Compares 2 ios and android versions Announcing the arrival of Valued Associate #679: Cesar...
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Compares 2 ios and android versions
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}
$begingroup$
Please review and let me know which version is better?
Just trying to find any caveats or better ways to accomplish the a version comparison independent from android and ios.
Formats accepted: '1.0.0' or '1' formats and an operator, e.g: compareVersion('1', '1.2.0', '>')
export function compareVersion(version1, version2, operator) {
const formattedV1 = version1.split(".");
const formattedV2 = version2.split(".");
let diff = 0;
if (formattedV1.length !== formattedV2.length) {
const lengthDiff = formattedV1.length - formattedV2.length;
for (let index = 0; index < Math.abs(lengthDiff); index += 1) {
if (lengthDiff > 0) {
formattedV2.push("0");
} else {
formattedV1.push("0");
}
}
}
for (let index = 0; index < formattedV1.length; index += 1) {
if (diff === 0) {
const v1 = parseInt(formattedV1[index]);
const v2 = parseInt(formattedV2[index]);
if (isNaN(v1) || isNaN(v2)) {
throw new Error("Problem comparing versions: not a valid number");
}
if (v1 < v2) {
diff = -1;
}
if (v1 > v2) {
diff = 1;
}
}
}
switch (operator) {
case "=":
case "==":
return diff === 0;
case ">=":
return diff >= 0;
case "<=":
return diff <= 0;
case ">":
return diff > 0;
case "<":
return diff < 0;
default:
throw new Error("Problem comparing versions");
}
}
OR
export function compareVersions(a, b, operator) {
const aParts = a.split('.');
const bParts = b.split('.');
const pairs = [];
for (let index = 0; index < Math.max(aParts.length, bParts.length); index += 1) {
pairs.push({
a: parseInt(aParts[index]),
b: parseInt(bParts[index]),
});
}
let diff = 0;
pairs.forEach((pair) => {
if (diff === 0) {
if (pair.a > pair.b) {
diff = 1;
}
if (pair.b > pair.a) {
diff = -1;
}
if (!isNaN(pair.a) && isNaN(pair.b)) {
diff = 1;
}
if (isNaN(pair.a) && !isNaN(pair.b)) {
diff = -1;
}
}
});
switch (operator) {
case '=':
case '==':
return diff === 0;
case '>=':
return diff >= 0;
case '<=':
return diff <= 0;
case '>':
return diff > 0;
case '<':
return diff < 0;
default:
throw new Error('Problem comparing versions');
}
}
javascript beginner react-native
asked 3 mins ago
VincentVincent
1
New contributor
Vincent is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Please review and let me know which version is better?
Just trying to find any caveats or better ways to accomplish the a version comparison independent from android and ios.
Formats accepted: '1.0.0' or '1' formats and an operator, e.g: compareVersion('1', '1.2.0', '>')
export function compareVersion(version1, version2, operator) {
const formattedV1 = version1.split(".");
const formattedV2 = version2.split(".");
let diff = 0;
if (formattedV1.length !== formattedV2.length) {
const lengthDiff = formattedV1.length - formattedV2.length;
for (let index = 0; index < Math.abs(lengthDiff); index += 1) {
if (lengthDiff > 0) {
formattedV2.push("0");
} else {
formattedV1.push("0");
}
}
}
for (let index = 0; index < formattedV1.length; index += 1) {
if (diff === 0) {
const v1 = parseInt(formattedV1[index]);
const v2 = parseInt(formattedV2[index]);
if (isNaN(v1) || isNaN(v2)) {
throw new Error("Problem comparing versions: not a valid number");
}
if (v1 < v2) {
diff = -1;
}
if (v1 > v2) {
diff = 1;
}
}
}
switch (operator) {
case "=":
case "==":
return diff === 0;
case ">=":
return diff >= 0;
case "<=":
return diff <= 0;
case ">":
return diff > 0;
case "<":
return diff < 0;
default:
throw new Error("Problem comparing versions");
}
}
OR
export function compareVersions(a, b, operator) {
const aParts = a.split('.');
const bParts = b.split('.');
const pairs = [];
for (let index = 0; index < Math.max(aParts.length, bParts.length); index += 1) {
pairs.push({
a: parseInt(aParts[index]),
b: parseInt(bParts[index]),
});
}
let diff = 0;
pairs.forEach((pair) => {
if (diff === 0) {
if (pair.a > pair.b) {
diff = 1;
}
if (pair.b > pair.a) {
diff = -1;
}
if (!isNaN(pair.a) && isNaN(pair.b)) {
diff = 1;
}
if (isNaN(pair.a) && !isNaN(pair.b)) {
diff = -1;
}
}
});
switch (operator) {
case '=':
case '==':
return diff === 0;
case '>=':
return diff >= 0;
case '<=':
return diff <= 0;
case '>':
return diff > 0;
case '<':
return diff < 0;
default:
throw new Error('Problem comparing versions');
}
}
javascript beginner react-native
asked 3 mins ago
VincentVincent
1
New contributor
Vincent is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Please review and let me know which version is better?
Just trying to find any caveats or better ways to accomplish the a version comparison independent from android and ios.
Formats accepted: '1.0.0' or '1' formats and an operator, e.g: compareVersion('1', '1.2.0', '>')
export function compareVersion(version1, version2, operator) {
const formattedV1 = version1.split(".");
const formattedV2 = version2.split(".");
let diff = 0;
if (formattedV1.length !== formattedV2.length) {
const lengthDiff = formattedV1.length - formattedV2.length;
for (let index = 0; index < Math.abs(lengthDiff); index += 1) {
if (lengthDiff > 0) {
formattedV2.push("0");
} else {
formattedV1.push("0");
}
}
}
for (let index = 0; index < formattedV1.length; index += 1) {
if (diff === 0) {
const v1 = parseInt(formattedV1[index]);
const v2 = parseInt(formattedV2[index]);
if (isNaN(v1) || isNaN(v2)) {
throw new Error("Problem comparing versions: not a valid number");
}
if (v1 < v2) {
diff = -1;
}
if (v1 > v2) {
diff = 1;
}
}
}
switch (operator) {
case "=":
case "==":
return diff === 0;
case ">=":
return diff >= 0;
case "<=":
return diff <= 0;
case ">":
return diff > 0;
case "<":
return diff < 0;
default:
throw new Error("Problem comparing versions");
}
}
OR
export function compareVersions(a, b, operator) {
const aParts = a.split('.');
const bParts = b.split('.');
const pairs = [];
for (let index = 0; index < Math.max(aParts.length, bParts.length); index += 1) {
pairs.push({
a: parseInt(aParts[index]),
b: parseInt(bParts[index]),
});
}
let diff = 0;
pairs.forEach((pair) => {
if (diff === 0) {
if (pair.a > pair.b) {
diff = 1;
}
if (pair.b > pair.a) {
diff = -1;
}
if (!isNaN(pair.a) && isNaN(pair.b)) {
diff = 1;
}
if (isNaN(pair.a) && !isNaN(pair.b)) {
diff = -1;
}
}
});
switch (operator) {
case '=':
case '==':
return diff === 0;
case '>=':
return diff >= 0;
case '<=':
return diff <= 0;
case '>':
return diff > 0;
case '<':
return diff < 0;
default:
throw new Error('Problem comparing versions');
}
}
javascript beginner react-native
asked 3 mins ago
VincentVincent
1
New contributor
Vincent is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Please review and let me know which version is better?
Just trying to find any caveats or better ways to accomplish the a version comparison independent from android and ios.
Formats accepted: '1.0.0' or '1' formats and an operator, e.g: compareVersion('1', '1.2.0', '>')
export function compareVersion(version1, version2, operator) {
const formattedV1 = version1.split(".");
const formattedV2 = version2.split(".");
let diff = 0;
if (formattedV1.length !== formattedV2.length) {
const lengthDiff = formattedV1.length - formattedV2.length;
for (let index = 0; index < Math.abs(lengthDiff); index += 1) {
if (lengthDiff > 0) {
formattedV2.push("0");
} else {
formattedV1.push("0");
}
}
}
for (let index = 0; index < formattedV1.length; index += 1) {
if (diff === 0) {
const v1 = parseInt(formattedV1[index]);
const v2 = parseInt(formattedV2[index]);
if (isNaN(v1) || isNaN(v2)) {
throw new Error("Problem comparing versions: not a valid number");
}
if (v1 < v2) {
diff = -1;
}
if (v1 > v2) {
diff = 1;
}
}
}
switch (operator) {
case "=":
case "==":
return diff === 0;
case ">=":
return diff >= 0;
case "<=":
return diff <= 0;
case ">":
return diff > 0;
case "<":
return diff < 0;
default:
throw new Error("Problem comparing versions");
}
}
OR
export function compareVersions(a, b, operator) {
const aParts = a.split('.');
const bParts = b.split('.');
const pairs = [];
for (let index = 0; index < Math.max(aParts.length, bParts.length); index += 1) {
pairs.push({
a: parseInt(aParts[index]),
b: parseInt(bParts[index]),
});
}
let diff = 0;
pairs.forEach((pair) => {
if (diff === 0) {
if (pair.a > pair.b) {
diff = 1;
}
if (pair.b > pair.a) {
diff = -1;
}
if (!isNaN(pair.a) && isNaN(pair.b)) {
diff = 1;
}
if (isNaN(pair.a) && !isNaN(pair.b)) {
diff = -1;
}
}
});
switch (operator) {
case '=':
case '==':
return diff === 0;
case '>=':
return diff >= 0;
case '<=':
return diff <= 0;
case '>':
return diff > 0;
case '<':
return diff < 0;
default:
throw new Error('Problem comparing versions');
}
}
javascript beginner react-native
javascript beginner react-native
asked 3 mins ago
VincentVincent
1
New contributor
Vincent is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 3 mins ago
VincentVincent
1
New contributor
Vincent is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 3 mins ago
VincentVincent
1
New contributor
Vincent is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 3 mins ago
VincentVincent
1
asked 3 mins ago
VincentVincent
1
1
New contributor
Vincent is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Vincent is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Vincent is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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Vincent is a new contributor. Be nice, and check out our Code of Conduct.
Vincent is a new contributor. Be nice, and check out our Code of Conduct.
Vincent is a new contributor. Be nice, and check out our Code of Conduct.
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