Solve Robot Paths using backtracking

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Solve Robot Paths using backtracking














0












$begingroup$


I got this problem during a mock interview, and I would like to get code review for the backtracking solution. I include 7 test cases, and my solution passes 7 out of 7 test cases. See the online code compiler here




Robot Paths



Prompt: Given a matrix of zeroes, determine how many unique paths exist from the top left corner to the bottom right corner



Input: An Array of Array of Integers (matrix)



Output: Integer



Examples:



matrix = [[0,0,0,0],
[0,0,0,0],
[0,0,0,0]]
robotPaths(matrix) = 38




matrix = [[0,0,0],
[0,0,0]]
robotPaths(matrix) = 4



# Note:     From any point, you can travel in the four cardinal directions. I decided to do backtracking approach to solve this problem.
# (north, south, east, west). A path is valid as long as it travels
# from the top left corner to the bottom right corner, does not go
# off of the matrix, and does not travel back on itself


def robot_paths(matrix):
num_of_rows = len(matrix)
num_of_cols = len(matrix[0])

def traverse(row, col):
nonlocal num_of_rows
nonlocal num_of_cols
# is row and col in bounds?
if row < 0 or row >= num_of_rows or col < 0 or col >= num_of_cols:
return 0

# has row, col already been visited?
if matrix[row][col] == 1:
return 0

# is row, col the destination?
if row == num_of_rows - 1 and col == num_of_cols - 1:
return 1

# mark coordinate as visited
matrix[row][col] = 1

# initialize sum of total unique paths to end from that coordinate
s = traverse(row, col + 1) + traverse(row + 1, col) + traverse(row - 1, col) + traverse(row, col - 1)

# backtrack; mark coordinate as unvisited so it can be
matrix[row][col] = 0

return s

return traverse(0, 0)



#############################################
######## DO NOT TOUCH TEST BELOW!!! #######
#############################################

def expect(count, name, test):
if (count == None or not isinstance(count, list) or len(count) != 2):
count = [0, 0]
else:
count[1] += 1

result = 'false'
errMsg = None
try:
if test():
result = ' true'
count[0] += 1
except Exception as err:
errMsg = str(err)

print(' ' + (str(count[1]) + ') ') + result + ' : ' + name)
if errMsg != None:
print(' ' + errMsg + 'n')

def lists_equal(lst1, lst2):
if len(lst1) != len(lst2):
return False
for i in range(0, len(lst1)):
if lst1[i] != lst2[i]:
return False
return True

print('Robot Paths Tests')
test_count = [0, 0]


def test():
matrix = [[0, 0, 0, 0],
[0, 0, 0, 0],
[0, 0, 0, 0]]
example = robot_paths(matrix)
return example == 38


expect(test_count, 'should work on first example input', test)


def test():
matrix = [[0, 0, 0],
[0, 0, 0]]
example = robot_paths(matrix)
return example == 4


expect(test_count, 'should work on second example input', test)


def test():
matrix = [[0]]
example = robot_paths(matrix)
return example == 1


expect(test_count, 'should work on single-element input', test)


def test():
matrix = [[0, 0, 0, 0, 0, 0]]
example = robot_paths(matrix)
return example == 1


expect(test_count, 'should work on single-row input', test)


def test():
matrix = [[0],
[0],
[0],
[0],
[0]]
example = robot_paths(matrix)
return example == 1


expect(test_count, 'should work on a 5 x 8 matrix input', test)


def test():
matrix = [[0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0]]
print(" Please be patient, test 6 may take longer to run")
example = robot_paths(matrix)
return example == 7110272


print('PASSED: ' + str(test_count[0]) + ' / ' + str(test_count[1]) + 'nn')








share









$endgroup$

















    0












    $begingroup$


    I got this problem during a mock interview, and I would like to get code review for the backtracking solution. I include 7 test cases, and my solution passes 7 out of 7 test cases. See the online code compiler here




    Robot Paths



    Prompt: Given a matrix of zeroes, determine how many unique paths exist from the top left corner to the bottom right corner



    Input: An Array of Array of Integers (matrix)



    Output: Integer



    Examples:



    matrix = [[0,0,0,0],
    [0,0,0,0],
    [0,0,0,0]]
    robotPaths(matrix) = 38




    matrix = [[0,0,0],
    [0,0,0]]
    robotPaths(matrix) = 4



    # Note:     From any point, you can travel in the four cardinal directions. I decided to do backtracking approach to solve this problem.
    # (north, south, east, west). A path is valid as long as it travels
    # from the top left corner to the bottom right corner, does not go
    # off of the matrix, and does not travel back on itself


    def robot_paths(matrix):
    num_of_rows = len(matrix)
    num_of_cols = len(matrix[0])

    def traverse(row, col):
    nonlocal num_of_rows
    nonlocal num_of_cols
    # is row and col in bounds?
    if row < 0 or row >= num_of_rows or col < 0 or col >= num_of_cols:
    return 0

    # has row, col already been visited?
    if matrix[row][col] == 1:
    return 0

    # is row, col the destination?
    if row == num_of_rows - 1 and col == num_of_cols - 1:
    return 1

    # mark coordinate as visited
    matrix[row][col] = 1

    # initialize sum of total unique paths to end from that coordinate
    s = traverse(row, col + 1) + traverse(row + 1, col) + traverse(row - 1, col) + traverse(row, col - 1)

    # backtrack; mark coordinate as unvisited so it can be
    matrix[row][col] = 0

    return s

    return traverse(0, 0)



    #############################################
    ######## DO NOT TOUCH TEST BELOW!!! #######
    #############################################

    def expect(count, name, test):
    if (count == None or not isinstance(count, list) or len(count) != 2):
    count = [0, 0]
    else:
    count[1] += 1

    result = 'false'
    errMsg = None
    try:
    if test():
    result = ' true'
    count[0] += 1
    except Exception as err:
    errMsg = str(err)

    print(' ' + (str(count[1]) + ') ') + result + ' : ' + name)
    if errMsg != None:
    print(' ' + errMsg + 'n')

    def lists_equal(lst1, lst2):
    if len(lst1) != len(lst2):
    return False
    for i in range(0, len(lst1)):
    if lst1[i] != lst2[i]:
    return False
    return True

    print('Robot Paths Tests')
    test_count = [0, 0]


    def test():
    matrix = [[0, 0, 0, 0],
    [0, 0, 0, 0],
    [0, 0, 0, 0]]
    example = robot_paths(matrix)
    return example == 38


    expect(test_count, 'should work on first example input', test)


    def test():
    matrix = [[0, 0, 0],
    [0, 0, 0]]
    example = robot_paths(matrix)
    return example == 4


    expect(test_count, 'should work on second example input', test)


    def test():
    matrix = [[0]]
    example = robot_paths(matrix)
    return example == 1


    expect(test_count, 'should work on single-element input', test)


    def test():
    matrix = [[0, 0, 0, 0, 0, 0]]
    example = robot_paths(matrix)
    return example == 1


    expect(test_count, 'should work on single-row input', test)


    def test():
    matrix = [[0],
    [0],
    [0],
    [0],
    [0]]
    example = robot_paths(matrix)
    return example == 1


    expect(test_count, 'should work on a 5 x 8 matrix input', test)


    def test():
    matrix = [[0, 0, 0, 0, 0, 0, 0, 0],
    [0, 0, 0, 0, 0, 0, 0, 0],
    [0, 0, 0, 0, 0, 0, 0, 0],
    [0, 0, 0, 0, 0, 0, 0, 0],
    [0, 0, 0, 0, 0, 0, 0, 0]]
    print(" Please be patient, test 6 may take longer to run")
    example = robot_paths(matrix)
    return example == 7110272


    print('PASSED: ' + str(test_count[0]) + ' / ' + str(test_count[1]) + 'nn')








    share









    $endgroup$















      0












      0








      0





      $begingroup$


      I got this problem during a mock interview, and I would like to get code review for the backtracking solution. I include 7 test cases, and my solution passes 7 out of 7 test cases. See the online code compiler here




      Robot Paths



      Prompt: Given a matrix of zeroes, determine how many unique paths exist from the top left corner to the bottom right corner



      Input: An Array of Array of Integers (matrix)



      Output: Integer



      Examples:



      matrix = [[0,0,0,0],
      [0,0,0,0],
      [0,0,0,0]]
      robotPaths(matrix) = 38




      matrix = [[0,0,0],
      [0,0,0]]
      robotPaths(matrix) = 4



      # Note:     From any point, you can travel in the four cardinal directions. I decided to do backtracking approach to solve this problem.
      # (north, south, east, west). A path is valid as long as it travels
      # from the top left corner to the bottom right corner, does not go
      # off of the matrix, and does not travel back on itself


      def robot_paths(matrix):
      num_of_rows = len(matrix)
      num_of_cols = len(matrix[0])

      def traverse(row, col):
      nonlocal num_of_rows
      nonlocal num_of_cols
      # is row and col in bounds?
      if row < 0 or row >= num_of_rows or col < 0 or col >= num_of_cols:
      return 0

      # has row, col already been visited?
      if matrix[row][col] == 1:
      return 0

      # is row, col the destination?
      if row == num_of_rows - 1 and col == num_of_cols - 1:
      return 1

      # mark coordinate as visited
      matrix[row][col] = 1

      # initialize sum of total unique paths to end from that coordinate
      s = traverse(row, col + 1) + traverse(row + 1, col) + traverse(row - 1, col) + traverse(row, col - 1)

      # backtrack; mark coordinate as unvisited so it can be
      matrix[row][col] = 0

      return s

      return traverse(0, 0)



      #############################################
      ######## DO NOT TOUCH TEST BELOW!!! #######
      #############################################

      def expect(count, name, test):
      if (count == None or not isinstance(count, list) or len(count) != 2):
      count = [0, 0]
      else:
      count[1] += 1

      result = 'false'
      errMsg = None
      try:
      if test():
      result = ' true'
      count[0] += 1
      except Exception as err:
      errMsg = str(err)

      print(' ' + (str(count[1]) + ') ') + result + ' : ' + name)
      if errMsg != None:
      print(' ' + errMsg + 'n')

      def lists_equal(lst1, lst2):
      if len(lst1) != len(lst2):
      return False
      for i in range(0, len(lst1)):
      if lst1[i] != lst2[i]:
      return False
      return True

      print('Robot Paths Tests')
      test_count = [0, 0]


      def test():
      matrix = [[0, 0, 0, 0],
      [0, 0, 0, 0],
      [0, 0, 0, 0]]
      example = robot_paths(matrix)
      return example == 38


      expect(test_count, 'should work on first example input', test)


      def test():
      matrix = [[0, 0, 0],
      [0, 0, 0]]
      example = robot_paths(matrix)
      return example == 4


      expect(test_count, 'should work on second example input', test)


      def test():
      matrix = [[0]]
      example = robot_paths(matrix)
      return example == 1


      expect(test_count, 'should work on single-element input', test)


      def test():
      matrix = [[0, 0, 0, 0, 0, 0]]
      example = robot_paths(matrix)
      return example == 1


      expect(test_count, 'should work on single-row input', test)


      def test():
      matrix = [[0],
      [0],
      [0],
      [0],
      [0]]
      example = robot_paths(matrix)
      return example == 1


      expect(test_count, 'should work on a 5 x 8 matrix input', test)


      def test():
      matrix = [[0, 0, 0, 0, 0, 0, 0, 0],
      [0, 0, 0, 0, 0, 0, 0, 0],
      [0, 0, 0, 0, 0, 0, 0, 0],
      [0, 0, 0, 0, 0, 0, 0, 0],
      [0, 0, 0, 0, 0, 0, 0, 0]]
      print(" Please be patient, test 6 may take longer to run")
      example = robot_paths(matrix)
      return example == 7110272


      print('PASSED: ' + str(test_count[0]) + ' / ' + str(test_count[1]) + 'nn')








      share









      $endgroup$




      I got this problem during a mock interview, and I would like to get code review for the backtracking solution. I include 7 test cases, and my solution passes 7 out of 7 test cases. See the online code compiler here




      Robot Paths



      Prompt: Given a matrix of zeroes, determine how many unique paths exist from the top left corner to the bottom right corner



      Input: An Array of Array of Integers (matrix)



      Output: Integer



      Examples:



      matrix = [[0,0,0,0],
      [0,0,0,0],
      [0,0,0,0]]
      robotPaths(matrix) = 38




      matrix = [[0,0,0],
      [0,0,0]]
      robotPaths(matrix) = 4



      # Note:     From any point, you can travel in the four cardinal directions. I decided to do backtracking approach to solve this problem.
      # (north, south, east, west). A path is valid as long as it travels
      # from the top left corner to the bottom right corner, does not go
      # off of the matrix, and does not travel back on itself


      def robot_paths(matrix):
      num_of_rows = len(matrix)
      num_of_cols = len(matrix[0])

      def traverse(row, col):
      nonlocal num_of_rows
      nonlocal num_of_cols
      # is row and col in bounds?
      if row < 0 or row >= num_of_rows or col < 0 or col >= num_of_cols:
      return 0

      # has row, col already been visited?
      if matrix[row][col] == 1:
      return 0

      # is row, col the destination?
      if row == num_of_rows - 1 and col == num_of_cols - 1:
      return 1

      # mark coordinate as visited
      matrix[row][col] = 1

      # initialize sum of total unique paths to end from that coordinate
      s = traverse(row, col + 1) + traverse(row + 1, col) + traverse(row - 1, col) + traverse(row, col - 1)

      # backtrack; mark coordinate as unvisited so it can be
      matrix[row][col] = 0

      return s

      return traverse(0, 0)



      #############################################
      ######## DO NOT TOUCH TEST BELOW!!! #######
      #############################################

      def expect(count, name, test):
      if (count == None or not isinstance(count, list) or len(count) != 2):
      count = [0, 0]
      else:
      count[1] += 1

      result = 'false'
      errMsg = None
      try:
      if test():
      result = ' true'
      count[0] += 1
      except Exception as err:
      errMsg = str(err)

      print(' ' + (str(count[1]) + ') ') + result + ' : ' + name)
      if errMsg != None:
      print(' ' + errMsg + 'n')

      def lists_equal(lst1, lst2):
      if len(lst1) != len(lst2):
      return False
      for i in range(0, len(lst1)):
      if lst1[i] != lst2[i]:
      return False
      return True

      print('Robot Paths Tests')
      test_count = [0, 0]


      def test():
      matrix = [[0, 0, 0, 0],
      [0, 0, 0, 0],
      [0, 0, 0, 0]]
      example = robot_paths(matrix)
      return example == 38


      expect(test_count, 'should work on first example input', test)


      def test():
      matrix = [[0, 0, 0],
      [0, 0, 0]]
      example = robot_paths(matrix)
      return example == 4


      expect(test_count, 'should work on second example input', test)


      def test():
      matrix = [[0]]
      example = robot_paths(matrix)
      return example == 1


      expect(test_count, 'should work on single-element input', test)


      def test():
      matrix = [[0, 0, 0, 0, 0, 0]]
      example = robot_paths(matrix)
      return example == 1


      expect(test_count, 'should work on single-row input', test)


      def test():
      matrix = [[0],
      [0],
      [0],
      [0],
      [0]]
      example = robot_paths(matrix)
      return example == 1


      expect(test_count, 'should work on a 5 x 8 matrix input', test)


      def test():
      matrix = [[0, 0, 0, 0, 0, 0, 0, 0],
      [0, 0, 0, 0, 0, 0, 0, 0],
      [0, 0, 0, 0, 0, 0, 0, 0],
      [0, 0, 0, 0, 0, 0, 0, 0],
      [0, 0, 0, 0, 0, 0, 0, 0]]
      print(" Please be patient, test 6 may take longer to run")
      example = robot_paths(matrix)
      return example == 7110272


      print('PASSED: ' + str(test_count[0]) + ' / ' + str(test_count[1]) + 'nn')






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