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Sort numbers based on the user input



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Simple Lotto GameGeneric Pairing Heap Performance





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$begingroup$


The purpose of the my program is to sort numbers based on the user input. Everything works perfectly, until user wants to input more than 6 data (inp = 5) and I am not sure why is it happening. Can you review it for best coding practices?



Code



#include <stdio.h>
#include <stdlib.h>

int size =0;

void ascSort(int a[size], int size, int temp) {
for(int i=1; i< size; i++){
for(int j=i; j>0; j--){
if(a[j-1]>a[j]){
temp = a[j-1];
a[j-1] = a[j];
a[j] = temp;
}
}
}
}

void descSort(int a[size], int size, int temp) {
for(int i=1; i< size; i++){
for(int j=i; j>0; j--){
if(a[j-1]<a[j]){
temp = a[j-1];
a[j-1] = a[j];
a[j] = temp;
}
}
}
}
int main(){
char inpChar, isContinue='y';
int inp, temp=0;
int a[size];

do {
printf("How many numbers would you like to sort?n");
fflush(stdin);
scanf("%d", &inp);
size = inp;

printf("%dn", size);

for(int i=0; i<size; i++){
//Below, I am printing 'size' for debugging purposes
printf("Type %d more numbers to sort ---- '%d'n", inp, size);
fflush(stdin);
scanf("%d", &a[i]);
inp--;
}
printf("Please input a for ascending order and d for descending ordern");
fflush(stdin);
scanf(" %c", &inpChar);

switch (inpChar) {
case 'a':
ascSort(a, size, temp);
break;
case 'd':
descSort(a, size, temp);
break;
default: printf("Invalid charactern");
}

printf("Sorted Array: n" );
for(int i=0; i<size; i++){
printf("%dn", a[i]);
}
printf("Do you want to repeat? Type y/nn");
fflush(stdin);
scanf(" %c", &isContinue);
} while(isContinue != 'n');

}









share|improve this question









New contributor




Gaous Muhammad Saklaen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$








  • 1




    $begingroup$
    Thanks a lot. Gonna do it now. Didn't know that before, by the way.
    $endgroup$
    – Gaous Muhammad Saklaen
    6 mins ago










  • $begingroup$
    You're very welcome!
    $endgroup$
    – Emma
    4 mins ago


















0












$begingroup$


The purpose of the my program is to sort numbers based on the user input. Everything works perfectly, until user wants to input more than 6 data (inp = 5) and I am not sure why is it happening. Can you review it for best coding practices?



Code



#include <stdio.h>
#include <stdlib.h>

int size =0;

void ascSort(int a[size], int size, int temp) {
for(int i=1; i< size; i++){
for(int j=i; j>0; j--){
if(a[j-1]>a[j]){
temp = a[j-1];
a[j-1] = a[j];
a[j] = temp;
}
}
}
}

void descSort(int a[size], int size, int temp) {
for(int i=1; i< size; i++){
for(int j=i; j>0; j--){
if(a[j-1]<a[j]){
temp = a[j-1];
a[j-1] = a[j];
a[j] = temp;
}
}
}
}
int main(){
char inpChar, isContinue='y';
int inp, temp=0;
int a[size];

do {
printf("How many numbers would you like to sort?n");
fflush(stdin);
scanf("%d", &inp);
size = inp;

printf("%dn", size);

for(int i=0; i<size; i++){
//Below, I am printing 'size' for debugging purposes
printf("Type %d more numbers to sort ---- '%d'n", inp, size);
fflush(stdin);
scanf("%d", &a[i]);
inp--;
}
printf("Please input a for ascending order and d for descending ordern");
fflush(stdin);
scanf(" %c", &inpChar);

switch (inpChar) {
case 'a':
ascSort(a, size, temp);
break;
case 'd':
descSort(a, size, temp);
break;
default: printf("Invalid charactern");
}

printf("Sorted Array: n" );
for(int i=0; i<size; i++){
printf("%dn", a[i]);
}
printf("Do you want to repeat? Type y/nn");
fflush(stdin);
scanf(" %c", &isContinue);
} while(isContinue != 'n');

}









share|improve this question









New contributor




Gaous Muhammad Saklaen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$








  • 1




    $begingroup$
    Thanks a lot. Gonna do it now. Didn't know that before, by the way.
    $endgroup$
    – Gaous Muhammad Saklaen
    6 mins ago










  • $begingroup$
    You're very welcome!
    $endgroup$
    – Emma
    4 mins ago














0












0








0


0



$begingroup$


The purpose of the my program is to sort numbers based on the user input. Everything works perfectly, until user wants to input more than 6 data (inp = 5) and I am not sure why is it happening. Can you review it for best coding practices?



Code



#include <stdio.h>
#include <stdlib.h>

int size =0;

void ascSort(int a[size], int size, int temp) {
for(int i=1; i< size; i++){
for(int j=i; j>0; j--){
if(a[j-1]>a[j]){
temp = a[j-1];
a[j-1] = a[j];
a[j] = temp;
}
}
}
}

void descSort(int a[size], int size, int temp) {
for(int i=1; i< size; i++){
for(int j=i; j>0; j--){
if(a[j-1]<a[j]){
temp = a[j-1];
a[j-1] = a[j];
a[j] = temp;
}
}
}
}
int main(){
char inpChar, isContinue='y';
int inp, temp=0;
int a[size];

do {
printf("How many numbers would you like to sort?n");
fflush(stdin);
scanf("%d", &inp);
size = inp;

printf("%dn", size);

for(int i=0; i<size; i++){
//Below, I am printing 'size' for debugging purposes
printf("Type %d more numbers to sort ---- '%d'n", inp, size);
fflush(stdin);
scanf("%d", &a[i]);
inp--;
}
printf("Please input a for ascending order and d for descending ordern");
fflush(stdin);
scanf(" %c", &inpChar);

switch (inpChar) {
case 'a':
ascSort(a, size, temp);
break;
case 'd':
descSort(a, size, temp);
break;
default: printf("Invalid charactern");
}

printf("Sorted Array: n" );
for(int i=0; i<size; i++){
printf("%dn", a[i]);
}
printf("Do you want to repeat? Type y/nn");
fflush(stdin);
scanf(" %c", &isContinue);
} while(isContinue != 'n');

}









share|improve this question









New contributor




Gaous Muhammad Saklaen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




The purpose of the my program is to sort numbers based on the user input. Everything works perfectly, until user wants to input more than 6 data (inp = 5) and I am not sure why is it happening. Can you review it for best coding practices?



Code



#include <stdio.h>
#include <stdlib.h>

int size =0;

void ascSort(int a[size], int size, int temp) {
for(int i=1; i< size; i++){
for(int j=i; j>0; j--){
if(a[j-1]>a[j]){
temp = a[j-1];
a[j-1] = a[j];
a[j] = temp;
}
}
}
}

void descSort(int a[size], int size, int temp) {
for(int i=1; i< size; i++){
for(int j=i; j>0; j--){
if(a[j-1]<a[j]){
temp = a[j-1];
a[j-1] = a[j];
a[j] = temp;
}
}
}
}
int main(){
char inpChar, isContinue='y';
int inp, temp=0;
int a[size];

do {
printf("How many numbers would you like to sort?n");
fflush(stdin);
scanf("%d", &inp);
size = inp;

printf("%dn", size);

for(int i=0; i<size; i++){
//Below, I am printing 'size' for debugging purposes
printf("Type %d more numbers to sort ---- '%d'n", inp, size);
fflush(stdin);
scanf("%d", &a[i]);
inp--;
}
printf("Please input a for ascending order and d for descending ordern");
fflush(stdin);
scanf(" %c", &inpChar);

switch (inpChar) {
case 'a':
ascSort(a, size, temp);
break;
case 'd':
descSort(a, size, temp);
break;
default: printf("Invalid charactern");
}

printf("Sorted Array: n" );
for(int i=0; i<size; i++){
printf("%dn", a[i]);
}
printf("Do you want to repeat? Type y/nn");
fflush(stdin);
scanf(" %c", &isContinue);
} while(isContinue != 'n');

}






c






share|improve this question









New contributor




Gaous Muhammad Saklaen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




Gaous Muhammad Saklaen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited 10 mins ago









Emma

2021215




2021215






New contributor




Gaous Muhammad Saklaen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 43 mins ago









Gaous Muhammad SaklaenGaous Muhammad Saklaen

12




12




New contributor




Gaous Muhammad Saklaen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Gaous Muhammad Saklaen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Gaous Muhammad Saklaen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








  • 1




    $begingroup$
    Thanks a lot. Gonna do it now. Didn't know that before, by the way.
    $endgroup$
    – Gaous Muhammad Saklaen
    6 mins ago










  • $begingroup$
    You're very welcome!
    $endgroup$
    – Emma
    4 mins ago














  • 1




    $begingroup$
    Thanks a lot. Gonna do it now. Didn't know that before, by the way.
    $endgroup$
    – Gaous Muhammad Saklaen
    6 mins ago










  • $begingroup$
    You're very welcome!
    $endgroup$
    – Emma
    4 mins ago








1




1




$begingroup$
Thanks a lot. Gonna do it now. Didn't know that before, by the way.
$endgroup$
– Gaous Muhammad Saklaen
6 mins ago




$begingroup$
Thanks a lot. Gonna do it now. Didn't know that before, by the way.
$endgroup$
– Gaous Muhammad Saklaen
6 mins ago












$begingroup$
You're very welcome!
$endgroup$
– Emma
4 mins ago




$begingroup$
You're very welcome!
$endgroup$
– Emma
4 mins ago










0






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oldest

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