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A C method that gets a string from the user input


Managing a user accountScalability of running commands from user inputC library that converts integers to string and vice-versaSumming user inputGet initials from name input by useritoa with “method of complements” for negative numbers in ANSI CCustom user input functionHandling user input - follow-upScan the user input and then work with these lettersK&R Exercise 1-22. Fold (break) lines at specified column













0












$begingroup$


I'm new to C (and English), so don't kill me yet...



I've made a simple function that gets a string from the user and returns a char* array with said input. I would like to know how to better utilize the C tools to adapt this piece of code to the C standards.



char *getstr()
{
unsigned char buffer[128];
char counter = -1;

for(;;)
{
unsigned char c;

buffer[++counter] = (c = (unsigned char)getchar()) == 'n' ? '' : c;

if(buffer[counter] == (unsigned char)'' || counter == 127)
{
buffer[++counter] = (unsigned char)'';
break;
}
}

unsigned char str[counter];
return strncpy(str, buffer, counter + 1);
}








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$endgroup$

















    0












    $begingroup$


    I'm new to C (and English), so don't kill me yet...



    I've made a simple function that gets a string from the user and returns a char* array with said input. I would like to know how to better utilize the C tools to adapt this piece of code to the C standards.



    char *getstr()
    {
    unsigned char buffer[128];
    char counter = -1;

    for(;;)
    {
    unsigned char c;

    buffer[++counter] = (c = (unsigned char)getchar()) == 'n' ? '' : c;

    if(buffer[counter] == (unsigned char)'' || counter == 127)
    {
    buffer[++counter] = (unsigned char)'';
    break;
    }
    }

    unsigned char str[counter];
    return strncpy(str, buffer, counter + 1);
    }








    share







    New contributor




    Stacklysm is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$















      0












      0








      0





      $begingroup$


      I'm new to C (and English), so don't kill me yet...



      I've made a simple function that gets a string from the user and returns a char* array with said input. I would like to know how to better utilize the C tools to adapt this piece of code to the C standards.



      char *getstr()
      {
      unsigned char buffer[128];
      char counter = -1;

      for(;;)
      {
      unsigned char c;

      buffer[++counter] = (c = (unsigned char)getchar()) == 'n' ? '' : c;

      if(buffer[counter] == (unsigned char)'' || counter == 127)
      {
      buffer[++counter] = (unsigned char)'';
      break;
      }
      }

      unsigned char str[counter];
      return strncpy(str, buffer, counter + 1);
      }








      share







      New contributor




      Stacklysm is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      I'm new to C (and English), so don't kill me yet...



      I've made a simple function that gets a string from the user and returns a char* array with said input. I would like to know how to better utilize the C tools to adapt this piece of code to the C standards.



      char *getstr()
      {
      unsigned char buffer[128];
      char counter = -1;

      for(;;)
      {
      unsigned char c;

      buffer[++counter] = (c = (unsigned char)getchar()) == 'n' ? '' : c;

      if(buffer[counter] == (unsigned char)'' || counter == 127)
      {
      buffer[++counter] = (unsigned char)'';
      break;
      }
      }

      unsigned char str[counter];
      return strncpy(str, buffer, counter + 1);
      }






      c reinventing-the-wheel





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      Stacklysm is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      share







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      Stacklysm is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.








      share



      share






      New contributor




      Stacklysm is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      asked 6 mins ago









      StacklysmStacklysm

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      New contributor




      Stacklysm is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      Stacklysm is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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