Does “variables should live in the smallest scope as possible” include the case “variables should not...
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Does “variables should live in the smallest scope as possible” include the case “variables should not exist if possible”?
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According to https://softwareengineering.stackexchange.com/a/388055/248528, variables should live in the smallest scope as possible, simplify the problem into my interpretation, it means we should refactor this kind of code:
public class Main{
private A a;
private B b;
public ABResult getResult(){
getA();
getB();
return ABFactory.mix(a,b);
}
private getA(){
a=SomeFactory.getA();
}
private getB(){
b=SomeFactory.getB();
}
}
into something like this:
public class Main{
public ABResult getResult(){
A a=getA();
B b=getB();
return ABFactory.mix(a,b);
}
private getA(){
a=SomeFactory.getA();
}
private getB(){
b=SomeFactory.getB();
}
}
but according to the "spirit" of "variables should live in the smallest scope as possible", isn't "never have variables" have smaller scope than "have variables"? So I think the version above should be refactored:
public class Main{
public ABResult getResult(){
return ABFactory.mix(getA(),getB());
}
private getA(){
a=SomeFactory.getA();
}
private getB(){
b=SomeFactory.getB();
}
}
so that getResult() doesn't have any local variables at all. Is that true?
refactoring scope local-variable
asked 4 hours ago
mmmaaammmaaa
2,68741724
add a comment |
According to https://softwareengineering.stackexchange.com/a/388055/248528, variables should live in the smallest scope as possible, simplify the problem into my interpretation, it means we should refactor this kind of code:
public class Main{
private A a;
private B b;
public ABResult getResult(){
getA();
getB();
return ABFactory.mix(a,b);
}
private getA(){
a=SomeFactory.getA();
}
private getB(){
b=SomeFactory.getB();
}
}
into something like this:
public class Main{
public ABResult getResult(){
A a=getA();
B b=getB();
return ABFactory.mix(a,b);
}
private getA(){
a=SomeFactory.getA();
}
private getB(){
b=SomeFactory.getB();
}
}
but according to the "spirit" of "variables should live in the smallest scope as possible", isn't "never have variables" have smaller scope than "have variables"? So I think the version above should be refactored:
public class Main{
public ABResult getResult(){
return ABFactory.mix(getA(),getB());
}
private getA(){
a=SomeFactory.getA();
}
private getB(){
b=SomeFactory.getB();
}
}
so that getResult() doesn't have any local variables at all. Is that true?
refactoring scope local-variable
asked 4 hours ago
mmmaaammmaaa
2,68741724
3
Creating explicit variables comes with the benefit of having to name them. Introducing a few variables can quickly turn an opaque method into a readable one.
– Jared Goguen
3 hours ago
add a comment |
According to https://softwareengineering.stackexchange.com/a/388055/248528, variables should live in the smallest scope as possible, simplify the problem into my interpretation, it means we should refactor this kind of code:
public class Main{
private A a;
private B b;
public ABResult getResult(){
getA();
getB();
return ABFactory.mix(a,b);
}
private getA(){
a=SomeFactory.getA();
}
private getB(){
b=SomeFactory.getB();
}
}
into something like this:
public class Main{
public ABResult getResult(){
A a=getA();
B b=getB();
return ABFactory.mix(a,b);
}
private getA(){
a=SomeFactory.getA();
}
private getB(){
b=SomeFactory.getB();
}
}
but according to the "spirit" of "variables should live in the smallest scope as possible", isn't "never have variables" have smaller scope than "have variables"? So I think the version above should be refactored:
public class Main{
public ABResult getResult(){
return ABFactory.mix(getA(),getB());
}
private getA(){
a=SomeFactory.getA();
}
private getB(){
b=SomeFactory.getB();
}
}
so that getResult() doesn't have any local variables at all. Is that true?
refactoring scope local-variable
asked 4 hours ago
mmmaaammmaaa
2,68741724
According to https://softwareengineering.stackexchange.com/a/388055/248528, variables should live in the smallest scope as possible, simplify the problem into my interpretation, it means we should refactor this kind of code:
public class Main{
private A a;
private B b;
public ABResult getResult(){
getA();
getB();
return ABFactory.mix(a,b);
}
private getA(){
a=SomeFactory.getA();
}
private getB(){
b=SomeFactory.getB();
}
}
into something like this:
public class Main{
public ABResult getResult(){
A a=getA();
B b=getB();
return ABFactory.mix(a,b);
}
private getA(){
a=SomeFactory.getA();
}
private getB(){
b=SomeFactory.getB();
}
}
but according to the "spirit" of "variables should live in the smallest scope as possible", isn't "never have variables" have smaller scope than "have variables"? So I think the version above should be refactored:
public class Main{
public ABResult getResult(){
return ABFactory.mix(getA(),getB());
}
private getA(){
a=SomeFactory.getA();
}
private getB(){
b=SomeFactory.getB();
}
}
so that getResult() doesn't have any local variables at all. Is that true?
refactoring scope local-variable
refactoring scope local-variable
asked 4 hours ago
mmmaaammmaaa
2,68741724
asked 4 hours ago
mmmaaammmaaa
2,68741724
asked 4 hours ago
mmmaaammmaaa
2,68741724
asked 4 hours ago
mmmaaammmaaa
2,68741724
asked 4 hours ago
mmmaaammmaaa
2,68741724
2,68741724
3
Creating explicit variables comes with the benefit of having to name them. Introducing a few variables can quickly turn an opaque method into a readable one.
– Jared Goguen
3 hours ago
add a comment |
3
Creating explicit variables comes with the benefit of having to name them. Introducing a few variables can quickly turn an opaque method into a readable one.
– Jared Goguen
3 hours ago
3
3
Creating explicit variables comes with the benefit of having to name them. Introducing a few variables can quickly turn an opaque method into a readable one.
– Jared Goguen
3 hours ago
Creating explicit variables comes with the benefit of having to name them. Introducing a few variables can quickly turn an opaque method into a readable one.
– Jared Goguen
3 hours ago
add a comment |
1 Answer
1
active
oldest
votes
No. There are several reasons why:
- Variables with meaningful names can make code easier to comprehend.
- Breaking up complex formulas into smaller steps can make the code easier to read.
- Caching.
- Holding references to objects so that they can be used more than once.
And so on.
answered 3 hours ago
Robert HarveyRobert Harvey
166k41380595
1
Also worth mentioning: The value is going to be stored in memory regardless, so it actually ends up with the same scope anyway. May as well name it(for the reasons Robert mentions above)!
– Maybe_Factor
1 hour ago
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
No. There are several reasons why:
- Variables with meaningful names can make code easier to comprehend.
- Breaking up complex formulas into smaller steps can make the code easier to read.
- Caching.
- Holding references to objects so that they can be used more than once.
And so on.
answered 3 hours ago
Robert HarveyRobert Harvey
166k41380595
1
Also worth mentioning: The value is going to be stored in memory regardless, so it actually ends up with the same scope anyway. May as well name it(for the reasons Robert mentions above)!
– Maybe_Factor
1 hour ago
add a comment |
No. There are several reasons why:
- Variables with meaningful names can make code easier to comprehend.
- Breaking up complex formulas into smaller steps can make the code easier to read.
- Caching.
- Holding references to objects so that they can be used more than once.
And so on.
answered 3 hours ago
Robert HarveyRobert Harvey
166k41380595
1
Also worth mentioning: The value is going to be stored in memory regardless, so it actually ends up with the same scope anyway. May as well name it(for the reasons Robert mentions above)!
– Maybe_Factor
1 hour ago
add a comment |
No. There are several reasons why:
- Variables with meaningful names can make code easier to comprehend.
- Breaking up complex formulas into smaller steps can make the code easier to read.
- Caching.
- Holding references to objects so that they can be used more than once.
And so on.
answered 3 hours ago
Robert HarveyRobert Harvey
166k41380595
No. There are several reasons why:
- Variables with meaningful names can make code easier to comprehend.
- Breaking up complex formulas into smaller steps can make the code easier to read.
- Caching.
- Holding references to objects so that they can be used more than once.
And so on.
answered 3 hours ago
Robert HarveyRobert Harvey
166k41380595
edited 2 hours ago
answered 3 hours ago
Robert HarveyRobert Harvey
166k41380595
answered 3 hours ago
Robert HarveyRobert Harvey
166k41380595
answered 3 hours ago
Robert HarveyRobert Harvey
166k41380595
166k41380595
1
Also worth mentioning: The value is going to be stored in memory regardless, so it actually ends up with the same scope anyway. May as well name it(for the reasons Robert mentions above)!
– Maybe_Factor
1 hour ago
add a comment |
1
Also worth mentioning: The value is going to be stored in memory regardless, so it actually ends up with the same scope anyway. May as well name it(for the reasons Robert mentions above)!
– Maybe_Factor
1 hour ago
1
1
Also worth mentioning: The value is going to be stored in memory regardless, so it actually ends up with the same scope anyway. May as well name it(for the reasons Robert mentions above)!
– Maybe_Factor
1 hour ago
Also worth mentioning: The value is going to be stored in memory regardless, so it actually ends up with the same scope anyway. May as well name it(for the reasons Robert mentions above)!
– Maybe_Factor
1 hour ago
add a comment |
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3
Creating explicit variables comes with the benefit of having to name them. Introducing a few variables can quickly turn an opaque method into a readable one.
– Jared Goguen
3 hours ago