this is easy to do.

Here is a pure tikz DIY without a single piece of pgfplots!

documentclass[tikz,border=5mm]{standalone}



 begin{document}



begin{tikzpicture}

fill[blue!20] (-2,-2)rectangle(2,2);

begin{scope}[transparency group,opacity=.9]   

fill[scale=0.4,domain=0:1.71,smooth,variable=x,green] plot ({x},{(x)^3})coordinate(a)|-(0,0)node[midway](m){};

fill[green](a)--(2,2)|-(m.center);

fill[scale=0.4,domain=0:-1.71,smooth,variable=x,green] plot ({x},{(x)^3})coordinate(b)|-(0,0)node[midway](n){};

fill[green](b)--(-2,-2)|-(n.center);

end{scope}

draw[scale=0.4,domain=-1.71:1.71,smooth,variable=x,black] plot ({x},{(x)^3});

draw[->] (-2,0) -- (2,0) node[right] {$x$};

draw[->] (0,-2) -- (0,2) node[above] {$y$};

end{tikzpicture}

end{document}

share|improve this answer

edited 1 hour ago

answered 5 hours ago

AndréCAndréC

9,44111447

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  There is a slight vertical line in your screenshot (at x=-1.71) because you fill this lower left domain with 2 areas (there is also a slight vertical line at x=+1.71 in the upper right domain, but not visible in your screenshot).
  
  – quark67
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You have a much better view than I do. I have just created a transparency group, normally this little net should have disappeared.
  
  – AndréC
  1 hour ago
  
  
  

  
  
  
  

add a comment | 

1

With pgfplots, this is easy to do.

Here is a pure tikz DIY without a single piece of pgfplots!

documentclass[tikz,border=5mm]{standalone}



 begin{document}



begin{tikzpicture}

fill[blue!20] (-2,-2)rectangle(2,2);

begin{scope}[transparency group,opacity=.9]   

fill[scale=0.4,domain=0:1.71,smooth,variable=x,green] plot ({x},{(x)^3})coordinate(a)|-(0,0)node[midway](m){};

fill[green](a)--(2,2)|-(m.center);

fill[scale=0.4,domain=0:-1.71,smooth,variable=x,green] plot ({x},{(x)^3})coordinate(b)|-(0,0)node[midway](n){};

fill[green](b)--(-2,-2)|-(n.center);

end{scope}

draw[scale=0.4,domain=-1.71:1.71,smooth,variable=x,black] plot ({x},{(x)^3});

draw[->] (-2,0) -- (2,0) node[right] {$x$};

draw[->] (0,-2) -- (0,2) node[above] {$y$};

end{tikzpicture}

end{document}

share|improve this answer

edited 1 hour ago

answered 5 hours ago

AndréCAndréC

9,44111447

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  There is a slight vertical line in your screenshot (at x=-1.71) because you fill this lower left domain with 2 areas (there is also a slight vertical line at x=+1.71 in the upper right domain, but not visible in your screenshot).
  
  – quark67
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You have a much better view than I do. I have just created a transparency group, normally this little net should have disappeared.
  
  – AndréC
  1 hour ago
  
  
  

  
  
  
  

add a comment | 

With pgfplots, this is easy to do.

Here is a pure tikz DIY without a single piece of pgfplots!

documentclass[tikz,border=5mm]{standalone}



 begin{document}



begin{tikzpicture}

fill[blue!20] (-2,-2)rectangle(2,2);

begin{scope}[transparency group,opacity=.9]   

fill[scale=0.4,domain=0:1.71,smooth,variable=x,green] plot ({x},{(x)^3})coordinate(a)|-(0,0)node[midway](m){};

fill[green](a)--(2,2)|-(m.center);

fill[scale=0.4,domain=0:-1.71,smooth,variable=x,green] plot ({x},{(x)^3})coordinate(b)|-(0,0)node[midway](n){};

fill[green](b)--(-2,-2)|-(n.center);

end{scope}

draw[scale=0.4,domain=-1.71:1.71,smooth,variable=x,black] plot ({x},{(x)^3});

draw[->] (-2,0) -- (2,0) node[right] {$x$};

draw[->] (0,-2) -- (0,2) node[above] {$y$};

end{tikzpicture}

end{document}

share|improve this answer

edited 1 hour ago

answered 5 hours ago

AndréCAndréC

9,44111447

documentclass[tikz,border=5mm]{standalone}



 begin{document}



begin{tikzpicture}

fill[blue!20] (-2,-2)rectangle(2,2);

begin{scope}[transparency group,opacity=.9]   

fill[scale=0.4,domain=0:1.71,smooth,variable=x,green] plot ({x},{(x)^3})coordinate(a)|-(0,0)node[midway](m){};

fill[green](a)--(2,2)|-(m.center);

fill[scale=0.4,domain=0:-1.71,smooth,variable=x,green] plot ({x},{(x)^3})coordinate(b)|-(0,0)node[midway](n){};

fill[green](b)--(-2,-2)|-(n.center);

end{scope}

draw[scale=0.4,domain=-1.71:1.71,smooth,variable=x,black] plot ({x},{(x)^3});

draw[->] (-2,0) -- (2,0) node[right] {$x$};

draw[->] (0,-2) -- (0,2) node[above] {$y$};

end{tikzpicture}

end{document}

share|improve this answer

edited 1 hour ago

answered 5 hours ago

AndréCAndréC

9,44111447

answered 5 hours ago

AndréCAndréC

9,44111447

answered 5 hours ago

AndréCAndréC

9,44111447