checking code if violates in c++
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checking code if violates in c++
$begingroup$
Hi all I need a code check up from all C++ experts. Basically, I need make my code not use these restrictions as shown below:
Can you check if I am using while(1)? thank you.
- No global variables
No labels or go-to statements
No infinite loops, examples include:
- for(;;)
- while(1)
- while(true)
- do{//code}while(1);
- No break statements to exit loops
Here is my code:
int main() {
//MARK: For the validation.
int error = 1;
//MARK: For the highest score.
int highestScore = 0;
//MARK: The player structure.
struct Player players[12];
//MARK: The index.
int index;
// MARK: Iterate through all the players.
for (index = 0; index < 12; index++) {
//MARK: Displaying player number.
cout << "nPLAYER #" << (index + 1) << "n";
cout << "n Player name:";
cin >> players[index].playerName;
while (error == 1) {
cout << "n Player's number:";
cin >> players[index].playerNumber;
//MARK: Simple validation to detect the player for entering negative numbers.
if (players[index].playerNumber < 0) {
cout << "n No negative numbers pleasen";
continue;
}
cout << "n Points scored: ";
cin >> players[index].playerPoints;
if (players[index].playerPoints < 0) {
cout << "n No negative numbers pleasen";
continue;
}
cin.clear();
error = 0;
}
error = 1;
}
c++
asked 1 min ago
MikeMike
11
New contributor
Mike is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Hi all I need a code check up from all C++ experts. Basically, I need make my code not use these restrictions as shown below:
Can you check if I am using while(1)? thank you.
- No global variables
No labels or go-to statements
No infinite loops, examples include:
- for(;;)
- while(1)
- while(true)
- do{//code}while(1);
- No break statements to exit loops
Here is my code:
int main() {
//MARK: For the validation.
int error = 1;
//MARK: For the highest score.
int highestScore = 0;
//MARK: The player structure.
struct Player players[12];
//MARK: The index.
int index;
// MARK: Iterate through all the players.
for (index = 0; index < 12; index++) {
//MARK: Displaying player number.
cout << "nPLAYER #" << (index + 1) << "n";
cout << "n Player name:";
cin >> players[index].playerName;
while (error == 1) {
cout << "n Player's number:";
cin >> players[index].playerNumber;
//MARK: Simple validation to detect the player for entering negative numbers.
if (players[index].playerNumber < 0) {
cout << "n No negative numbers pleasen";
continue;
}
cout << "n Points scored: ";
cin >> players[index].playerPoints;
if (players[index].playerPoints < 0) {
cout << "n No negative numbers pleasen";
continue;
}
cin.clear();
error = 0;
}
error = 1;
}
c++
asked 1 min ago
MikeMike
11
New contributor
Mike is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Hi all I need a code check up from all C++ experts. Basically, I need make my code not use these restrictions as shown below:
Can you check if I am using while(1)? thank you.
- No global variables
No labels or go-to statements
No infinite loops, examples include:
- for(;;)
- while(1)
- while(true)
- do{//code}while(1);
- No break statements to exit loops
Here is my code:
int main() {
//MARK: For the validation.
int error = 1;
//MARK: For the highest score.
int highestScore = 0;
//MARK: The player structure.
struct Player players[12];
//MARK: The index.
int index;
// MARK: Iterate through all the players.
for (index = 0; index < 12; index++) {
//MARK: Displaying player number.
cout << "nPLAYER #" << (index + 1) << "n";
cout << "n Player name:";
cin >> players[index].playerName;
while (error == 1) {
cout << "n Player's number:";
cin >> players[index].playerNumber;
//MARK: Simple validation to detect the player for entering negative numbers.
if (players[index].playerNumber < 0) {
cout << "n No negative numbers pleasen";
continue;
}
cout << "n Points scored: ";
cin >> players[index].playerPoints;
if (players[index].playerPoints < 0) {
cout << "n No negative numbers pleasen";
continue;
}
cin.clear();
error = 0;
}
error = 1;
}
c++
asked 1 min ago
MikeMike
11
New contributor
Mike is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Hi all I need a code check up from all C++ experts. Basically, I need make my code not use these restrictions as shown below:
Can you check if I am using while(1)? thank you.
- No global variables
No labels or go-to statements
No infinite loops, examples include:
- for(;;)
- while(1)
- while(true)
- do{//code}while(1);
- No break statements to exit loops
Here is my code:
int main() {
//MARK: For the validation.
int error = 1;
//MARK: For the highest score.
int highestScore = 0;
//MARK: The player structure.
struct Player players[12];
//MARK: The index.
int index;
// MARK: Iterate through all the players.
for (index = 0; index < 12; index++) {
//MARK: Displaying player number.
cout << "nPLAYER #" << (index + 1) << "n";
cout << "n Player name:";
cin >> players[index].playerName;
while (error == 1) {
cout << "n Player's number:";
cin >> players[index].playerNumber;
//MARK: Simple validation to detect the player for entering negative numbers.
if (players[index].playerNumber < 0) {
cout << "n No negative numbers pleasen";
continue;
}
cout << "n Points scored: ";
cin >> players[index].playerPoints;
if (players[index].playerPoints < 0) {
cout << "n No negative numbers pleasen";
continue;
}
cin.clear();
error = 0;
}
error = 1;
}
c++
c++
asked 1 min ago
MikeMike
11
New contributor
Mike is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 1 min ago
MikeMike
11
New contributor
Mike is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 1 min ago
MikeMike
11
New contributor
Mike is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 1 min ago
MikeMike
11
asked 1 min ago
MikeMike
11
11
New contributor
Mike is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Mike is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Mike is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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Mike is a new contributor. Be nice, and check out our Code of Conduct.
Mike is a new contributor. Be nice, and check out our Code of Conduct.
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Mike is a new contributor. Be nice, and check out our Code of Conduct.
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