RSS torrent downloaderChromium Nightly Build DownloaderTorrent File RemoverTkinter RSS feedPython Document...

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Align equations with text before one of them

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RSS torrent downloader


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1












$begingroup$


Just looking for any tips on improving what I have. It does exactly what I want but i'm still learning Python and was wondering if there's something I can do to make it more efficient or simpler.



import feedparser
import os
import urllib
import re

dwnLoc = 'C:/Downloads/'

#shows currently watching
shwOne = 'RSS LINK'
shwTwo = 'RSS LINK2'
aniLst = [shwOne, shwTwo]

#the episodes currently on
oneCur = [72,73]
twoCur = [13]
allEpi = [oneCur, twoCur]

#parse rss feed to
#create lists for episodes to download, their download links, and file names
newEpi =[]
dwnLnk = []
filNme = []
for shows,epi in zip(aniLst,allEpi):
dump = feedparser.parse(shows)
epiTrk = []
for post in dump.entries:
epiNum = [int(item) for item in post.title.split() if item.isdigit()]
if len(epiNum) == 1:
if epiNum[0] > epi[len(epi)-1]:
dwnLnk.append(post.link)
filNme.append(post.title + '.torrent')
epiTrk.append(epiNum[0])
newEpi.append(epiTrk)

#downloads and runs torrent
for link,name in zip(dwnLnk,filNme):
fileDownloaded = dwnLoc + name + '.torrent'
urllib.request.urlretrieve(link,fileDownloaded)
os.startfile(fileDownloaded)

#rewrites script to increment current episodes if one was downloaded
content = []
with open(__file__,"r") as f:
for line in f:
content.append(line)

with open(__file__,"w") as f:
counter = 0
for i,item in enumerate(content):
if all(str1 in item for str1 in ['Cur',']']) and not any(str2 in item for str2 in ['all','if']):
endFnd = item.find(']')
epiLst = newEpi[counter]
itmAdd = item[:endFnd]
for epiAdd in reversed(epiLst):
itmAdd += ',' + str(epiAdd)
content[i] = itmAdd + ']n'
counter += 1
for j in range(len(content)):
f.write(content[j])









share|improve this question









New contributor




qrs is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$












  • $begingroup$
    This time it should be right.
    $endgroup$
    – qrs
    47 mins ago
















1












$begingroup$


Just looking for any tips on improving what I have. It does exactly what I want but i'm still learning Python and was wondering if there's something I can do to make it more efficient or simpler.



import feedparser
import os
import urllib
import re

dwnLoc = 'C:/Downloads/'

#shows currently watching
shwOne = 'RSS LINK'
shwTwo = 'RSS LINK2'
aniLst = [shwOne, shwTwo]

#the episodes currently on
oneCur = [72,73]
twoCur = [13]
allEpi = [oneCur, twoCur]

#parse rss feed to
#create lists for episodes to download, their download links, and file names
newEpi =[]
dwnLnk = []
filNme = []
for shows,epi in zip(aniLst,allEpi):
dump = feedparser.parse(shows)
epiTrk = []
for post in dump.entries:
epiNum = [int(item) for item in post.title.split() if item.isdigit()]
if len(epiNum) == 1:
if epiNum[0] > epi[len(epi)-1]:
dwnLnk.append(post.link)
filNme.append(post.title + '.torrent')
epiTrk.append(epiNum[0])
newEpi.append(epiTrk)

#downloads and runs torrent
for link,name in zip(dwnLnk,filNme):
fileDownloaded = dwnLoc + name + '.torrent'
urllib.request.urlretrieve(link,fileDownloaded)
os.startfile(fileDownloaded)

#rewrites script to increment current episodes if one was downloaded
content = []
with open(__file__,"r") as f:
for line in f:
content.append(line)

with open(__file__,"w") as f:
counter = 0
for i,item in enumerate(content):
if all(str1 in item for str1 in ['Cur',']']) and not any(str2 in item for str2 in ['all','if']):
endFnd = item.find(']')
epiLst = newEpi[counter]
itmAdd = item[:endFnd]
for epiAdd in reversed(epiLst):
itmAdd += ',' + str(epiAdd)
content[i] = itmAdd + ']n'
counter += 1
for j in range(len(content)):
f.write(content[j])









share|improve this question









New contributor




qrs is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$












  • $begingroup$
    This time it should be right.
    $endgroup$
    – qrs
    47 mins ago














1












1








1





$begingroup$


Just looking for any tips on improving what I have. It does exactly what I want but i'm still learning Python and was wondering if there's something I can do to make it more efficient or simpler.



import feedparser
import os
import urllib
import re

dwnLoc = 'C:/Downloads/'

#shows currently watching
shwOne = 'RSS LINK'
shwTwo = 'RSS LINK2'
aniLst = [shwOne, shwTwo]

#the episodes currently on
oneCur = [72,73]
twoCur = [13]
allEpi = [oneCur, twoCur]

#parse rss feed to
#create lists for episodes to download, their download links, and file names
newEpi =[]
dwnLnk = []
filNme = []
for shows,epi in zip(aniLst,allEpi):
dump = feedparser.parse(shows)
epiTrk = []
for post in dump.entries:
epiNum = [int(item) for item in post.title.split() if item.isdigit()]
if len(epiNum) == 1:
if epiNum[0] > epi[len(epi)-1]:
dwnLnk.append(post.link)
filNme.append(post.title + '.torrent')
epiTrk.append(epiNum[0])
newEpi.append(epiTrk)

#downloads and runs torrent
for link,name in zip(dwnLnk,filNme):
fileDownloaded = dwnLoc + name + '.torrent'
urllib.request.urlretrieve(link,fileDownloaded)
os.startfile(fileDownloaded)

#rewrites script to increment current episodes if one was downloaded
content = []
with open(__file__,"r") as f:
for line in f:
content.append(line)

with open(__file__,"w") as f:
counter = 0
for i,item in enumerate(content):
if all(str1 in item for str1 in ['Cur',']']) and not any(str2 in item for str2 in ['all','if']):
endFnd = item.find(']')
epiLst = newEpi[counter]
itmAdd = item[:endFnd]
for epiAdd in reversed(epiLst):
itmAdd += ',' + str(epiAdd)
content[i] = itmAdd + ']n'
counter += 1
for j in range(len(content)):
f.write(content[j])









share|improve this question









New contributor




qrs is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




Just looking for any tips on improving what I have. It does exactly what I want but i'm still learning Python and was wondering if there's something I can do to make it more efficient or simpler.



import feedparser
import os
import urllib
import re

dwnLoc = 'C:/Downloads/'

#shows currently watching
shwOne = 'RSS LINK'
shwTwo = 'RSS LINK2'
aniLst = [shwOne, shwTwo]

#the episodes currently on
oneCur = [72,73]
twoCur = [13]
allEpi = [oneCur, twoCur]

#parse rss feed to
#create lists for episodes to download, their download links, and file names
newEpi =[]
dwnLnk = []
filNme = []
for shows,epi in zip(aniLst,allEpi):
dump = feedparser.parse(shows)
epiTrk = []
for post in dump.entries:
epiNum = [int(item) for item in post.title.split() if item.isdigit()]
if len(epiNum) == 1:
if epiNum[0] > epi[len(epi)-1]:
dwnLnk.append(post.link)
filNme.append(post.title + '.torrent')
epiTrk.append(epiNum[0])
newEpi.append(epiTrk)

#downloads and runs torrent
for link,name in zip(dwnLnk,filNme):
fileDownloaded = dwnLoc + name + '.torrent'
urllib.request.urlretrieve(link,fileDownloaded)
os.startfile(fileDownloaded)

#rewrites script to increment current episodes if one was downloaded
content = []
with open(__file__,"r") as f:
for line in f:
content.append(line)

with open(__file__,"w") as f:
counter = 0
for i,item in enumerate(content):
if all(str1 in item for str1 in ['Cur',']']) and not any(str2 in item for str2 in ['all','if']):
endFnd = item.find(']')
epiLst = newEpi[counter]
itmAdd = item[:endFnd]
for epiAdd in reversed(epiLst):
itmAdd += ',' + str(epiAdd)
content[i] = itmAdd + ']n'
counter += 1
for j in range(len(content)):
f.write(content[j])






python beginner http rss






share|improve this question









New contributor




qrs is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




qrs is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited 1 min ago









200_success

130k16153419




130k16153419






New contributor




qrs is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 6 hours ago









qrsqrs

61




61




New contributor




qrs is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





qrs is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






qrs is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • $begingroup$
    This time it should be right.
    $endgroup$
    – qrs
    47 mins ago


















  • $begingroup$
    This time it should be right.
    $endgroup$
    – qrs
    47 mins ago
















$begingroup$
This time it should be right.
$endgroup$
– qrs
47 mins ago




$begingroup$
This time it should be right.
$endgroup$
– qrs
47 mins ago










0






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