Why does a metal block make a shrill sound but not a wooden block upon hammering?How does paper make sound...
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Why does a metal block make a shrill sound but not a wooden block upon hammering?
How does paper make sound when it is torn?Why do cold metal plate make less noise?Does sound absorption depends upon the amplitude of sound wave?Why does medium not affect the frequency of sound?Undamped oscillations of sound waveWhat is the shape of the vibration when the system is exited at off natural/resonant frequency?A metallic container when hammered deforms but a wine glass when falls or hammered breaks. Why?Why is sound produced when we hit a metal?Why does fire make very little sound?At what frequency does a string vibrate?
$begingroup$
When hammered, a metal block makes a shrill sound but not a wooden block of identical shape. Is it that the wooden block vibrates with lesser frequency than the metal block? If so, why is that? Also why is the vibration of a metallic block more visible than a wooden block? More amplitude?
solid-state-physics acoustics everyday-life elasticity vibrations
asked 15 hours ago
mithusengupta123mithusengupta123
1,25511436
$endgroup$
add a comment |
$begingroup$
When hammered, a metal block makes a shrill sound but not a wooden block of identical shape. Is it that the wooden block vibrates with lesser frequency than the metal block? If so, why is that? Also why is the vibration of a metallic block more visible than a wooden block? More amplitude?
solid-state-physics acoustics everyday-life elasticity vibrations
asked 15 hours ago
mithusengupta123mithusengupta123
1,25511436
$endgroup$
add a comment |
$begingroup$
When hammered, a metal block makes a shrill sound but not a wooden block of identical shape. Is it that the wooden block vibrates with lesser frequency than the metal block? If so, why is that? Also why is the vibration of a metallic block more visible than a wooden block? More amplitude?
solid-state-physics acoustics everyday-life elasticity vibrations
asked 15 hours ago
mithusengupta123mithusengupta123
1,25511436
$endgroup$
When hammered, a metal block makes a shrill sound but not a wooden block of identical shape. Is it that the wooden block vibrates with lesser frequency than the metal block? If so, why is that? Also why is the vibration of a metallic block more visible than a wooden block? More amplitude?
solid-state-physics acoustics everyday-life elasticity vibrations
solid-state-physics acoustics everyday-life elasticity vibrations
asked 15 hours ago
mithusengupta123mithusengupta123
1,25511436
asked 15 hours ago
mithusengupta123mithusengupta123
1,25511436
edited 15 hours ago
mithusengupta123
asked 15 hours ago
mithusengupta123mithusengupta123
1,25511436
asked 15 hours ago
mithusengupta123mithusengupta123
1,25511436
asked 15 hours ago
mithusengupta123mithusengupta123
1,25511436
1,25511436
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Is it that the wooden block vibrates with lesser frequency than the
metal block? If so, why is that?
'Yes', to the first question.
Metal is stiffer than wood and produces higher frequencies (higher pitch).
This follows from the wave equation (here in one dimension):
$$u_{tt}=frac{E}{rho}u_{xx}$$
$E$ is Young's Modulus and $rho$ the material's density.
When solved, the solution contains a time-dependent factor like this:
$$cosBig(frac{npi ct}{L}Big)$$
where $n=1,2,3,...$, and $c=sqrt{frac{E}{rho}}$ and $L$ a chracteristic length (e.g. the length of a clamped string).
To find the frequencies:
$$cos omega t=cosBig(frac{npi ct}{L}Big)$$
$$omega=2pi f=frac{npi c}{L}$$
$$f=frac{n}{2L}sqrt{frac{E}{rho}}$$
The fundamental frequency (for $n=1$) is given by:
$$f_1=frac{1}{2L}sqrt{frac{E}{rho}}$$
So for stiffer materials, i.e. larger $E$, the fundamental frequency (as well as the harmonics) is higher.
answered 14 hours ago
GertGert
17.8k32960
$endgroup$
$begingroup$
Thanks. How will this change if instead of a string I consider a metallic block? Why is the vibration of metal block more visible than the wooden block? Why more amplitude?
$endgroup$
– mithusengupta123
14 hours ago
$begingroup$
The principle that applies to a string also applies to other shapes/objects. The amplitude should mainly depend on how much energy was put in initially, i.e. how hard the block was struck.
$endgroup$
– Gert
14 hours ago
$begingroup$
I meant subjected to the same supply of energy i,e., same way of hammering on two blocks of identical shape, one of wood and the other of a metal.
$endgroup$
– mithusengupta123
13 hours ago
$begingroup$
@mithusengupta123 Same reason, frequencies. Higher frequency = shorter wavelength, so for a block of wood, it bends a lot less (also damping as in other answers)
$endgroup$
– somebody
4 hours ago
add a comment |
$begingroup$
The metal block has a relatively low level of internal damping, however the wooden block has a high level of internal damping: Much of the energy imparted to the wooden block is dissipated internally as heat and deformation, also the higher frequencies are damped more than the lower frequencies (it acts like a low pass filter).
So the wooden block will vibrate with fewer harmonics (hence less shrill) and also with lower amplitude (and also with lower duration).
answered 13 hours ago
user45664user45664
1,1282824
$endgroup$
1
$begingroup$
Hmm. The way humans perceive a note's pitch is by the fundamental frequency of the note. Filtering out more or less higher harmonics doesn't change the pitch, it only changes the timbre. That why a particular note played on a piano and a clarinet sound differently, even if the pitch remains the same.
$endgroup$
– Gert
12 hours ago
$begingroup$
Good catch--I edited my answer.
$endgroup$
– user45664
10 hours ago
$begingroup$
Why though: Because of the way the atoms are arranged. And without a crystalline structure (as all metals have), it's not going to sound very good.
$endgroup$
– Mazura
4 hours ago
$begingroup$
@Mazura You don't even need a crystalline structure, just any kind of regular structure (at least, I think so?)
$endgroup$
– somebody
4 hours ago
$begingroup$
@somebody - If you're making a bell and you want it to sound good you have to use copper. And if you don't want it to break you have to add tin, to turn it into bronze. Why copper is the best is because of the way the atoms are arranged. Adding tin adds a damper in between atoms of copper. NOVA, S39E08 shows this with cgi.
$endgroup$
– Mazura
4 hours ago
|
show 1 more comment
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Is it that the wooden block vibrates with lesser frequency than the
metal block? If so, why is that?
'Yes', to the first question.
Metal is stiffer than wood and produces higher frequencies (higher pitch).
This follows from the wave equation (here in one dimension):
$$u_{tt}=frac{E}{rho}u_{xx}$$
$E$ is Young's Modulus and $rho$ the material's density.
When solved, the solution contains a time-dependent factor like this:
$$cosBig(frac{npi ct}{L}Big)$$
where $n=1,2,3,...$, and $c=sqrt{frac{E}{rho}}$ and $L$ a chracteristic length (e.g. the length of a clamped string).
To find the frequencies:
$$cos omega t=cosBig(frac{npi ct}{L}Big)$$
$$omega=2pi f=frac{npi c}{L}$$
$$f=frac{n}{2L}sqrt{frac{E}{rho}}$$
The fundamental frequency (for $n=1$) is given by:
$$f_1=frac{1}{2L}sqrt{frac{E}{rho}}$$
So for stiffer materials, i.e. larger $E$, the fundamental frequency (as well as the harmonics) is higher.
answered 14 hours ago
GertGert
17.8k32960
$endgroup$
$begingroup$
Thanks. How will this change if instead of a string I consider a metallic block? Why is the vibration of metal block more visible than the wooden block? Why more amplitude?
$endgroup$
– mithusengupta123
14 hours ago
$begingroup$
The principle that applies to a string also applies to other shapes/objects. The amplitude should mainly depend on how much energy was put in initially, i.e. how hard the block was struck.
$endgroup$
– Gert
14 hours ago
$begingroup$
I meant subjected to the same supply of energy i,e., same way of hammering on two blocks of identical shape, one of wood and the other of a metal.
$endgroup$
– mithusengupta123
13 hours ago
$begingroup$
@mithusengupta123 Same reason, frequencies. Higher frequency = shorter wavelength, so for a block of wood, it bends a lot less (also damping as in other answers)
$endgroup$
– somebody
4 hours ago
add a comment |
$begingroup$
Is it that the wooden block vibrates with lesser frequency than the
metal block? If so, why is that?
'Yes', to the first question.
Metal is stiffer than wood and produces higher frequencies (higher pitch).
This follows from the wave equation (here in one dimension):
$$u_{tt}=frac{E}{rho}u_{xx}$$
$E$ is Young's Modulus and $rho$ the material's density.
When solved, the solution contains a time-dependent factor like this:
$$cosBig(frac{npi ct}{L}Big)$$
where $n=1,2,3,...$, and $c=sqrt{frac{E}{rho}}$ and $L$ a chracteristic length (e.g. the length of a clamped string).
To find the frequencies:
$$cos omega t=cosBig(frac{npi ct}{L}Big)$$
$$omega=2pi f=frac{npi c}{L}$$
$$f=frac{n}{2L}sqrt{frac{E}{rho}}$$
The fundamental frequency (for $n=1$) is given by:
$$f_1=frac{1}{2L}sqrt{frac{E}{rho}}$$
So for stiffer materials, i.e. larger $E$, the fundamental frequency (as well as the harmonics) is higher.
answered 14 hours ago
GertGert
17.8k32960
$endgroup$
$begingroup$
Thanks. How will this change if instead of a string I consider a metallic block? Why is the vibration of metal block more visible than the wooden block? Why more amplitude?
$endgroup$
– mithusengupta123
14 hours ago
$begingroup$
The principle that applies to a string also applies to other shapes/objects. The amplitude should mainly depend on how much energy was put in initially, i.e. how hard the block was struck.
$endgroup$
– Gert
14 hours ago
$begingroup$
I meant subjected to the same supply of energy i,e., same way of hammering on two blocks of identical shape, one of wood and the other of a metal.
$endgroup$
– mithusengupta123
13 hours ago
$begingroup$
@mithusengupta123 Same reason, frequencies. Higher frequency = shorter wavelength, so for a block of wood, it bends a lot less (also damping as in other answers)
$endgroup$
– somebody
4 hours ago
add a comment |
$begingroup$
Is it that the wooden block vibrates with lesser frequency than the
metal block? If so, why is that?
'Yes', to the first question.
Metal is stiffer than wood and produces higher frequencies (higher pitch).
This follows from the wave equation (here in one dimension):
$$u_{tt}=frac{E}{rho}u_{xx}$$
$E$ is Young's Modulus and $rho$ the material's density.
When solved, the solution contains a time-dependent factor like this:
$$cosBig(frac{npi ct}{L}Big)$$
where $n=1,2,3,...$, and $c=sqrt{frac{E}{rho}}$ and $L$ a chracteristic length (e.g. the length of a clamped string).
To find the frequencies:
$$cos omega t=cosBig(frac{npi ct}{L}Big)$$
$$omega=2pi f=frac{npi c}{L}$$
$$f=frac{n}{2L}sqrt{frac{E}{rho}}$$
The fundamental frequency (for $n=1$) is given by:
$$f_1=frac{1}{2L}sqrt{frac{E}{rho}}$$
So for stiffer materials, i.e. larger $E$, the fundamental frequency (as well as the harmonics) is higher.
answered 14 hours ago
GertGert
17.8k32960
$endgroup$
Is it that the wooden block vibrates with lesser frequency than the
metal block? If so, why is that?
'Yes', to the first question.
Metal is stiffer than wood and produces higher frequencies (higher pitch).
This follows from the wave equation (here in one dimension):
$$u_{tt}=frac{E}{rho}u_{xx}$$
$E$ is Young's Modulus and $rho$ the material's density.
When solved, the solution contains a time-dependent factor like this:
$$cosBig(frac{npi ct}{L}Big)$$
where $n=1,2,3,...$, and $c=sqrt{frac{E}{rho}}$ and $L$ a chracteristic length (e.g. the length of a clamped string).
To find the frequencies:
$$cos omega t=cosBig(frac{npi ct}{L}Big)$$
$$omega=2pi f=frac{npi c}{L}$$
$$f=frac{n}{2L}sqrt{frac{E}{rho}}$$
The fundamental frequency (for $n=1$) is given by:
$$f_1=frac{1}{2L}sqrt{frac{E}{rho}}$$
So for stiffer materials, i.e. larger $E$, the fundamental frequency (as well as the harmonics) is higher.
answered 14 hours ago
GertGert
17.8k32960
edited 2 hours ago
answered 14 hours ago
GertGert
17.8k32960
answered 14 hours ago
GertGert
17.8k32960
answered 14 hours ago
GertGert
17.8k32960
17.8k32960
$begingroup$
Thanks. How will this change if instead of a string I consider a metallic block? Why is the vibration of metal block more visible than the wooden block? Why more amplitude?
$endgroup$
– mithusengupta123
14 hours ago
$begingroup$
The principle that applies to a string also applies to other shapes/objects. The amplitude should mainly depend on how much energy was put in initially, i.e. how hard the block was struck.
$endgroup$
– Gert
14 hours ago
$begingroup$
I meant subjected to the same supply of energy i,e., same way of hammering on two blocks of identical shape, one of wood and the other of a metal.
$endgroup$
– mithusengupta123
13 hours ago
$begingroup$
@mithusengupta123 Same reason, frequencies. Higher frequency = shorter wavelength, so for a block of wood, it bends a lot less (also damping as in other answers)
$endgroup$
– somebody
4 hours ago
add a comment |
$begingroup$
Thanks. How will this change if instead of a string I consider a metallic block? Why is the vibration of metal block more visible than the wooden block? Why more amplitude?
$endgroup$
– mithusengupta123
14 hours ago
$begingroup$
The principle that applies to a string also applies to other shapes/objects. The amplitude should mainly depend on how much energy was put in initially, i.e. how hard the block was struck.
$endgroup$
– Gert
14 hours ago
$begingroup$
I meant subjected to the same supply of energy i,e., same way of hammering on two blocks of identical shape, one of wood and the other of a metal.
$endgroup$
– mithusengupta123
13 hours ago
$begingroup$
@mithusengupta123 Same reason, frequencies. Higher frequency = shorter wavelength, so for a block of wood, it bends a lot less (also damping as in other answers)
$endgroup$
– somebody
4 hours ago
$begingroup$
Thanks. How will this change if instead of a string I consider a metallic block? Why is the vibration of metal block more visible than the wooden block? Why more amplitude?
$endgroup$
– mithusengupta123
14 hours ago
$begingroup$
Thanks. How will this change if instead of a string I consider a metallic block? Why is the vibration of metal block more visible than the wooden block? Why more amplitude?
$endgroup$
– mithusengupta123
14 hours ago
$begingroup$
The principle that applies to a string also applies to other shapes/objects. The amplitude should mainly depend on how much energy was put in initially, i.e. how hard the block was struck.
$endgroup$
– Gert
14 hours ago
$begingroup$
The principle that applies to a string also applies to other shapes/objects. The amplitude should mainly depend on how much energy was put in initially, i.e. how hard the block was struck.
$endgroup$
– Gert
14 hours ago
$begingroup$
I meant subjected to the same supply of energy i,e., same way of hammering on two blocks of identical shape, one of wood and the other of a metal.
$endgroup$
– mithusengupta123
13 hours ago
$begingroup$
I meant subjected to the same supply of energy i,e., same way of hammering on two blocks of identical shape, one of wood and the other of a metal.
$endgroup$
– mithusengupta123
13 hours ago
$begingroup$
@mithusengupta123 Same reason, frequencies. Higher frequency = shorter wavelength, so for a block of wood, it bends a lot less (also damping as in other answers)
$endgroup$
– somebody
4 hours ago
$begingroup$
@mithusengupta123 Same reason, frequencies. Higher frequency = shorter wavelength, so for a block of wood, it bends a lot less (also damping as in other answers)
$endgroup$
– somebody
4 hours ago
add a comment |
$begingroup$
The metal block has a relatively low level of internal damping, however the wooden block has a high level of internal damping: Much of the energy imparted to the wooden block is dissipated internally as heat and deformation, also the higher frequencies are damped more than the lower frequencies (it acts like a low pass filter).
So the wooden block will vibrate with fewer harmonics (hence less shrill) and also with lower amplitude (and also with lower duration).
answered 13 hours ago
user45664user45664
1,1282824
$endgroup$
1
$begingroup$
Hmm. The way humans perceive a note's pitch is by the fundamental frequency of the note. Filtering out more or less higher harmonics doesn't change the pitch, it only changes the timbre. That why a particular note played on a piano and a clarinet sound differently, even if the pitch remains the same.
$endgroup$
– Gert
12 hours ago
$begingroup$
Good catch--I edited my answer.
$endgroup$
– user45664
10 hours ago
$begingroup$
Why though: Because of the way the atoms are arranged. And without a crystalline structure (as all metals have), it's not going to sound very good.
$endgroup$
– Mazura
4 hours ago
$begingroup$
@Mazura You don't even need a crystalline structure, just any kind of regular structure (at least, I think so?)
$endgroup$
– somebody
4 hours ago
$begingroup$
@somebody - If you're making a bell and you want it to sound good you have to use copper. And if you don't want it to break you have to add tin, to turn it into bronze. Why copper is the best is because of the way the atoms are arranged. Adding tin adds a damper in between atoms of copper. NOVA, S39E08 shows this with cgi.
$endgroup$
– Mazura
4 hours ago
|
show 1 more comment
$begingroup$
The metal block has a relatively low level of internal damping, however the wooden block has a high level of internal damping: Much of the energy imparted to the wooden block is dissipated internally as heat and deformation, also the higher frequencies are damped more than the lower frequencies (it acts like a low pass filter).
So the wooden block will vibrate with fewer harmonics (hence less shrill) and also with lower amplitude (and also with lower duration).
answered 13 hours ago
user45664user45664
1,1282824
$endgroup$
1
$begingroup$
Hmm. The way humans perceive a note's pitch is by the fundamental frequency of the note. Filtering out more or less higher harmonics doesn't change the pitch, it only changes the timbre. That why a particular note played on a piano and a clarinet sound differently, even if the pitch remains the same.
$endgroup$
– Gert
12 hours ago
$begingroup$
Good catch--I edited my answer.
$endgroup$
– user45664
10 hours ago
$begingroup$
Why though: Because of the way the atoms are arranged. And without a crystalline structure (as all metals have), it's not going to sound very good.
$endgroup$
– Mazura
4 hours ago
$begingroup$
@Mazura You don't even need a crystalline structure, just any kind of regular structure (at least, I think so?)
$endgroup$
– somebody
4 hours ago
$begingroup$
@somebody - If you're making a bell and you want it to sound good you have to use copper. And if you don't want it to break you have to add tin, to turn it into bronze. Why copper is the best is because of the way the atoms are arranged. Adding tin adds a damper in between atoms of copper. NOVA, S39E08 shows this with cgi.
$endgroup$
– Mazura
4 hours ago
|
show 1 more comment
$begingroup$
The metal block has a relatively low level of internal damping, however the wooden block has a high level of internal damping: Much of the energy imparted to the wooden block is dissipated internally as heat and deformation, also the higher frequencies are damped more than the lower frequencies (it acts like a low pass filter).
So the wooden block will vibrate with fewer harmonics (hence less shrill) and also with lower amplitude (and also with lower duration).
answered 13 hours ago
user45664user45664
1,1282824
$endgroup$
The metal block has a relatively low level of internal damping, however the wooden block has a high level of internal damping: Much of the energy imparted to the wooden block is dissipated internally as heat and deformation, also the higher frequencies are damped more than the lower frequencies (it acts like a low pass filter).
So the wooden block will vibrate with fewer harmonics (hence less shrill) and also with lower amplitude (and also with lower duration).
answered 13 hours ago
user45664user45664
1,1282824
edited 10 hours ago
answered 13 hours ago
user45664user45664
1,1282824
answered 13 hours ago
user45664user45664
1,1282824
answered 13 hours ago
user45664user45664
1,1282824
1,1282824
1
$begingroup$
Hmm. The way humans perceive a note's pitch is by the fundamental frequency of the note. Filtering out more or less higher harmonics doesn't change the pitch, it only changes the timbre. That why a particular note played on a piano and a clarinet sound differently, even if the pitch remains the same.
$endgroup$
– Gert
12 hours ago
$begingroup$
Good catch--I edited my answer.
$endgroup$
– user45664
10 hours ago
$begingroup$
Why though: Because of the way the atoms are arranged. And without a crystalline structure (as all metals have), it's not going to sound very good.
$endgroup$
– Mazura
4 hours ago
$begingroup$
@Mazura You don't even need a crystalline structure, just any kind of regular structure (at least, I think so?)
$endgroup$
– somebody
4 hours ago
$begingroup$
@somebody - If you're making a bell and you want it to sound good you have to use copper. And if you don't want it to break you have to add tin, to turn it into bronze. Why copper is the best is because of the way the atoms are arranged. Adding tin adds a damper in between atoms of copper. NOVA, S39E08 shows this with cgi.
$endgroup$
– Mazura
4 hours ago
|
show 1 more comment
1
$begingroup$
Hmm. The way humans perceive a note's pitch is by the fundamental frequency of the note. Filtering out more or less higher harmonics doesn't change the pitch, it only changes the timbre. That why a particular note played on a piano and a clarinet sound differently, even if the pitch remains the same.
$endgroup$
– Gert
12 hours ago
$begingroup$
Good catch--I edited my answer.
$endgroup$
– user45664
10 hours ago
$begingroup$
Why though: Because of the way the atoms are arranged. And without a crystalline structure (as all metals have), it's not going to sound very good.
$endgroup$
– Mazura
4 hours ago
$begingroup$
@Mazura You don't even need a crystalline structure, just any kind of regular structure (at least, I think so?)
$endgroup$
– somebody
4 hours ago
$begingroup$
@somebody - If you're making a bell and you want it to sound good you have to use copper. And if you don't want it to break you have to add tin, to turn it into bronze. Why copper is the best is because of the way the atoms are arranged. Adding tin adds a damper in between atoms of copper. NOVA, S39E08 shows this with cgi.
$endgroup$
– Mazura
4 hours ago
1
1
$begingroup$
Hmm. The way humans perceive a note's pitch is by the fundamental frequency of the note. Filtering out more or less higher harmonics doesn't change the pitch, it only changes the timbre. That why a particular note played on a piano and a clarinet sound differently, even if the pitch remains the same.
$endgroup$
– Gert
12 hours ago
$begingroup$
Hmm. The way humans perceive a note's pitch is by the fundamental frequency of the note. Filtering out more or less higher harmonics doesn't change the pitch, it only changes the timbre. That why a particular note played on a piano and a clarinet sound differently, even if the pitch remains the same.
$endgroup$
– Gert
12 hours ago
$begingroup$
Good catch--I edited my answer.
$endgroup$
– user45664
10 hours ago
$begingroup$
Good catch--I edited my answer.
$endgroup$
– user45664
10 hours ago
$begingroup$
Why though: Because of the way the atoms are arranged. And without a crystalline structure (as all metals have), it's not going to sound very good.
$endgroup$
– Mazura
4 hours ago
$begingroup$
Why though: Because of the way the atoms are arranged. And without a crystalline structure (as all metals have), it's not going to sound very good.
$endgroup$
– Mazura
4 hours ago
$begingroup$
@Mazura You don't even need a crystalline structure, just any kind of regular structure (at least, I think so?)
$endgroup$
– somebody
4 hours ago
$begingroup$
@Mazura You don't even need a crystalline structure, just any kind of regular structure (at least, I think so?)
$endgroup$
– somebody
4 hours ago
$begingroup$
@somebody - If you're making a bell and you want it to sound good you have to use copper. And if you don't want it to break you have to add tin, to turn it into bronze. Why copper is the best is because of the way the atoms are arranged. Adding tin adds a damper in between atoms of copper. NOVA, S39E08 shows this with cgi.
$endgroup$
– Mazura
4 hours ago
$begingroup$
@somebody - If you're making a bell and you want it to sound good you have to use copper. And if you don't want it to break you have to add tin, to turn it into bronze. Why copper is the best is because of the way the atoms are arranged. Adding tin adds a damper in between atoms of copper. NOVA, S39E08 shows this with cgi.
$endgroup$
– Mazura
4 hours ago
|
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