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What would the chemical name be for C13H8Cl3NO

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What would the chemical name be for C13H8Cl3NO

How would you name this organic compound?What is the rationale of the IUPAC name for DDT?What would the name and formula be for Mo+O+Se?Chemical name : MelamineWhat would the name of this organic compound be?What is the chemical name of the compound H2S4O?What is the iupac name for ch3ch2cooag?What is the chemical name of this derivative of aniline?IUPAC Name for the following?What would be the name of this compound?

2

$begingroup$

Formula

C13H8Cl3NO

SMILES

C1=C(C(=CC(=C1)Cl)Cl)N(C(C2=CC=CC=C2)=O)Cl

I found the diagram on the left in a book and drew the one on the right using

https://pubchem.ncbi.nlm.nih.gov/edit2/index.html

And got the SMILES description from that.

Any clues as to what might be an IUPAC name and the formal way to write it out? Have I have even drawn it correctly? I could not do it exactly because the two rings kept connecting if I followed the same orientation. I don't know enough about double ring compounds to even hazard a guess.

Is there a automatic naming engine out there?

A compound called British Impregnite found in The Scientific method by Louis F. Fieser p.137

organic-chemistry nomenclature molecular-structure

share|improve this question

edited 2 hours ago

andselisk

17k655115

asked 2 hours ago

KalleMPKalleMP

389116

$endgroup$

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  Try Chemspider chemspider.com
  $endgroup$
  – Waylander
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  Chemdoodle thinks it is [N-Chloro(2,4-dichlorophenyl)amino]phenylformaldehyde but there is probably a less systematic version as well.
  $endgroup$
  – matt_black
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  $begingroup$
  @matt_black Wow, that's like most complicated, but very much not systematic name I've seen.
  $endgroup$
  – Mithoron
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  $begingroup$
  @matt_black That's Chemdoodle being Chemdoodle, I think:)
  $endgroup$
  – andselisk
  2 hours ago
  

  
  
  
  

add a comment | 

2

$begingroup$

Formula

C13H8Cl3NO

SMILES

C1=C(C(=CC(=C1)Cl)Cl)N(C(C2=CC=CC=C2)=O)Cl

I found the diagram on the left in a book and drew the one on the right using

https://pubchem.ncbi.nlm.nih.gov/edit2/index.html

And got the SMILES description from that.

Any clues as to what might be an IUPAC name and the formal way to write it out? Have I have even drawn it correctly? I could not do it exactly because the two rings kept connecting if I followed the same orientation. I don't know enough about double ring compounds to even hazard a guess.

Is there a automatic naming engine out there?

A compound called British Impregnite found in The Scientific method by Louis F. Fieser p.137

organic-chemistry nomenclature molecular-structure

share|improve this question

edited 2 hours ago

andselisk

17k655115

asked 2 hours ago

KalleMPKalleMP

389116

$endgroup$

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  Try Chemspider chemspider.com
  $endgroup$
  – Waylander
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  Chemdoodle thinks it is [N-Chloro(2,4-dichlorophenyl)amino]phenylformaldehyde but there is probably a less systematic version as well.
  $endgroup$
  – matt_black
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  $begingroup$
  @matt_black Wow, that's like most complicated, but very much not systematic name I've seen.
  $endgroup$
  – Mithoron
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  $begingroup$
  @matt_black That's Chemdoodle being Chemdoodle, I think:)
  $endgroup$
  – andselisk
  2 hours ago
  

  
  
  
  

add a comment | 

$begingroup$

Formula

C13H8Cl3NO

SMILES

C1=C(C(=CC(=C1)Cl)Cl)N(C(C2=CC=CC=C2)=O)Cl

I found the diagram on the left in a book and drew the one on the right using

https://pubchem.ncbi.nlm.nih.gov/edit2/index.html

And got the SMILES description from that.

Any clues as to what might be an IUPAC name and the formal way to write it out? Have I have even drawn it correctly? I could not do it exactly because the two rings kept connecting if I followed the same orientation. I don't know enough about double ring compounds to even hazard a guess.

Is there a automatic naming engine out there?

A compound called British Impregnite found in The Scientific method by Louis F. Fieser p.137

organic-chemistry nomenclature molecular-structure

share|improve this question

edited 2 hours ago

andselisk

17k655115

asked 2 hours ago

KalleMPKalleMP

389116

$endgroup$

share|improve this question

edited 2 hours ago

andselisk

17k655115

asked 2 hours ago

KalleMPKalleMP

389116

share|improve this question

edited 2 hours ago

andselisk

17k655115

asked 2 hours ago

KalleMPKalleMP

389116

edited 2 hours ago

andselisk

17k655115

edited 2 hours ago

andselisk

17k655115

asked 2 hours ago

KalleMPKalleMP

389116

asked 2 hours ago

KalleMPKalleMP

389116

2 Answers
2

active

oldest

votes

5

$begingroup$

Well, let's reconstruct that starting from the very right side, where it says a $ce{C_6H_5}$. The ring and the $ce{CO}$ group would be a benzaldehyde if it had an $ce{H}$ instead of an $ce{N}$, right? Or a benzoic acid if it was $ce{OH}$ instead of $ce{N}$. So what would it be if it had an $ce{NH_2}$-group? It would be a benzamide. If the $ce{N}$ is substituted with for example a chloride we call that N-chlorobenzamide. And now we have another $ce{N}$-centered ligand, the second phenyl ring. The ring has three positions, the one where it's connected to the rest of the molecule would be 1, so that makes a 2,4-dichlorophenyl.

Summarizing we get N-chloro-N-(2,4-dichlorophenyl)benzamide

share|improve this answer

edited 2 hours ago

Loong♦

33.3k883172

answered 2 hours ago

JustanotherchemistJustanotherchemist

1,894620

$endgroup$

add a comment | 

2

$begingroup$

There is a paper [1] reporting a structural investigation of aromatic N-chloroamides.
They investigated polymorphs of similar compound they refer to as N-chloro-N-phenylbenzamide:

Chlorinated product, I suspect, is indeed is going to be named N‐chloro‐N‐(2,4‐dichlorophenyl)benzamide, as the first answer suggested.

References

1. Naumov, P.; Topcu, Y.; Eckert-Maksić, M.; Glasovac, Z.; Pavošević, F.; Kochunnoonny, M.; Hara, H. Photoinduced Rearrangement of Aromatic N-Chloroamides to Chloroaromatic Amides in the Solid State: Inverted $Π_ce{N}–Σ_ce{N}$ Occupational Stability of Amidyl Radicals. The Journal of Physical Chemistry A 2011, 115 (26), 7834–7848. https://doi.org/10.1021/jp203771c.

share|improve this answer

answered 2 hours ago

andseliskandselisk

17k655115

$endgroup$

add a comment | 

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5

$begingroup$

Well, let's reconstruct that starting from the very right side, where it says a $ce{C_6H_5}$. The ring and the $ce{CO}$ group would be a benzaldehyde if it had an $ce{H}$ instead of an $ce{N}$, right? Or a benzoic acid if it was $ce{OH}$ instead of $ce{N}$. So what would it be if it had an $ce{NH_2}$-group? It would be a benzamide. If the $ce{N}$ is substituted with for example a chloride we call that N-chlorobenzamide. And now we have another $ce{N}$-centered ligand, the second phenyl ring. The ring has three positions, the one where it's connected to the rest of the molecule would be 1, so that makes a 2,4-dichlorophenyl.

Summarizing we get N-chloro-N-(2,4-dichlorophenyl)benzamide

share|improve this answer

edited 2 hours ago

Loong♦

33.3k883172

answered 2 hours ago

JustanotherchemistJustanotherchemist

1,894620

$endgroup$

add a comment | 

5

$begingroup$

Well, let's reconstruct that starting from the very right side, where it says a $ce{C_6H_5}$. The ring and the $ce{CO}$ group would be a benzaldehyde if it had an $ce{H}$ instead of an $ce{N}$, right? Or a benzoic acid if it was $ce{OH}$ instead of $ce{N}$. So what would it be if it had an $ce{NH_2}$-group? It would be a benzamide. If the $ce{N}$ is substituted with for example a chloride we call that N-chlorobenzamide. And now we have another $ce{N}$-centered ligand, the second phenyl ring. The ring has three positions, the one where it's connected to the rest of the molecule would be 1, so that makes a 2,4-dichlorophenyl.

Summarizing we get N-chloro-N-(2,4-dichlorophenyl)benzamide

share|improve this answer

edited 2 hours ago

Loong♦

33.3k883172

answered 2 hours ago

JustanotherchemistJustanotherchemist

1,894620

$endgroup$

add a comment | 

$begingroup$

Well, let's reconstruct that starting from the very right side, where it says a $ce{C_6H_5}$. The ring and the $ce{CO}$ group would be a benzaldehyde if it had an $ce{H}$ instead of an $ce{N}$, right? Or a benzoic acid if it was $ce{OH}$ instead of $ce{N}$. So what would it be if it had an $ce{NH_2}$-group? It would be a benzamide. If the $ce{N}$ is substituted with for example a chloride we call that N-chlorobenzamide. And now we have another $ce{N}$-centered ligand, the second phenyl ring. The ring has three positions, the one where it's connected to the rest of the molecule would be 1, so that makes a 2,4-dichlorophenyl.

Summarizing we get N-chloro-N-(2,4-dichlorophenyl)benzamide

share|improve this answer

edited 2 hours ago

Loong♦

33.3k883172

answered 2 hours ago

JustanotherchemistJustanotherchemist

1,894620

$endgroup$

share|improve this answer

edited 2 hours ago

Loong♦

33.3k883172

answered 2 hours ago

JustanotherchemistJustanotherchemist

1,894620

edited 2 hours ago

Loong♦

33.3k883172

edited 2 hours ago

Loong♦

33.3k883172

answered 2 hours ago

JustanotherchemistJustanotherchemist

1,894620

answered 2 hours ago

JustanotherchemistJustanotherchemist

1,894620

2

$begingroup$

There is a paper [1] reporting a structural investigation of aromatic N-chloroamides.
They investigated polymorphs of similar compound they refer to as N-chloro-N-phenylbenzamide:

Chlorinated product, I suspect, is indeed is going to be named N‐chloro‐N‐(2,4‐dichlorophenyl)benzamide, as the first answer suggested.

References

1. Naumov, P.; Topcu, Y.; Eckert-Maksić, M.; Glasovac, Z.; Pavošević, F.; Kochunnoonny, M.; Hara, H. Photoinduced Rearrangement of Aromatic N-Chloroamides to Chloroaromatic Amides in the Solid State: Inverted $Π_ce{N}–Σ_ce{N}$ Occupational Stability of Amidyl Radicals. The Journal of Physical Chemistry A 2011, 115 (26), 7834–7848. https://doi.org/10.1021/jp203771c.

share|improve this answer

answered 2 hours ago

andseliskandselisk

17k655115

$endgroup$

add a comment | 

2

$begingroup$

There is a paper [1] reporting a structural investigation of aromatic N-chloroamides.
They investigated polymorphs of similar compound they refer to as N-chloro-N-phenylbenzamide:

Chlorinated product, I suspect, is indeed is going to be named N‐chloro‐N‐(2,4‐dichlorophenyl)benzamide, as the first answer suggested.

References

1. Naumov, P.; Topcu, Y.; Eckert-Maksić, M.; Glasovac, Z.; Pavošević, F.; Kochunnoonny, M.; Hara, H. Photoinduced Rearrangement of Aromatic N-Chloroamides to Chloroaromatic Amides in the Solid State: Inverted $Π_ce{N}–Σ_ce{N}$ Occupational Stability of Amidyl Radicals. The Journal of Physical Chemistry A 2011, 115 (26), 7834–7848. https://doi.org/10.1021/jp203771c.

share|improve this answer

answered 2 hours ago

andseliskandselisk

17k655115

$endgroup$

add a comment | 

$begingroup$

There is a paper [1] reporting a structural investigation of aromatic N-chloroamides.
They investigated polymorphs of similar compound they refer to as N-chloro-N-phenylbenzamide:

Chlorinated product, I suspect, is indeed is going to be named N‐chloro‐N‐(2,4‐dichlorophenyl)benzamide, as the first answer suggested.

References

1. Naumov, P.; Topcu, Y.; Eckert-Maksić, M.; Glasovac, Z.; Pavošević, F.; Kochunnoonny, M.; Hara, H. Photoinduced Rearrangement of Aromatic N-Chloroamides to Chloroaromatic Amides in the Solid State: Inverted $Π_ce{N}–Σ_ce{N}$ Occupational Stability of Amidyl Radicals. The Journal of Physical Chemistry A 2011, 115 (26), 7834–7848. https://doi.org/10.1021/jp203771c.

share|improve this answer

answered 2 hours ago

andseliskandselisk

17k655115

$endgroup$

share|improve this answer

answered 2 hours ago

andseliskandselisk

17k655115

answered 2 hours ago

andseliskandselisk

17k655115

answered 2 hours ago

andseliskandselisk

17k655115