8 channel quiz buzzer circuit using 8051 microcontrollerBaud-rate for 8051 MicrocontrollerAVR Button...

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8 channel quiz buzzer circuit using 8051 microcontroller


Baud-rate for 8051 MicrocontrollerAVR Button InterfacingSend a text from 8051 using TR8008051 Microcontroller & OscillatorBuzzer Driver CircuitCountdown Timer on Switch Input ARM 7PIC16F1783 Inclinometer Project using Accelerometer 12-bit ADC issueUsing timers 8051 Assembly MicrocontrollerInterfacing keypad with 8051 microcontroller in ProteusUsing piezo buzzer to play complex waveforms













2












$begingroup$


Project: 8 channel quiz buzzer circuit using 8051 microcontroller from this site.



For the first candidate who presses their button, their number will show on the 7-segment display and the buzzer will make a sound.



After making all the connections, the display is working but the buzzer is not making any sound. Buzzer delay time in code in 1ms. When we give direct 5V supply to the buzzer it works, but not in the circuit.



Please give me some solution for this.



circuit diagram



#include<reg51.h>

#define SEGMENT P2 // PORT2 to Segments of 7-Segment Display
#define SWITCH P1 // Input Switches (buttons) to PORT1

sbit buzz=P3^0; // Buzzer
sbit rst=P3^3; // Reset Switch (Reset the display) - not the microcontroller
sbit digit=P3^7; // 7-Segment Display Common Pin (to enable)


void delay (int); // Delay function

int x=0,y,z;
unsigned char ch[]={0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x98}; // Hexadecimal values from 0 to 9.

void delay (int d)
{
unsigned char i;
for(;d>0;d--)
{
for(i=250;i>0;i--);
for(i=248;i>0;i--);
}
}

void main()
{
SWITCH=0xff;
SEGMENT=0xff;
digit=1;
buzz=0;
rst=1;

while(1)
{
while(SWITCH==0xff); // wait until any button is pressed.

while (SWITCH==0xfe) // Button 1 is pressed.
{
SEGMENT=ch[1];
buzz=1;
delay(1000); // Activate buzzer for 1 second.
buzz=0;
while(rst!=0); // display the digit until the reset is pressed.
}

while (SWITCH==0xfd) // Button 2 is pressed.
{
SEGMENT=ch[2];
buzz=1;
delay(1000);
buzz=0;
while(rst!=0);
}

while (SWITCH==0xfb) // Button 3 is pressed.
{
SEGMENT=ch[3];
buzz=1;
delay(1000);
buzz=0;
while(rst!=0);
}

while (SWITCH==0xf7) // Button 4 is pressed.
{
SEGMENT=ch[4];
buzz=1;
delay(1000);
buzz=0;
while(rst!=0);
}

while (SWITCH==0xef) // Button 5 is pressed.
{
SEGMENT=ch[5];
buzz=1;
delay(1000);
buzz=0;
while(rst!=0);
}

while (SWITCH==0xdf) // Button 6 is pressed.
{
SEGMENT=ch[6];
buzz=1;
delay(1000);
buzz=0;
while(rst!=0);
}

while (SWITCH==0xbf) // Button 7 is pressed.
{
SEGMENT=ch[7];
buzz=1;
delay(1000);
buzz=0;
while(rst!=0);
}

while (SWITCH==0x7f) // Button 8 is pressed.
{
SEGMENT=ch[8];
buzz=1;
delay(1000);
buzz=0;
while(rst!=0);
}

SEGMENT=0xff;
rst=1;

}
}









share|improve this question









New contributor




Shrutika Jagtap is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$








  • 1




    $begingroup$
    it sounds like the microcontroller output is too weak to drive the buzzer, measure the voltage on the buzzer
    $endgroup$
    – Jasen
    5 hours ago










  • $begingroup$
    We measure the voltage on buzzer .It is 5v.
    $endgroup$
    – Shrutika Jagtap
    5 hours ago






  • 2




    $begingroup$
    Can you remove disconnect the resistor from pin 10 of the AT89C51 and drive it manually with 5V? (P.S. do use reference names as well for components, it is easier to refer to them that way)
    $endgroup$
    – Huisman
    5 hours ago












  • $begingroup$
    P3^3 What language is this? It is nonsense in C, ^ being the bitwise XOR operator.
    $endgroup$
    – Lundin
    4 hours ago






  • 2




    $begingroup$
    @Lundin It is no nonsense. Please read keil.com/support/man/docs/c51/c51_le_sbit.htm
    $endgroup$
    – Huisman
    4 hours ago
















2












$begingroup$


Project: 8 channel quiz buzzer circuit using 8051 microcontroller from this site.



For the first candidate who presses their button, their number will show on the 7-segment display and the buzzer will make a sound.



After making all the connections, the display is working but the buzzer is not making any sound. Buzzer delay time in code in 1ms. When we give direct 5V supply to the buzzer it works, but not in the circuit.



Please give me some solution for this.



circuit diagram



#include<reg51.h>

#define SEGMENT P2 // PORT2 to Segments of 7-Segment Display
#define SWITCH P1 // Input Switches (buttons) to PORT1

sbit buzz=P3^0; // Buzzer
sbit rst=P3^3; // Reset Switch (Reset the display) - not the microcontroller
sbit digit=P3^7; // 7-Segment Display Common Pin (to enable)


void delay (int); // Delay function

int x=0,y,z;
unsigned char ch[]={0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x98}; // Hexadecimal values from 0 to 9.

void delay (int d)
{
unsigned char i;
for(;d>0;d--)
{
for(i=250;i>0;i--);
for(i=248;i>0;i--);
}
}

void main()
{
SWITCH=0xff;
SEGMENT=0xff;
digit=1;
buzz=0;
rst=1;

while(1)
{
while(SWITCH==0xff); // wait until any button is pressed.

while (SWITCH==0xfe) // Button 1 is pressed.
{
SEGMENT=ch[1];
buzz=1;
delay(1000); // Activate buzzer for 1 second.
buzz=0;
while(rst!=0); // display the digit until the reset is pressed.
}

while (SWITCH==0xfd) // Button 2 is pressed.
{
SEGMENT=ch[2];
buzz=1;
delay(1000);
buzz=0;
while(rst!=0);
}

while (SWITCH==0xfb) // Button 3 is pressed.
{
SEGMENT=ch[3];
buzz=1;
delay(1000);
buzz=0;
while(rst!=0);
}

while (SWITCH==0xf7) // Button 4 is pressed.
{
SEGMENT=ch[4];
buzz=1;
delay(1000);
buzz=0;
while(rst!=0);
}

while (SWITCH==0xef) // Button 5 is pressed.
{
SEGMENT=ch[5];
buzz=1;
delay(1000);
buzz=0;
while(rst!=0);
}

while (SWITCH==0xdf) // Button 6 is pressed.
{
SEGMENT=ch[6];
buzz=1;
delay(1000);
buzz=0;
while(rst!=0);
}

while (SWITCH==0xbf) // Button 7 is pressed.
{
SEGMENT=ch[7];
buzz=1;
delay(1000);
buzz=0;
while(rst!=0);
}

while (SWITCH==0x7f) // Button 8 is pressed.
{
SEGMENT=ch[8];
buzz=1;
delay(1000);
buzz=0;
while(rst!=0);
}

SEGMENT=0xff;
rst=1;

}
}









share|improve this question









New contributor




Shrutika Jagtap is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$








  • 1




    $begingroup$
    it sounds like the microcontroller output is too weak to drive the buzzer, measure the voltage on the buzzer
    $endgroup$
    – Jasen
    5 hours ago










  • $begingroup$
    We measure the voltage on buzzer .It is 5v.
    $endgroup$
    – Shrutika Jagtap
    5 hours ago






  • 2




    $begingroup$
    Can you remove disconnect the resistor from pin 10 of the AT89C51 and drive it manually with 5V? (P.S. do use reference names as well for components, it is easier to refer to them that way)
    $endgroup$
    – Huisman
    5 hours ago












  • $begingroup$
    P3^3 What language is this? It is nonsense in C, ^ being the bitwise XOR operator.
    $endgroup$
    – Lundin
    4 hours ago






  • 2




    $begingroup$
    @Lundin It is no nonsense. Please read keil.com/support/man/docs/c51/c51_le_sbit.htm
    $endgroup$
    – Huisman
    4 hours ago














2












2








2





$begingroup$


Project: 8 channel quiz buzzer circuit using 8051 microcontroller from this site.



For the first candidate who presses their button, their number will show on the 7-segment display and the buzzer will make a sound.



After making all the connections, the display is working but the buzzer is not making any sound. Buzzer delay time in code in 1ms. When we give direct 5V supply to the buzzer it works, but not in the circuit.



Please give me some solution for this.



circuit diagram



#include<reg51.h>

#define SEGMENT P2 // PORT2 to Segments of 7-Segment Display
#define SWITCH P1 // Input Switches (buttons) to PORT1

sbit buzz=P3^0; // Buzzer
sbit rst=P3^3; // Reset Switch (Reset the display) - not the microcontroller
sbit digit=P3^7; // 7-Segment Display Common Pin (to enable)


void delay (int); // Delay function

int x=0,y,z;
unsigned char ch[]={0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x98}; // Hexadecimal values from 0 to 9.

void delay (int d)
{
unsigned char i;
for(;d>0;d--)
{
for(i=250;i>0;i--);
for(i=248;i>0;i--);
}
}

void main()
{
SWITCH=0xff;
SEGMENT=0xff;
digit=1;
buzz=0;
rst=1;

while(1)
{
while(SWITCH==0xff); // wait until any button is pressed.

while (SWITCH==0xfe) // Button 1 is pressed.
{
SEGMENT=ch[1];
buzz=1;
delay(1000); // Activate buzzer for 1 second.
buzz=0;
while(rst!=0); // display the digit until the reset is pressed.
}

while (SWITCH==0xfd) // Button 2 is pressed.
{
SEGMENT=ch[2];
buzz=1;
delay(1000);
buzz=0;
while(rst!=0);
}

while (SWITCH==0xfb) // Button 3 is pressed.
{
SEGMENT=ch[3];
buzz=1;
delay(1000);
buzz=0;
while(rst!=0);
}

while (SWITCH==0xf7) // Button 4 is pressed.
{
SEGMENT=ch[4];
buzz=1;
delay(1000);
buzz=0;
while(rst!=0);
}

while (SWITCH==0xef) // Button 5 is pressed.
{
SEGMENT=ch[5];
buzz=1;
delay(1000);
buzz=0;
while(rst!=0);
}

while (SWITCH==0xdf) // Button 6 is pressed.
{
SEGMENT=ch[6];
buzz=1;
delay(1000);
buzz=0;
while(rst!=0);
}

while (SWITCH==0xbf) // Button 7 is pressed.
{
SEGMENT=ch[7];
buzz=1;
delay(1000);
buzz=0;
while(rst!=0);
}

while (SWITCH==0x7f) // Button 8 is pressed.
{
SEGMENT=ch[8];
buzz=1;
delay(1000);
buzz=0;
while(rst!=0);
}

SEGMENT=0xff;
rst=1;

}
}









share|improve this question









New contributor




Shrutika Jagtap is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




Project: 8 channel quiz buzzer circuit using 8051 microcontroller from this site.



For the first candidate who presses their button, their number will show on the 7-segment display and the buzzer will make a sound.



After making all the connections, the display is working but the buzzer is not making any sound. Buzzer delay time in code in 1ms. When we give direct 5V supply to the buzzer it works, but not in the circuit.



Please give me some solution for this.



circuit diagram



#include<reg51.h>

#define SEGMENT P2 // PORT2 to Segments of 7-Segment Display
#define SWITCH P1 // Input Switches (buttons) to PORT1

sbit buzz=P3^0; // Buzzer
sbit rst=P3^3; // Reset Switch (Reset the display) - not the microcontroller
sbit digit=P3^7; // 7-Segment Display Common Pin (to enable)


void delay (int); // Delay function

int x=0,y,z;
unsigned char ch[]={0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x98}; // Hexadecimal values from 0 to 9.

void delay (int d)
{
unsigned char i;
for(;d>0;d--)
{
for(i=250;i>0;i--);
for(i=248;i>0;i--);
}
}

void main()
{
SWITCH=0xff;
SEGMENT=0xff;
digit=1;
buzz=0;
rst=1;

while(1)
{
while(SWITCH==0xff); // wait until any button is pressed.

while (SWITCH==0xfe) // Button 1 is pressed.
{
SEGMENT=ch[1];
buzz=1;
delay(1000); // Activate buzzer for 1 second.
buzz=0;
while(rst!=0); // display the digit until the reset is pressed.
}

while (SWITCH==0xfd) // Button 2 is pressed.
{
SEGMENT=ch[2];
buzz=1;
delay(1000);
buzz=0;
while(rst!=0);
}

while (SWITCH==0xfb) // Button 3 is pressed.
{
SEGMENT=ch[3];
buzz=1;
delay(1000);
buzz=0;
while(rst!=0);
}

while (SWITCH==0xf7) // Button 4 is pressed.
{
SEGMENT=ch[4];
buzz=1;
delay(1000);
buzz=0;
while(rst!=0);
}

while (SWITCH==0xef) // Button 5 is pressed.
{
SEGMENT=ch[5];
buzz=1;
delay(1000);
buzz=0;
while(rst!=0);
}

while (SWITCH==0xdf) // Button 6 is pressed.
{
SEGMENT=ch[6];
buzz=1;
delay(1000);
buzz=0;
while(rst!=0);
}

while (SWITCH==0xbf) // Button 7 is pressed.
{
SEGMENT=ch[7];
buzz=1;
delay(1000);
buzz=0;
while(rst!=0);
}

while (SWITCH==0x7f) // Button 8 is pressed.
{
SEGMENT=ch[8];
buzz=1;
delay(1000);
buzz=0;
while(rst!=0);
}

SEGMENT=0xff;
rst=1;

}
}






microcontroller 8051 piezo-buzzer






share|improve this question









New contributor




Shrutika Jagtap is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




Shrutika Jagtap is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited 1 hour ago









SamGibson

11.6k41739




11.6k41739






New contributor




Shrutika Jagtap is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 5 hours ago









Shrutika JagtapShrutika Jagtap

212




212




New contributor




Shrutika Jagtap is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Shrutika Jagtap is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Shrutika Jagtap is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








  • 1




    $begingroup$
    it sounds like the microcontroller output is too weak to drive the buzzer, measure the voltage on the buzzer
    $endgroup$
    – Jasen
    5 hours ago










  • $begingroup$
    We measure the voltage on buzzer .It is 5v.
    $endgroup$
    – Shrutika Jagtap
    5 hours ago






  • 2




    $begingroup$
    Can you remove disconnect the resistor from pin 10 of the AT89C51 and drive it manually with 5V? (P.S. do use reference names as well for components, it is easier to refer to them that way)
    $endgroup$
    – Huisman
    5 hours ago












  • $begingroup$
    P3^3 What language is this? It is nonsense in C, ^ being the bitwise XOR operator.
    $endgroup$
    – Lundin
    4 hours ago






  • 2




    $begingroup$
    @Lundin It is no nonsense. Please read keil.com/support/man/docs/c51/c51_le_sbit.htm
    $endgroup$
    – Huisman
    4 hours ago














  • 1




    $begingroup$
    it sounds like the microcontroller output is too weak to drive the buzzer, measure the voltage on the buzzer
    $endgroup$
    – Jasen
    5 hours ago










  • $begingroup$
    We measure the voltage on buzzer .It is 5v.
    $endgroup$
    – Shrutika Jagtap
    5 hours ago






  • 2




    $begingroup$
    Can you remove disconnect the resistor from pin 10 of the AT89C51 and drive it manually with 5V? (P.S. do use reference names as well for components, it is easier to refer to them that way)
    $endgroup$
    – Huisman
    5 hours ago












  • $begingroup$
    P3^3 What language is this? It is nonsense in C, ^ being the bitwise XOR operator.
    $endgroup$
    – Lundin
    4 hours ago






  • 2




    $begingroup$
    @Lundin It is no nonsense. Please read keil.com/support/man/docs/c51/c51_le_sbit.htm
    $endgroup$
    – Huisman
    4 hours ago








1




1




$begingroup$
it sounds like the microcontroller output is too weak to drive the buzzer, measure the voltage on the buzzer
$endgroup$
– Jasen
5 hours ago




$begingroup$
it sounds like the microcontroller output is too weak to drive the buzzer, measure the voltage on the buzzer
$endgroup$
– Jasen
5 hours ago












$begingroup$
We measure the voltage on buzzer .It is 5v.
$endgroup$
– Shrutika Jagtap
5 hours ago




$begingroup$
We measure the voltage on buzzer .It is 5v.
$endgroup$
– Shrutika Jagtap
5 hours ago




2




2




$begingroup$
Can you remove disconnect the resistor from pin 10 of the AT89C51 and drive it manually with 5V? (P.S. do use reference names as well for components, it is easier to refer to them that way)
$endgroup$
– Huisman
5 hours ago






$begingroup$
Can you remove disconnect the resistor from pin 10 of the AT89C51 and drive it manually with 5V? (P.S. do use reference names as well for components, it is easier to refer to them that way)
$endgroup$
– Huisman
5 hours ago














$begingroup$
P3^3 What language is this? It is nonsense in C, ^ being the bitwise XOR operator.
$endgroup$
– Lundin
4 hours ago




$begingroup$
P3^3 What language is this? It is nonsense in C, ^ being the bitwise XOR operator.
$endgroup$
– Lundin
4 hours ago




2




2




$begingroup$
@Lundin It is no nonsense. Please read keil.com/support/man/docs/c51/c51_le_sbit.htm
$endgroup$
– Huisman
4 hours ago




$begingroup$
@Lundin It is no nonsense. Please read keil.com/support/man/docs/c51/c51_le_sbit.htm
$endgroup$
– Huisman
4 hours ago










2 Answers
2






active

oldest

votes


















5












$begingroup$

The 8051 and clones typically use an I/O configuration that is described as "pseudo-bidirectional". They have active pull-down but quasi-passive pull-up (there's a transistor that is turned on briefly to improve the rise time). This means that they can only source a tiny amount of continuous current to an external device. The datasheet (DC Characteristics, page 10) shows that VOH drops to 2.4V at just 60 µA of current.



This is not enough current to drive your NPN transistor. Instead, try putting a logic-level N-channel MOSFET there.





Note also that your other NPN (the one attached to pin 17 — you really do need to use reference designators in your schematics!) should actually be a PNP. This requires inverting the logic in your code that drives pin 17.






share|improve this answer











$endgroup$













  • $begingroup$
    There's only one digit of display so the transistor attached to pin 17 is not even needed at all. The SEGMENT=0xFF line at the end of the loop blanks the display.
    $endgroup$
    – Finbarr
    1 hour ago





















1












$begingroup$

You don't say what type of device the buzzer is (electromechanical, piezo, etc.) or how much current it requires to operate, but I don't think either of those is the problem.



One millisecond is too short a time for the buzzer to wake up and make enough noise to be heard. Increase the on-time to 1 second to verify that the code is working, then adjust to taste.



BTW, what type of buzzer is it? Datasheet or link?






share|improve this answer









$endgroup$









  • 1




    $begingroup$
    Hi, "One millisecond is too short a time for the buzzer to wake up" FYI the OP isn't claiming to drive the buzzer for 1ms. The code (I added a link to the original source page) is supposed to switch on the buzzer, delay for 1000 x 1ms = 1s (hence the delay(1000);), then switch the buzzer off. There are comments in the original code which I linked (not included by the OP) which make this clearer. That doesn't answer all of your questions, but I hope their intent is now clearer.
    $endgroup$
    – SamGibson
    1 hour ago













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2 Answers
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2 Answers
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The 8051 and clones typically use an I/O configuration that is described as "pseudo-bidirectional". They have active pull-down but quasi-passive pull-up (there's a transistor that is turned on briefly to improve the rise time). This means that they can only source a tiny amount of continuous current to an external device. The datasheet (DC Characteristics, page 10) shows that VOH drops to 2.4V at just 60 µA of current.



This is not enough current to drive your NPN transistor. Instead, try putting a logic-level N-channel MOSFET there.





Note also that your other NPN (the one attached to pin 17 — you really do need to use reference designators in your schematics!) should actually be a PNP. This requires inverting the logic in your code that drives pin 17.






share|improve this answer











$endgroup$













  • $begingroup$
    There's only one digit of display so the transistor attached to pin 17 is not even needed at all. The SEGMENT=0xFF line at the end of the loop blanks the display.
    $endgroup$
    – Finbarr
    1 hour ago


















5












$begingroup$

The 8051 and clones typically use an I/O configuration that is described as "pseudo-bidirectional". They have active pull-down but quasi-passive pull-up (there's a transistor that is turned on briefly to improve the rise time). This means that they can only source a tiny amount of continuous current to an external device. The datasheet (DC Characteristics, page 10) shows that VOH drops to 2.4V at just 60 µA of current.



This is not enough current to drive your NPN transistor. Instead, try putting a logic-level N-channel MOSFET there.





Note also that your other NPN (the one attached to pin 17 — you really do need to use reference designators in your schematics!) should actually be a PNP. This requires inverting the logic in your code that drives pin 17.






share|improve this answer











$endgroup$













  • $begingroup$
    There's only one digit of display so the transistor attached to pin 17 is not even needed at all. The SEGMENT=0xFF line at the end of the loop blanks the display.
    $endgroup$
    – Finbarr
    1 hour ago
















5












5








5





$begingroup$

The 8051 and clones typically use an I/O configuration that is described as "pseudo-bidirectional". They have active pull-down but quasi-passive pull-up (there's a transistor that is turned on briefly to improve the rise time). This means that they can only source a tiny amount of continuous current to an external device. The datasheet (DC Characteristics, page 10) shows that VOH drops to 2.4V at just 60 µA of current.



This is not enough current to drive your NPN transistor. Instead, try putting a logic-level N-channel MOSFET there.





Note also that your other NPN (the one attached to pin 17 — you really do need to use reference designators in your schematics!) should actually be a PNP. This requires inverting the logic in your code that drives pin 17.






share|improve this answer











$endgroup$



The 8051 and clones typically use an I/O configuration that is described as "pseudo-bidirectional". They have active pull-down but quasi-passive pull-up (there's a transistor that is turned on briefly to improve the rise time). This means that they can only source a tiny amount of continuous current to an external device. The datasheet (DC Characteristics, page 10) shows that VOH drops to 2.4V at just 60 µA of current.



This is not enough current to drive your NPN transistor. Instead, try putting a logic-level N-channel MOSFET there.





Note also that your other NPN (the one attached to pin 17 — you really do need to use reference designators in your schematics!) should actually be a PNP. This requires inverting the logic in your code that drives pin 17.







share|improve this answer














share|improve this answer



share|improve this answer








edited 2 hours ago

























answered 2 hours ago









Dave TweedDave Tweed

122k9152264




122k9152264












  • $begingroup$
    There's only one digit of display so the transistor attached to pin 17 is not even needed at all. The SEGMENT=0xFF line at the end of the loop blanks the display.
    $endgroup$
    – Finbarr
    1 hour ago




















  • $begingroup$
    There's only one digit of display so the transistor attached to pin 17 is not even needed at all. The SEGMENT=0xFF line at the end of the loop blanks the display.
    $endgroup$
    – Finbarr
    1 hour ago


















$begingroup$
There's only one digit of display so the transistor attached to pin 17 is not even needed at all. The SEGMENT=0xFF line at the end of the loop blanks the display.
$endgroup$
– Finbarr
1 hour ago






$begingroup$
There's only one digit of display so the transistor attached to pin 17 is not even needed at all. The SEGMENT=0xFF line at the end of the loop blanks the display.
$endgroup$
– Finbarr
1 hour ago















1












$begingroup$

You don't say what type of device the buzzer is (electromechanical, piezo, etc.) or how much current it requires to operate, but I don't think either of those is the problem.



One millisecond is too short a time for the buzzer to wake up and make enough noise to be heard. Increase the on-time to 1 second to verify that the code is working, then adjust to taste.



BTW, what type of buzzer is it? Datasheet or link?






share|improve this answer









$endgroup$









  • 1




    $begingroup$
    Hi, "One millisecond is too short a time for the buzzer to wake up" FYI the OP isn't claiming to drive the buzzer for 1ms. The code (I added a link to the original source page) is supposed to switch on the buzzer, delay for 1000 x 1ms = 1s (hence the delay(1000);), then switch the buzzer off. There are comments in the original code which I linked (not included by the OP) which make this clearer. That doesn't answer all of your questions, but I hope their intent is now clearer.
    $endgroup$
    – SamGibson
    1 hour ago


















1












$begingroup$

You don't say what type of device the buzzer is (electromechanical, piezo, etc.) or how much current it requires to operate, but I don't think either of those is the problem.



One millisecond is too short a time for the buzzer to wake up and make enough noise to be heard. Increase the on-time to 1 second to verify that the code is working, then adjust to taste.



BTW, what type of buzzer is it? Datasheet or link?






share|improve this answer









$endgroup$









  • 1




    $begingroup$
    Hi, "One millisecond is too short a time for the buzzer to wake up" FYI the OP isn't claiming to drive the buzzer for 1ms. The code (I added a link to the original source page) is supposed to switch on the buzzer, delay for 1000 x 1ms = 1s (hence the delay(1000);), then switch the buzzer off. There are comments in the original code which I linked (not included by the OP) which make this clearer. That doesn't answer all of your questions, but I hope their intent is now clearer.
    $endgroup$
    – SamGibson
    1 hour ago
















1












1








1





$begingroup$

You don't say what type of device the buzzer is (electromechanical, piezo, etc.) or how much current it requires to operate, but I don't think either of those is the problem.



One millisecond is too short a time for the buzzer to wake up and make enough noise to be heard. Increase the on-time to 1 second to verify that the code is working, then adjust to taste.



BTW, what type of buzzer is it? Datasheet or link?






share|improve this answer









$endgroup$



You don't say what type of device the buzzer is (electromechanical, piezo, etc.) or how much current it requires to operate, but I don't think either of those is the problem.



One millisecond is too short a time for the buzzer to wake up and make enough noise to be heard. Increase the on-time to 1 second to verify that the code is working, then adjust to taste.



BTW, what type of buzzer is it? Datasheet or link?







share|improve this answer












share|improve this answer



share|improve this answer










answered 2 hours ago









AnalogKidAnalogKid

2,73637




2,73637








  • 1




    $begingroup$
    Hi, "One millisecond is too short a time for the buzzer to wake up" FYI the OP isn't claiming to drive the buzzer for 1ms. The code (I added a link to the original source page) is supposed to switch on the buzzer, delay for 1000 x 1ms = 1s (hence the delay(1000);), then switch the buzzer off. There are comments in the original code which I linked (not included by the OP) which make this clearer. That doesn't answer all of your questions, but I hope their intent is now clearer.
    $endgroup$
    – SamGibson
    1 hour ago
















  • 1




    $begingroup$
    Hi, "One millisecond is too short a time for the buzzer to wake up" FYI the OP isn't claiming to drive the buzzer for 1ms. The code (I added a link to the original source page) is supposed to switch on the buzzer, delay for 1000 x 1ms = 1s (hence the delay(1000);), then switch the buzzer off. There are comments in the original code which I linked (not included by the OP) which make this clearer. That doesn't answer all of your questions, but I hope their intent is now clearer.
    $endgroup$
    – SamGibson
    1 hour ago










1




1




$begingroup$
Hi, "One millisecond is too short a time for the buzzer to wake up" FYI the OP isn't claiming to drive the buzzer for 1ms. The code (I added a link to the original source page) is supposed to switch on the buzzer, delay for 1000 x 1ms = 1s (hence the delay(1000);), then switch the buzzer off. There are comments in the original code which I linked (not included by the OP) which make this clearer. That doesn't answer all of your questions, but I hope their intent is now clearer.
$endgroup$
– SamGibson
1 hour ago






$begingroup$
Hi, "One millisecond is too short a time for the buzzer to wake up" FYI the OP isn't claiming to drive the buzzer for 1ms. The code (I added a link to the original source page) is supposed to switch on the buzzer, delay for 1000 x 1ms = 1s (hence the delay(1000);), then switch the buzzer off. There are comments in the original code which I linked (not included by the OP) which make this clearer. That doesn't answer all of your questions, but I hope their intent is now clearer.
$endgroup$
– SamGibson
1 hour ago












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