Read/write a pipe-delimited file line by line with some simple text manipulationRead file line-by-line with...

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Read/write a pipe-delimited file line by line with some simple text manipulation


Read file line-by-line with circular bufferRead Space Delimited Text File to Standardized Data Typefunction responsible for parsing 2 csv txt files, comparing them and writing csv txt files as outputC++ Read File line by lineA minimal CLI password storage and retrieval managerPython read/write pickled fileSimple python code takes command line argument for file location and tokenizes textRead integers from text file and write to CSV fileFile manipulation with HaskellRead and write BMP file in C






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}







9












$begingroup$


This code that I wrote is supposed to read/write a pipe-delimited file line by line to a new file with some simple text manipulation. (It also adds two new columns) and publishes a "Status Update" ever 100,000 lines to keep me updated on how close it is to completion.



I previously posted this code on StackOverflow to get help with incrementing, and someone mentioned that it would be faster if I did not open the second text file, but being extremely new at Python, I do not understand how to do that without potentially breaking the code.



counter=1
for line in open(r"C:Pathname.txt"):
spline = line.split("|")
if counter==1:
with open(r"C:PATH2019.txt",'a') as NewFile:
spline.insert(23,"Column A")
spline.insert(23,"Column B")
s="|"
newline=s.join(spline)
NewFile.write(newline)

elif counter > 1 and not spline[22]=="0.00":
spline.insert(23,"")
spline.insert(23,"")
gl=spline[0]
gl=gl.strip()
if gl[0]=="-": gl="000" + gl
gl=gl.upper()
spline[0]=gl

if gl[:3]=="000": spline[24]="Incorrect"

s="|"
newline=s.join(spline)

with open(r"C:PATHPythonWrittenData.txt",'a') as NewFile:
NewFile.write(newline)

counter+=1
if counter%100000==0: print("Status Update: n", "{:,}".format(counter))









share|improve this question











$endgroup$












  • $begingroup$
    Can you edit your question to explain what the loop is supposed to do?
    $endgroup$
    – David White
    Apr 1 at 14:28










  • $begingroup$
    @DavidWhite Added. For quick reference: It reads one text file line by line, performs string manipulation, and then writes it into a new file line by line.
    $endgroup$
    – Emily Alden
    Apr 1 at 14:56


















9












$begingroup$


This code that I wrote is supposed to read/write a pipe-delimited file line by line to a new file with some simple text manipulation. (It also adds two new columns) and publishes a "Status Update" ever 100,000 lines to keep me updated on how close it is to completion.



I previously posted this code on StackOverflow to get help with incrementing, and someone mentioned that it would be faster if I did not open the second text file, but being extremely new at Python, I do not understand how to do that without potentially breaking the code.



counter=1
for line in open(r"C:Pathname.txt"):
spline = line.split("|")
if counter==1:
with open(r"C:PATH2019.txt",'a') as NewFile:
spline.insert(23,"Column A")
spline.insert(23,"Column B")
s="|"
newline=s.join(spline)
NewFile.write(newline)

elif counter > 1 and not spline[22]=="0.00":
spline.insert(23,"")
spline.insert(23,"")
gl=spline[0]
gl=gl.strip()
if gl[0]=="-": gl="000" + gl
gl=gl.upper()
spline[0]=gl

if gl[:3]=="000": spline[24]="Incorrect"

s="|"
newline=s.join(spline)

with open(r"C:PATHPythonWrittenData.txt",'a') as NewFile:
NewFile.write(newline)

counter+=1
if counter%100000==0: print("Status Update: n", "{:,}".format(counter))









share|improve this question











$endgroup$












  • $begingroup$
    Can you edit your question to explain what the loop is supposed to do?
    $endgroup$
    – David White
    Apr 1 at 14:28










  • $begingroup$
    @DavidWhite Added. For quick reference: It reads one text file line by line, performs string manipulation, and then writes it into a new file line by line.
    $endgroup$
    – Emily Alden
    Apr 1 at 14:56














9












9








9





$begingroup$


This code that I wrote is supposed to read/write a pipe-delimited file line by line to a new file with some simple text manipulation. (It also adds two new columns) and publishes a "Status Update" ever 100,000 lines to keep me updated on how close it is to completion.



I previously posted this code on StackOverflow to get help with incrementing, and someone mentioned that it would be faster if I did not open the second text file, but being extremely new at Python, I do not understand how to do that without potentially breaking the code.



counter=1
for line in open(r"C:Pathname.txt"):
spline = line.split("|")
if counter==1:
with open(r"C:PATH2019.txt",'a') as NewFile:
spline.insert(23,"Column A")
spline.insert(23,"Column B")
s="|"
newline=s.join(spline)
NewFile.write(newline)

elif counter > 1 and not spline[22]=="0.00":
spline.insert(23,"")
spline.insert(23,"")
gl=spline[0]
gl=gl.strip()
if gl[0]=="-": gl="000" + gl
gl=gl.upper()
spline[0]=gl

if gl[:3]=="000": spline[24]="Incorrect"

s="|"
newline=s.join(spline)

with open(r"C:PATHPythonWrittenData.txt",'a') as NewFile:
NewFile.write(newline)

counter+=1
if counter%100000==0: print("Status Update: n", "{:,}".format(counter))









share|improve this question











$endgroup$




This code that I wrote is supposed to read/write a pipe-delimited file line by line to a new file with some simple text manipulation. (It also adds two new columns) and publishes a "Status Update" ever 100,000 lines to keep me updated on how close it is to completion.



I previously posted this code on StackOverflow to get help with incrementing, and someone mentioned that it would be faster if I did not open the second text file, but being extremely new at Python, I do not understand how to do that without potentially breaking the code.



counter=1
for line in open(r"C:Pathname.txt"):
spline = line.split("|")
if counter==1:
with open(r"C:PATH2019.txt",'a') as NewFile:
spline.insert(23,"Column A")
spline.insert(23,"Column B")
s="|"
newline=s.join(spline)
NewFile.write(newline)

elif counter > 1 and not spline[22]=="0.00":
spline.insert(23,"")
spline.insert(23,"")
gl=spline[0]
gl=gl.strip()
if gl[0]=="-": gl="000" + gl
gl=gl.upper()
spline[0]=gl

if gl[:3]=="000": spline[24]="Incorrect"

s="|"
newline=s.join(spline)

with open(r"C:PATHPythonWrittenData.txt",'a') as NewFile:
NewFile.write(newline)

counter+=1
if counter%100000==0: print("Status Update: n", "{:,}".format(counter))






python beginner python-3.x file csv






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Apr 1 at 16:48









200_success

131k17157422




131k17157422










asked Apr 1 at 13:23









Emily AldenEmily Alden

24228




24228












  • $begingroup$
    Can you edit your question to explain what the loop is supposed to do?
    $endgroup$
    – David White
    Apr 1 at 14:28










  • $begingroup$
    @DavidWhite Added. For quick reference: It reads one text file line by line, performs string manipulation, and then writes it into a new file line by line.
    $endgroup$
    – Emily Alden
    Apr 1 at 14:56


















  • $begingroup$
    Can you edit your question to explain what the loop is supposed to do?
    $endgroup$
    – David White
    Apr 1 at 14:28










  • $begingroup$
    @DavidWhite Added. For quick reference: It reads one text file line by line, performs string manipulation, and then writes it into a new file line by line.
    $endgroup$
    – Emily Alden
    Apr 1 at 14:56
















$begingroup$
Can you edit your question to explain what the loop is supposed to do?
$endgroup$
– David White
Apr 1 at 14:28




$begingroup$
Can you edit your question to explain what the loop is supposed to do?
$endgroup$
– David White
Apr 1 at 14:28












$begingroup$
@DavidWhite Added. For quick reference: It reads one text file line by line, performs string manipulation, and then writes it into a new file line by line.
$endgroup$
– Emily Alden
Apr 1 at 14:56




$begingroup$
@DavidWhite Added. For quick reference: It reads one text file line by line, performs string manipulation, and then writes it into a new file line by line.
$endgroup$
– Emily Alden
Apr 1 at 14:56










2 Answers
2






active

oldest

votes


















6












$begingroup$

A nice trick you can use in python is to open two (or more) files at once in one line. This is done with something like:



with open('file_one.txt', 'r') as file_one, open('file_two.txt', 'r') as file_two:
for line in file_one:
...
for line in file_two:
...


This is a very common way of reading from one file and writing to another without continually opening and closing one of them.



Currently, you're opening and closing the files with each iteration of the loop. Your program loops through the lines in name.txt, checks an if / elif condition, then if either are satisfied, a file is opened, written to, then closed again with every iteration of the loop.



Simply by opening both files at the same time you can stop opening and closing them repeatedly.



For more info on the with statement and other context managers, see here.





Another small improvement can be made. At the moment, you check the first if condition every time, but you know it will only actually evaluate to True once. it would be better to remove that check and just always perform that block once. Assign counter after the first block (after where if counter == 1 currently is) then replace the elif statement with a while loop.





It would be worth getting familiar with PEP8 if you're going to use Python a lot in the future. It's a standard style guide and will help with the readability of your code (for you and others). Just small stuff like new lines after colons or spaces either side of variable declarations / comparisons.





If you include an example file and desired output, there may be more I can help with.






share|improve this answer









$endgroup$













  • $begingroup$
    I decided to accept this answer as it has the information most pertinent to my skill level and it worked. (I couldn't get the iterative answer to produce the expected results). Thank you very much. I am modifying my code so that it will be PEP8 compliant.
    $endgroup$
    – Emily Alden
    Apr 1 at 21:07



















8












$begingroup$

Here is another way to organize your code. Instead of an if within the loop, use iterators more explicitly. Concretely:



with open(r"C:Pathname.txt") as source:
lines = iter(source)

# first line
first_line = next(lines)
with open(r"C:PATH2019.txt") as summary:
# ... omitted ...

# remaining lines
with open(r"C:PATHPythonWrittenData.txt", 'a') as dest:
for counter, line in enumerate(lines, start=1):
# ... omitted ...



I have also used enumerate to update counter and line simultaneously.



The other answer has some more tips on writing good python code. But as far as structuring the opening and closing of files, as well as the main loop, this approach should get you started.






share|improve this answer









$endgroup$













  • $begingroup$
    I'm not sure I understand the reasoning behind first_line=next(lines) could you explain how it should be used?
    $endgroup$
    – Emily Alden
    Apr 1 at 18:22










  • $begingroup$
    @EmilyAlden Why accept an answer when you don’t understand why that answer works?
    $endgroup$
    – David White
    Apr 1 at 19:11










  • $begingroup$
    @DavidWhite: Honestly I bounced between which answer to accept. I understand the use of iter and enumerate here which are the main parts of the answer. The line I do not understand applies only once and I believe I can write around that line and get the results I want. (Still working on it though).
    $endgroup$
    – Emily Alden
    Apr 1 at 19:36








  • 1




    $begingroup$
    @EmilyAlden first_line = next(iterator) is equivalent to for first_line in iterator: break
    $endgroup$
    – wizzwizz4
    Apr 1 at 19:48










  • $begingroup$
    @wizzwizz4 Thank you.
    $endgroup$
    – Emily Alden
    Apr 1 at 19:50












Your Answer





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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









6












$begingroup$

A nice trick you can use in python is to open two (or more) files at once in one line. This is done with something like:



with open('file_one.txt', 'r') as file_one, open('file_two.txt', 'r') as file_two:
for line in file_one:
...
for line in file_two:
...


This is a very common way of reading from one file and writing to another without continually opening and closing one of them.



Currently, you're opening and closing the files with each iteration of the loop. Your program loops through the lines in name.txt, checks an if / elif condition, then if either are satisfied, a file is opened, written to, then closed again with every iteration of the loop.



Simply by opening both files at the same time you can stop opening and closing them repeatedly.



For more info on the with statement and other context managers, see here.





Another small improvement can be made. At the moment, you check the first if condition every time, but you know it will only actually evaluate to True once. it would be better to remove that check and just always perform that block once. Assign counter after the first block (after where if counter == 1 currently is) then replace the elif statement with a while loop.





It would be worth getting familiar with PEP8 if you're going to use Python a lot in the future. It's a standard style guide and will help with the readability of your code (for you and others). Just small stuff like new lines after colons or spaces either side of variable declarations / comparisons.





If you include an example file and desired output, there may be more I can help with.






share|improve this answer









$endgroup$













  • $begingroup$
    I decided to accept this answer as it has the information most pertinent to my skill level and it worked. (I couldn't get the iterative answer to produce the expected results). Thank you very much. I am modifying my code so that it will be PEP8 compliant.
    $endgroup$
    – Emily Alden
    Apr 1 at 21:07
















6












$begingroup$

A nice trick you can use in python is to open two (or more) files at once in one line. This is done with something like:



with open('file_one.txt', 'r') as file_one, open('file_two.txt', 'r') as file_two:
for line in file_one:
...
for line in file_two:
...


This is a very common way of reading from one file and writing to another without continually opening and closing one of them.



Currently, you're opening and closing the files with each iteration of the loop. Your program loops through the lines in name.txt, checks an if / elif condition, then if either are satisfied, a file is opened, written to, then closed again with every iteration of the loop.



Simply by opening both files at the same time you can stop opening and closing them repeatedly.



For more info on the with statement and other context managers, see here.





Another small improvement can be made. At the moment, you check the first if condition every time, but you know it will only actually evaluate to True once. it would be better to remove that check and just always perform that block once. Assign counter after the first block (after where if counter == 1 currently is) then replace the elif statement with a while loop.





It would be worth getting familiar with PEP8 if you're going to use Python a lot in the future. It's a standard style guide and will help with the readability of your code (for you and others). Just small stuff like new lines after colons or spaces either side of variable declarations / comparisons.





If you include an example file and desired output, there may be more I can help with.






share|improve this answer









$endgroup$













  • $begingroup$
    I decided to accept this answer as it has the information most pertinent to my skill level and it worked. (I couldn't get the iterative answer to produce the expected results). Thank you very much. I am modifying my code so that it will be PEP8 compliant.
    $endgroup$
    – Emily Alden
    Apr 1 at 21:07














6












6








6





$begingroup$

A nice trick you can use in python is to open two (or more) files at once in one line. This is done with something like:



with open('file_one.txt', 'r') as file_one, open('file_two.txt', 'r') as file_two:
for line in file_one:
...
for line in file_two:
...


This is a very common way of reading from one file and writing to another without continually opening and closing one of them.



Currently, you're opening and closing the files with each iteration of the loop. Your program loops through the lines in name.txt, checks an if / elif condition, then if either are satisfied, a file is opened, written to, then closed again with every iteration of the loop.



Simply by opening both files at the same time you can stop opening and closing them repeatedly.



For more info on the with statement and other context managers, see here.





Another small improvement can be made. At the moment, you check the first if condition every time, but you know it will only actually evaluate to True once. it would be better to remove that check and just always perform that block once. Assign counter after the first block (after where if counter == 1 currently is) then replace the elif statement with a while loop.





It would be worth getting familiar with PEP8 if you're going to use Python a lot in the future. It's a standard style guide and will help with the readability of your code (for you and others). Just small stuff like new lines after colons or spaces either side of variable declarations / comparisons.





If you include an example file and desired output, there may be more I can help with.






share|improve this answer









$endgroup$



A nice trick you can use in python is to open two (or more) files at once in one line. This is done with something like:



with open('file_one.txt', 'r') as file_one, open('file_two.txt', 'r') as file_two:
for line in file_one:
...
for line in file_two:
...


This is a very common way of reading from one file and writing to another without continually opening and closing one of them.



Currently, you're opening and closing the files with each iteration of the loop. Your program loops through the lines in name.txt, checks an if / elif condition, then if either are satisfied, a file is opened, written to, then closed again with every iteration of the loop.



Simply by opening both files at the same time you can stop opening and closing them repeatedly.



For more info on the with statement and other context managers, see here.





Another small improvement can be made. At the moment, you check the first if condition every time, but you know it will only actually evaluate to True once. it would be better to remove that check and just always perform that block once. Assign counter after the first block (after where if counter == 1 currently is) then replace the elif statement with a while loop.





It would be worth getting familiar with PEP8 if you're going to use Python a lot in the future. It's a standard style guide and will help with the readability of your code (for you and others). Just small stuff like new lines after colons or spaces either side of variable declarations / comparisons.





If you include an example file and desired output, there may be more I can help with.







share|improve this answer












share|improve this answer



share|improve this answer










answered Apr 1 at 15:20









HoboProberHoboProber

4216




4216












  • $begingroup$
    I decided to accept this answer as it has the information most pertinent to my skill level and it worked. (I couldn't get the iterative answer to produce the expected results). Thank you very much. I am modifying my code so that it will be PEP8 compliant.
    $endgroup$
    – Emily Alden
    Apr 1 at 21:07


















  • $begingroup$
    I decided to accept this answer as it has the information most pertinent to my skill level and it worked. (I couldn't get the iterative answer to produce the expected results). Thank you very much. I am modifying my code so that it will be PEP8 compliant.
    $endgroup$
    – Emily Alden
    Apr 1 at 21:07
















$begingroup$
I decided to accept this answer as it has the information most pertinent to my skill level and it worked. (I couldn't get the iterative answer to produce the expected results). Thank you very much. I am modifying my code so that it will be PEP8 compliant.
$endgroup$
– Emily Alden
Apr 1 at 21:07




$begingroup$
I decided to accept this answer as it has the information most pertinent to my skill level and it worked. (I couldn't get the iterative answer to produce the expected results). Thank you very much. I am modifying my code so that it will be PEP8 compliant.
$endgroup$
– Emily Alden
Apr 1 at 21:07













8












$begingroup$

Here is another way to organize your code. Instead of an if within the loop, use iterators more explicitly. Concretely:



with open(r"C:Pathname.txt") as source:
lines = iter(source)

# first line
first_line = next(lines)
with open(r"C:PATH2019.txt") as summary:
# ... omitted ...

# remaining lines
with open(r"C:PATHPythonWrittenData.txt", 'a') as dest:
for counter, line in enumerate(lines, start=1):
# ... omitted ...



I have also used enumerate to update counter and line simultaneously.



The other answer has some more tips on writing good python code. But as far as structuring the opening and closing of files, as well as the main loop, this approach should get you started.






share|improve this answer









$endgroup$













  • $begingroup$
    I'm not sure I understand the reasoning behind first_line=next(lines) could you explain how it should be used?
    $endgroup$
    – Emily Alden
    Apr 1 at 18:22










  • $begingroup$
    @EmilyAlden Why accept an answer when you don’t understand why that answer works?
    $endgroup$
    – David White
    Apr 1 at 19:11










  • $begingroup$
    @DavidWhite: Honestly I bounced between which answer to accept. I understand the use of iter and enumerate here which are the main parts of the answer. The line I do not understand applies only once and I believe I can write around that line and get the results I want. (Still working on it though).
    $endgroup$
    – Emily Alden
    Apr 1 at 19:36








  • 1




    $begingroup$
    @EmilyAlden first_line = next(iterator) is equivalent to for first_line in iterator: break
    $endgroup$
    – wizzwizz4
    Apr 1 at 19:48










  • $begingroup$
    @wizzwizz4 Thank you.
    $endgroup$
    – Emily Alden
    Apr 1 at 19:50
















8












$begingroup$

Here is another way to organize your code. Instead of an if within the loop, use iterators more explicitly. Concretely:



with open(r"C:Pathname.txt") as source:
lines = iter(source)

# first line
first_line = next(lines)
with open(r"C:PATH2019.txt") as summary:
# ... omitted ...

# remaining lines
with open(r"C:PATHPythonWrittenData.txt", 'a') as dest:
for counter, line in enumerate(lines, start=1):
# ... omitted ...



I have also used enumerate to update counter and line simultaneously.



The other answer has some more tips on writing good python code. But as far as structuring the opening and closing of files, as well as the main loop, this approach should get you started.






share|improve this answer









$endgroup$













  • $begingroup$
    I'm not sure I understand the reasoning behind first_line=next(lines) could you explain how it should be used?
    $endgroup$
    – Emily Alden
    Apr 1 at 18:22










  • $begingroup$
    @EmilyAlden Why accept an answer when you don’t understand why that answer works?
    $endgroup$
    – David White
    Apr 1 at 19:11










  • $begingroup$
    @DavidWhite: Honestly I bounced between which answer to accept. I understand the use of iter and enumerate here which are the main parts of the answer. The line I do not understand applies only once and I believe I can write around that line and get the results I want. (Still working on it though).
    $endgroup$
    – Emily Alden
    Apr 1 at 19:36








  • 1




    $begingroup$
    @EmilyAlden first_line = next(iterator) is equivalent to for first_line in iterator: break
    $endgroup$
    – wizzwizz4
    Apr 1 at 19:48










  • $begingroup$
    @wizzwizz4 Thank you.
    $endgroup$
    – Emily Alden
    Apr 1 at 19:50














8












8








8





$begingroup$

Here is another way to organize your code. Instead of an if within the loop, use iterators more explicitly. Concretely:



with open(r"C:Pathname.txt") as source:
lines = iter(source)

# first line
first_line = next(lines)
with open(r"C:PATH2019.txt") as summary:
# ... omitted ...

# remaining lines
with open(r"C:PATHPythonWrittenData.txt", 'a') as dest:
for counter, line in enumerate(lines, start=1):
# ... omitted ...



I have also used enumerate to update counter and line simultaneously.



The other answer has some more tips on writing good python code. But as far as structuring the opening and closing of files, as well as the main loop, this approach should get you started.






share|improve this answer









$endgroup$



Here is another way to organize your code. Instead of an if within the loop, use iterators more explicitly. Concretely:



with open(r"C:Pathname.txt") as source:
lines = iter(source)

# first line
first_line = next(lines)
with open(r"C:PATH2019.txt") as summary:
# ... omitted ...

# remaining lines
with open(r"C:PATHPythonWrittenData.txt", 'a') as dest:
for counter, line in enumerate(lines, start=1):
# ... omitted ...



I have also used enumerate to update counter and line simultaneously.



The other answer has some more tips on writing good python code. But as far as structuring the opening and closing of files, as well as the main loop, this approach should get you started.







share|improve this answer












share|improve this answer



share|improve this answer










answered Apr 1 at 15:39









Benjamin KuykendallBenjamin Kuykendall

75329




75329












  • $begingroup$
    I'm not sure I understand the reasoning behind first_line=next(lines) could you explain how it should be used?
    $endgroup$
    – Emily Alden
    Apr 1 at 18:22










  • $begingroup$
    @EmilyAlden Why accept an answer when you don’t understand why that answer works?
    $endgroup$
    – David White
    Apr 1 at 19:11










  • $begingroup$
    @DavidWhite: Honestly I bounced between which answer to accept. I understand the use of iter and enumerate here which are the main parts of the answer. The line I do not understand applies only once and I believe I can write around that line and get the results I want. (Still working on it though).
    $endgroup$
    – Emily Alden
    Apr 1 at 19:36








  • 1




    $begingroup$
    @EmilyAlden first_line = next(iterator) is equivalent to for first_line in iterator: break
    $endgroup$
    – wizzwizz4
    Apr 1 at 19:48










  • $begingroup$
    @wizzwizz4 Thank you.
    $endgroup$
    – Emily Alden
    Apr 1 at 19:50


















  • $begingroup$
    I'm not sure I understand the reasoning behind first_line=next(lines) could you explain how it should be used?
    $endgroup$
    – Emily Alden
    Apr 1 at 18:22










  • $begingroup$
    @EmilyAlden Why accept an answer when you don’t understand why that answer works?
    $endgroup$
    – David White
    Apr 1 at 19:11










  • $begingroup$
    @DavidWhite: Honestly I bounced between which answer to accept. I understand the use of iter and enumerate here which are the main parts of the answer. The line I do not understand applies only once and I believe I can write around that line and get the results I want. (Still working on it though).
    $endgroup$
    – Emily Alden
    Apr 1 at 19:36








  • 1




    $begingroup$
    @EmilyAlden first_line = next(iterator) is equivalent to for first_line in iterator: break
    $endgroup$
    – wizzwizz4
    Apr 1 at 19:48










  • $begingroup$
    @wizzwizz4 Thank you.
    $endgroup$
    – Emily Alden
    Apr 1 at 19:50
















$begingroup$
I'm not sure I understand the reasoning behind first_line=next(lines) could you explain how it should be used?
$endgroup$
– Emily Alden
Apr 1 at 18:22




$begingroup$
I'm not sure I understand the reasoning behind first_line=next(lines) could you explain how it should be used?
$endgroup$
– Emily Alden
Apr 1 at 18:22












$begingroup$
@EmilyAlden Why accept an answer when you don’t understand why that answer works?
$endgroup$
– David White
Apr 1 at 19:11




$begingroup$
@EmilyAlden Why accept an answer when you don’t understand why that answer works?
$endgroup$
– David White
Apr 1 at 19:11












$begingroup$
@DavidWhite: Honestly I bounced between which answer to accept. I understand the use of iter and enumerate here which are the main parts of the answer. The line I do not understand applies only once and I believe I can write around that line and get the results I want. (Still working on it though).
$endgroup$
– Emily Alden
Apr 1 at 19:36






$begingroup$
@DavidWhite: Honestly I bounced between which answer to accept. I understand the use of iter and enumerate here which are the main parts of the answer. The line I do not understand applies only once and I believe I can write around that line and get the results I want. (Still working on it though).
$endgroup$
– Emily Alden
Apr 1 at 19:36






1




1




$begingroup$
@EmilyAlden first_line = next(iterator) is equivalent to for first_line in iterator: break
$endgroup$
– wizzwizz4
Apr 1 at 19:48




$begingroup$
@EmilyAlden first_line = next(iterator) is equivalent to for first_line in iterator: break
$endgroup$
– wizzwizz4
Apr 1 at 19:48












$begingroup$
@wizzwizz4 Thank you.
$endgroup$
– Emily Alden
Apr 1 at 19:50




$begingroup$
@wizzwizz4 Thank you.
$endgroup$
– Emily Alden
Apr 1 at 19:50


















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