Roman Numerals equation 1Differentiate between the numbers from 1 to 5 with one single yes/no questionThe...
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Roman Numerals equation 1
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$begingroup$
The following Roman numeral equation is of course incorrect.
Make the equation correct by moving exactly one letter anywhere. You must place that letter in the equation (cannot remove it). You can be creative.
Of course "not equal to" or > or < is not allowed.
lateral-thinking
asked 14 hours ago
DEEMDEEM
6,159120109
$endgroup$
add a comment |
$begingroup$
The following Roman numeral equation is of course incorrect.
Make the equation correct by moving exactly one letter anywhere. You must place that letter in the equation (cannot remove it). You can be creative.
Of course "not equal to" or > or < is not allowed.
lateral-thinking
asked 14 hours ago
DEEMDEEM
6,159120109
$endgroup$
$begingroup$
Can I move rot13(Gur yrggref Q be Z sebz lbhe hfreanzr? be gur yrggre Z sebz "Znxr gur rdhngvba...)?
$endgroup$
– Chris Cudmore
12 hours ago
$begingroup$
No I dont think that was my intention.
$endgroup$
– DEEM
12 hours ago
$begingroup$
To clarify, you mean move a single character (L, I or M) in the equation to a new location in the equation to make it valid. Would moving an I adjacent to another I to make a V or X be valid? Does the construction have to be valid? i.e. IM for 999 is not a valid Roman Numeral. Do you permit it?
$endgroup$
– Chris Cudmore
9 hours ago
$begingroup$
Any single letter needs to be moved. The lateral thinking is "V" in "M " is also a letter.
$endgroup$
– DEEM
9 hours ago
add a comment |
$begingroup$
The following Roman numeral equation is of course incorrect.
Make the equation correct by moving exactly one letter anywhere. You must place that letter in the equation (cannot remove it). You can be creative.
Of course "not equal to" or > or < is not allowed.
lateral-thinking
asked 14 hours ago
DEEMDEEM
6,159120109
$endgroup$
The following Roman numeral equation is of course incorrect.
Make the equation correct by moving exactly one letter anywhere. You must place that letter in the equation (cannot remove it). You can be creative.
Of course "not equal to" or > or < is not allowed.
lateral-thinking
lateral-thinking
asked 14 hours ago
DEEMDEEM
6,159120109
asked 14 hours ago
DEEMDEEM
6,159120109
edited 14 hours ago
DEEM
asked 14 hours ago
DEEMDEEM
6,159120109
asked 14 hours ago
DEEMDEEM
6,159120109
asked 14 hours ago
DEEMDEEM
6,159120109
6,159120109
$begingroup$
Can I move rot13(Gur yrggref Q be Z sebz lbhe hfreanzr? be gur yrggre Z sebz "Znxr gur rdhngvba...)?
$endgroup$
– Chris Cudmore
12 hours ago
$begingroup$
No I dont think that was my intention.
$endgroup$
– DEEM
12 hours ago
$begingroup$
To clarify, you mean move a single character (L, I or M) in the equation to a new location in the equation to make it valid. Would moving an I adjacent to another I to make a V or X be valid? Does the construction have to be valid? i.e. IM for 999 is not a valid Roman Numeral. Do you permit it?
$endgroup$
– Chris Cudmore
9 hours ago
$begingroup$
Any single letter needs to be moved. The lateral thinking is "V" in "M " is also a letter.
$endgroup$
– DEEM
9 hours ago
add a comment |
$begingroup$
Can I move rot13(Gur yrggref Q be Z sebz lbhe hfreanzr? be gur yrggre Z sebz "Znxr gur rdhngvba...)?
$endgroup$
– Chris Cudmore
12 hours ago
$begingroup$
No I dont think that was my intention.
$endgroup$
– DEEM
12 hours ago
$begingroup$
To clarify, you mean move a single character (L, I or M) in the equation to a new location in the equation to make it valid. Would moving an I adjacent to another I to make a V or X be valid? Does the construction have to be valid? i.e. IM for 999 is not a valid Roman Numeral. Do you permit it?
$endgroup$
– Chris Cudmore
9 hours ago
$begingroup$
Any single letter needs to be moved. The lateral thinking is "V" in "M " is also a letter.
$endgroup$
– DEEM
9 hours ago
$begingroup$
Can I move rot13(Gur yrggref Q be Z sebz lbhe hfreanzr? be gur yrggre Z sebz "Znxr gur rdhngvba...)?
$endgroup$
– Chris Cudmore
12 hours ago
$begingroup$
Can I move rot13(Gur yrggref Q be Z sebz lbhe hfreanzr? be gur yrggre Z sebz "Znxr gur rdhngvba...)?
$endgroup$
– Chris Cudmore
12 hours ago
$begingroup$
No I dont think that was my intention.
$endgroup$
– DEEM
12 hours ago
$begingroup$
No I dont think that was my intention.
$endgroup$
– DEEM
12 hours ago
$begingroup$
To clarify, you mean move a single character (L, I or M) in the equation to a new location in the equation to make it valid. Would moving an I adjacent to another I to make a V or X be valid? Does the construction have to be valid? i.e. IM for 999 is not a valid Roman Numeral. Do you permit it?
$endgroup$
– Chris Cudmore
9 hours ago
$begingroup$
To clarify, you mean move a single character (L, I or M) in the equation to a new location in the equation to make it valid. Would moving an I adjacent to another I to make a V or X be valid? Does the construction have to be valid? i.e. IM for 999 is not a valid Roman Numeral. Do you permit it?
$endgroup$
– Chris Cudmore
9 hours ago
$begingroup$
Any single letter needs to be moved. The lateral thinking is "V" in "M " is also a letter.
$endgroup$
– DEEM
9 hours ago
$begingroup$
Any single letter needs to be moved. The lateral thinking is "V" in "M " is also a letter.
$endgroup$
– DEEM
9 hours ago
add a comment |
5 Answers
5
active
oldest
votes
$begingroup$
Very lateral:
Move the 'v' within the M, then flip the equation. Allow Roman on one side, Arabic on the other with ^ as the exponent sign
Giving:
answered 14 hours ago
TwoBitOperationTwoBitOperation
6,92311156
$endgroup$
$begingroup$
Ah, This makes sense given the suspicious amount of space between the 'L' and the 'I'
$endgroup$
– Joseph B.
14 hours ago
add a comment |
$begingroup$
Again very lateral:
Move the L, rotate and shrink it and stick it between the last two II's, making an M leaving I = M - IM
answered 14 hours ago
Chris CudmoreChris Cudmore
4,57711337
$endgroup$
$begingroup$
Wow. Hats off to your creativity!
$endgroup$
– DEEM
14 hours ago
add a comment |
$begingroup$
I believe I've gotten it.
Take the bottom of L (which is a sideways letter I) and put it on top of the last I on the right (leave it sideways).
This creates: II = M - IIT
'T' is not a roman numeral, just a line above an I
A line atop a roman numeral designates that it is multiplied by 1000
The equation thus becomes 2 = 1000 - 998, which is correct
answered 12 hours ago
CrescentSickleCrescentSickle
612
New contributor
CrescentSickle is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
1
$begingroup$
This works, and I like the thinking. However, I'll be disappointed if this is the correct answer as 998 is properly written CMXCVIII -- That is your solution doesn't conform to the rules of construction.
$endgroup$
– Chris Cudmore
12 hours ago
$begingroup$
@ChrisCudmore The formatting might be another part of "lateral thinking". Just a guess.
$endgroup$
– CrescentSickle
12 hours ago
1
$begingroup$
Could be. Good answer, anyways.
$endgroup$
– Chris Cudmore
12 hours ago
add a comment |
$begingroup$
How's This?
I'll update when I think of a better answer
answered 14 hours ago
Joseph B.Joseph B.
1165
New contributor
Joseph B. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
1
$begingroup$
Sorry @Joseph. > or < is not what I had in mind
$endgroup$
– DEEM
14 hours ago
$begingroup$
@DEEM no worries, I'll get there
$endgroup$
– Joseph B.
14 hours ago
$begingroup$
Upvote for noticing the "letter" that can be moved. Nice.
$endgroup$
– Chris Cudmore
14 hours ago
$begingroup$
Indeed. I applaud the creativity
$endgroup$
– DEEM
14 hours ago
add a comment |
$begingroup$
I've got a solution.
Take the $M$ and split it up into four parts: one "|", one "", one "/", and another "|".
Next,
Take the "/" and the "", and put them vertically end-to-end above the "$-$" to make an (admittedly shifted) $L$.
This makes
$LI = LIII$ with two lines that we still need to use. Obviously, we throw them on the left side of the equation between the $L$ and the $I$ to get $LIII=LIII$
answered 10 hours ago
Brandon_JBrandon_J
1,842230
$endgroup$
$begingroup$
That's really stretching the meaning of "by moving exactly one letter"
$endgroup$
– Chris Cudmore
9 hours ago
$begingroup$
I suppose. @ChrisCudmore he didn't specifically say if it could be broken up or not.
$endgroup$
– Brandon_J
9 hours ago
add a comment |
Your Answer
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5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Very lateral:
Move the 'v' within the M, then flip the equation. Allow Roman on one side, Arabic on the other with ^ as the exponent sign
Giving:
answered 14 hours ago
TwoBitOperationTwoBitOperation
6,92311156
$endgroup$
$begingroup$
Ah, This makes sense given the suspicious amount of space between the 'L' and the 'I'
$endgroup$
– Joseph B.
14 hours ago
add a comment |
$begingroup$
Very lateral:
Move the 'v' within the M, then flip the equation. Allow Roman on one side, Arabic on the other with ^ as the exponent sign
Giving:
answered 14 hours ago
TwoBitOperationTwoBitOperation
6,92311156
$endgroup$
$begingroup$
Ah, This makes sense given the suspicious amount of space between the 'L' and the 'I'
$endgroup$
– Joseph B.
14 hours ago
add a comment |
$begingroup$
Very lateral:
Move the 'v' within the M, then flip the equation. Allow Roman on one side, Arabic on the other with ^ as the exponent sign
Giving:
answered 14 hours ago
TwoBitOperationTwoBitOperation
6,92311156
$endgroup$
Very lateral:
Move the 'v' within the M, then flip the equation. Allow Roman on one side, Arabic on the other with ^ as the exponent sign
Giving:
answered 14 hours ago
TwoBitOperationTwoBitOperation
6,92311156
answered 14 hours ago
TwoBitOperationTwoBitOperation
6,92311156
answered 14 hours ago
TwoBitOperationTwoBitOperation
6,92311156
answered 14 hours ago
TwoBitOperationTwoBitOperation
6,92311156
6,92311156
$begingroup$
Ah, This makes sense given the suspicious amount of space between the 'L' and the 'I'
$endgroup$
– Joseph B.
14 hours ago
add a comment |
$begingroup$
Ah, This makes sense given the suspicious amount of space between the 'L' and the 'I'
$endgroup$
– Joseph B.
14 hours ago
$begingroup$
Ah, This makes sense given the suspicious amount of space between the 'L' and the 'I'
$endgroup$
– Joseph B.
14 hours ago
$begingroup$
Ah, This makes sense given the suspicious amount of space between the 'L' and the 'I'
$endgroup$
– Joseph B.
14 hours ago
add a comment |
$begingroup$
Again very lateral:
Move the L, rotate and shrink it and stick it between the last two II's, making an M leaving I = M - IM
answered 14 hours ago
Chris CudmoreChris Cudmore
4,57711337
$endgroup$
$begingroup$
Wow. Hats off to your creativity!
$endgroup$
– DEEM
14 hours ago
add a comment |
$begingroup$
Again very lateral:
Move the L, rotate and shrink it and stick it between the last two II's, making an M leaving I = M - IM
answered 14 hours ago
Chris CudmoreChris Cudmore
4,57711337
$endgroup$
$begingroup$
Wow. Hats off to your creativity!
$endgroup$
– DEEM
14 hours ago
add a comment |
$begingroup$
Again very lateral:
Move the L, rotate and shrink it and stick it between the last two II's, making an M leaving I = M - IM
answered 14 hours ago
Chris CudmoreChris Cudmore
4,57711337
$endgroup$
Again very lateral:
Move the L, rotate and shrink it and stick it between the last two II's, making an M leaving I = M - IM
answered 14 hours ago
Chris CudmoreChris Cudmore
4,57711337
answered 14 hours ago
Chris CudmoreChris Cudmore
4,57711337
answered 14 hours ago
Chris CudmoreChris Cudmore
4,57711337
answered 14 hours ago
Chris CudmoreChris Cudmore
4,57711337
4,57711337
$begingroup$
Wow. Hats off to your creativity!
$endgroup$
– DEEM
14 hours ago
add a comment |
$begingroup$
Wow. Hats off to your creativity!
$endgroup$
– DEEM
14 hours ago
$begingroup$
Wow. Hats off to your creativity!
$endgroup$
– DEEM
14 hours ago
$begingroup$
Wow. Hats off to your creativity!
$endgroup$
– DEEM
14 hours ago
add a comment |
$begingroup$
I believe I've gotten it.
Take the bottom of L (which is a sideways letter I) and put it on top of the last I on the right (leave it sideways).
This creates: II = M - IIT
'T' is not a roman numeral, just a line above an I
A line atop a roman numeral designates that it is multiplied by 1000
The equation thus becomes 2 = 1000 - 998, which is correct
answered 12 hours ago
CrescentSickleCrescentSickle
612
New contributor
CrescentSickle is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
1
$begingroup$
This works, and I like the thinking. However, I'll be disappointed if this is the correct answer as 998 is properly written CMXCVIII -- That is your solution doesn't conform to the rules of construction.
$endgroup$
– Chris Cudmore
12 hours ago
$begingroup$
@ChrisCudmore The formatting might be another part of "lateral thinking". Just a guess.
$endgroup$
– CrescentSickle
12 hours ago
1
$begingroup$
Could be. Good answer, anyways.
$endgroup$
– Chris Cudmore
12 hours ago
add a comment |
$begingroup$
I believe I've gotten it.
Take the bottom of L (which is a sideways letter I) and put it on top of the last I on the right (leave it sideways).
This creates: II = M - IIT
'T' is not a roman numeral, just a line above an I
A line atop a roman numeral designates that it is multiplied by 1000
The equation thus becomes 2 = 1000 - 998, which is correct
answered 12 hours ago
CrescentSickleCrescentSickle
612
New contributor
CrescentSickle is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
1
$begingroup$
This works, and I like the thinking. However, I'll be disappointed if this is the correct answer as 998 is properly written CMXCVIII -- That is your solution doesn't conform to the rules of construction.
$endgroup$
– Chris Cudmore
12 hours ago
$begingroup$
@ChrisCudmore The formatting might be another part of "lateral thinking". Just a guess.
$endgroup$
– CrescentSickle
12 hours ago
1
$begingroup$
Could be. Good answer, anyways.
$endgroup$
– Chris Cudmore
12 hours ago
add a comment |
$begingroup$
I believe I've gotten it.
Take the bottom of L (which is a sideways letter I) and put it on top of the last I on the right (leave it sideways).
This creates: II = M - IIT
'T' is not a roman numeral, just a line above an I
A line atop a roman numeral designates that it is multiplied by 1000
The equation thus becomes 2 = 1000 - 998, which is correct
answered 12 hours ago
CrescentSickleCrescentSickle
612
New contributor
CrescentSickle is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I believe I've gotten it.
Take the bottom of L (which is a sideways letter I) and put it on top of the last I on the right (leave it sideways).
This creates: II = M - IIT
'T' is not a roman numeral, just a line above an I
A line atop a roman numeral designates that it is multiplied by 1000
The equation thus becomes 2 = 1000 - 998, which is correct
answered 12 hours ago
CrescentSickleCrescentSickle
612
New contributor
CrescentSickle is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 12 hours ago
CrescentSickleCrescentSickle
612
New contributor
CrescentSickle is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 12 hours ago
CrescentSickleCrescentSickle
612
answered 12 hours ago
CrescentSickleCrescentSickle
612
612
New contributor
CrescentSickle is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
CrescentSickle is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
CrescentSickle is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
$begingroup$
This works, and I like the thinking. However, I'll be disappointed if this is the correct answer as 998 is properly written CMXCVIII -- That is your solution doesn't conform to the rules of construction.
$endgroup$
– Chris Cudmore
12 hours ago
$begingroup$
@ChrisCudmore The formatting might be another part of "lateral thinking". Just a guess.
$endgroup$
– CrescentSickle
12 hours ago
1
$begingroup$
Could be. Good answer, anyways.
$endgroup$
– Chris Cudmore
12 hours ago
add a comment |
1
$begingroup$
This works, and I like the thinking. However, I'll be disappointed if this is the correct answer as 998 is properly written CMXCVIII -- That is your solution doesn't conform to the rules of construction.
$endgroup$
– Chris Cudmore
12 hours ago
$begingroup$
@ChrisCudmore The formatting might be another part of "lateral thinking". Just a guess.
$endgroup$
– CrescentSickle
12 hours ago
1
$begingroup$
Could be. Good answer, anyways.
$endgroup$
– Chris Cudmore
12 hours ago
1
1
$begingroup$
This works, and I like the thinking. However, I'll be disappointed if this is the correct answer as 998 is properly written CMXCVIII -- That is your solution doesn't conform to the rules of construction.
$endgroup$
– Chris Cudmore
12 hours ago
$begingroup$
This works, and I like the thinking. However, I'll be disappointed if this is the correct answer as 998 is properly written CMXCVIII -- That is your solution doesn't conform to the rules of construction.
$endgroup$
– Chris Cudmore
12 hours ago
$begingroup$
@ChrisCudmore The formatting might be another part of "lateral thinking". Just a guess.
$endgroup$
– CrescentSickle
12 hours ago
$begingroup$
@ChrisCudmore The formatting might be another part of "lateral thinking". Just a guess.
$endgroup$
– CrescentSickle
12 hours ago
1
1
$begingroup$
Could be. Good answer, anyways.
$endgroup$
– Chris Cudmore
12 hours ago
$begingroup$
Could be. Good answer, anyways.
$endgroup$
– Chris Cudmore
12 hours ago
add a comment |
$begingroup$
How's This?
I'll update when I think of a better answer
answered 14 hours ago
Joseph B.Joseph B.
1165
New contributor
Joseph B. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
1
$begingroup$
Sorry @Joseph. > or < is not what I had in mind
$endgroup$
– DEEM
14 hours ago
$begingroup$
@DEEM no worries, I'll get there
$endgroup$
– Joseph B.
14 hours ago
$begingroup$
Upvote for noticing the "letter" that can be moved. Nice.
$endgroup$
– Chris Cudmore
14 hours ago
$begingroup$
Indeed. I applaud the creativity
$endgroup$
– DEEM
14 hours ago
add a comment |
$begingroup$
How's This?
I'll update when I think of a better answer
answered 14 hours ago
Joseph B.Joseph B.
1165
New contributor
Joseph B. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
1
$begingroup$
Sorry @Joseph. > or < is not what I had in mind
$endgroup$
– DEEM
14 hours ago
$begingroup$
@DEEM no worries, I'll get there
$endgroup$
– Joseph B.
14 hours ago
$begingroup$
Upvote for noticing the "letter" that can be moved. Nice.
$endgroup$
– Chris Cudmore
14 hours ago
$begingroup$
Indeed. I applaud the creativity
$endgroup$
– DEEM
14 hours ago
add a comment |
$begingroup$
How's This?
I'll update when I think of a better answer
answered 14 hours ago
Joseph B.Joseph B.
1165
New contributor
Joseph B. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
How's This?
I'll update when I think of a better answer
answered 14 hours ago
Joseph B.Joseph B.
1165
New contributor
Joseph B. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 14 hours ago
Joseph B.Joseph B.
1165
New contributor
Joseph B. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 14 hours ago
Joseph B.Joseph B.
1165
answered 14 hours ago
Joseph B.Joseph B.
1165
1165
New contributor
Joseph B. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Joseph B. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Joseph B. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
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Sorry @Joseph. > or < is not what I had in mind
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– DEEM
14 hours ago
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@DEEM no worries, I'll get there
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– Joseph B.
14 hours ago
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Upvote for noticing the "letter" that can be moved. Nice.
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– Chris Cudmore
14 hours ago
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Indeed. I applaud the creativity
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– DEEM
14 hours ago
add a comment |
1
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Sorry @Joseph. > or < is not what I had in mind
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– DEEM
14 hours ago
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@DEEM no worries, I'll get there
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– Joseph B.
14 hours ago
$begingroup$
Upvote for noticing the "letter" that can be moved. Nice.
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– Chris Cudmore
14 hours ago
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Indeed. I applaud the creativity
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– DEEM
14 hours ago
1
1
$begingroup$
Sorry @Joseph. > or < is not what I had in mind
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– DEEM
14 hours ago
$begingroup$
Sorry @Joseph. > or < is not what I had in mind
$endgroup$
– DEEM
14 hours ago
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@DEEM no worries, I'll get there
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– Joseph B.
14 hours ago
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@DEEM no worries, I'll get there
$endgroup$
– Joseph B.
14 hours ago
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Upvote for noticing the "letter" that can be moved. Nice.
$endgroup$
– Chris Cudmore
14 hours ago
$begingroup$
Upvote for noticing the "letter" that can be moved. Nice.
$endgroup$
– Chris Cudmore
14 hours ago
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Indeed. I applaud the creativity
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– DEEM
14 hours ago
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Indeed. I applaud the creativity
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– DEEM
14 hours ago
add a comment |
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I've got a solution.
Take the $M$ and split it up into four parts: one "|", one "", one "/", and another "|".
Next,
Take the "/" and the "", and put them vertically end-to-end above the "$-$" to make an (admittedly shifted) $L$.
This makes
$LI = LIII$ with two lines that we still need to use. Obviously, we throw them on the left side of the equation between the $L$ and the $I$ to get $LIII=LIII$
answered 10 hours ago
Brandon_JBrandon_J
1,842230
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That's really stretching the meaning of "by moving exactly one letter"
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– Chris Cudmore
9 hours ago
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I suppose. @ChrisCudmore he didn't specifically say if it could be broken up or not.
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– Brandon_J
9 hours ago
add a comment |
$begingroup$
I've got a solution.
Take the $M$ and split it up into four parts: one "|", one "", one "/", and another "|".
Next,
Take the "/" and the "", and put them vertically end-to-end above the "$-$" to make an (admittedly shifted) $L$.
This makes
$LI = LIII$ with two lines that we still need to use. Obviously, we throw them on the left side of the equation between the $L$ and the $I$ to get $LIII=LIII$
answered 10 hours ago
Brandon_JBrandon_J
1,842230
$endgroup$
$begingroup$
That's really stretching the meaning of "by moving exactly one letter"
$endgroup$
– Chris Cudmore
9 hours ago
$begingroup$
I suppose. @ChrisCudmore he didn't specifically say if it could be broken up or not.
$endgroup$
– Brandon_J
9 hours ago
add a comment |
$begingroup$
I've got a solution.
Take the $M$ and split it up into four parts: one "|", one "", one "/", and another "|".
Next,
Take the "/" and the "", and put them vertically end-to-end above the "$-$" to make an (admittedly shifted) $L$.
This makes
$LI = LIII$ with two lines that we still need to use. Obviously, we throw them on the left side of the equation between the $L$ and the $I$ to get $LIII=LIII$
answered 10 hours ago
Brandon_JBrandon_J
1,842230
$endgroup$
I've got a solution.
Take the $M$ and split it up into four parts: one "|", one "", one "/", and another "|".
Next,
Take the "/" and the "", and put them vertically end-to-end above the "$-$" to make an (admittedly shifted) $L$.
This makes
$LI = LIII$ with two lines that we still need to use. Obviously, we throw them on the left side of the equation between the $L$ and the $I$ to get $LIII=LIII$
answered 10 hours ago
Brandon_JBrandon_J
1,842230
answered 10 hours ago
Brandon_JBrandon_J
1,842230
answered 10 hours ago
Brandon_JBrandon_J
1,842230
answered 10 hours ago
Brandon_JBrandon_J
1,842230
1,842230
$begingroup$
That's really stretching the meaning of "by moving exactly one letter"
$endgroup$
– Chris Cudmore
9 hours ago
$begingroup$
I suppose. @ChrisCudmore he didn't specifically say if it could be broken up or not.
$endgroup$
– Brandon_J
9 hours ago
add a comment |
$begingroup$
That's really stretching the meaning of "by moving exactly one letter"
$endgroup$
– Chris Cudmore
9 hours ago
$begingroup$
I suppose. @ChrisCudmore he didn't specifically say if it could be broken up or not.
$endgroup$
– Brandon_J
9 hours ago
$begingroup$
That's really stretching the meaning of "by moving exactly one letter"
$endgroup$
– Chris Cudmore
9 hours ago
$begingroup$
That's really stretching the meaning of "by moving exactly one letter"
$endgroup$
– Chris Cudmore
9 hours ago
$begingroup$
I suppose. @ChrisCudmore he didn't specifically say if it could be broken up or not.
$endgroup$
– Brandon_J
9 hours ago
$begingroup$
I suppose. @ChrisCudmore he didn't specifically say if it could be broken up or not.
$endgroup$
– Brandon_J
9 hours ago
add a comment |
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$begingroup$
Can I move rot13(Gur yrggref Q be Z sebz lbhe hfreanzr? be gur yrggre Z sebz "Znxr gur rdhngvba...)?
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– Chris Cudmore
12 hours ago
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No I dont think that was my intention.
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– DEEM
12 hours ago
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To clarify, you mean move a single character (L, I or M) in the equation to a new location in the equation to make it valid. Would moving an I adjacent to another I to make a V or X be valid? Does the construction have to be valid? i.e. IM for 999 is not a valid Roman Numeral. Do you permit it?
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– Chris Cudmore
9 hours ago
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Any single letter needs to be moved. The lateral thinking is "V" in "M " is also a letter.
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– DEEM
9 hours ago