Rendering elements (which can change numbers) using jQuery The 2019 Stack Overflow Developer...
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Rendering elements (which can change numbers) using jQuery
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$begingroup$
Currently when the user selects some tags in my app I generate them in a function, like this:
// Show tags that are currently used in search
var htmlNodes = '<ul class="tags">';
// If no pinned nodes, reset not found nodes
if (graphFactory.existPinnedNodes() == false) {
graphFactory.updateNotFoundNodes();
}
// Add not found nodes as tags (gray)
for (let x = 0; x < graphFactory.getNotFoundNodes().length; x++) {
htmlNodes = htmlNodes + '<li><a class="notfound" href="#">' + graphFactory.getNotFoundNodes()[x] + '</a></li>';
}
// Add pinned nodes as tags (blue)
for (let q = 0; q < graphFactory.getPinnedNodes().length; q++) {
htmlNodes = htmlNodes + '<li><a href="#">' + graphFactory.getPinnedNodes()[q] + '</a></li>';
}
htmlNodes = htmlNodes + '<div class="tagsend"></div></ul>';
$('#pinnednodeslist').html(htmlNodes);
Basically I create a <ul> of class tags, add some li elements with a specific tag each, and then render it into the #pinnednodeslist element.
As you can see, the number of <li> elements might change, depending on the number of getPinnedNodes or getNotFoundNodes, so I wonder if I have to reconstruct this html every time or if there is a more efficient way to do that...
Maybe a better way is that I don't have to mix so much HTML with my code?
For instance, I was thinking to leave all the elements there and just make them invisible, simply adding a class to show them and the html content to display within... But maybe you know of some other better way to do that?
javascript jquery interface
edited 6 mins ago
Jamal♦
30.6k11121227
asked 20 hours ago
Dmitry ParanyushkinDmitry Paranyushkin
1062
New contributor
Dmitry Paranyushkin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Currently when the user selects some tags in my app I generate them in a function, like this:
// Show tags that are currently used in search
var htmlNodes = '<ul class="tags">';
// If no pinned nodes, reset not found nodes
if (graphFactory.existPinnedNodes() == false) {
graphFactory.updateNotFoundNodes();
}
// Add not found nodes as tags (gray)
for (let x = 0; x < graphFactory.getNotFoundNodes().length; x++) {
htmlNodes = htmlNodes + '<li><a class="notfound" href="#">' + graphFactory.getNotFoundNodes()[x] + '</a></li>';
}
// Add pinned nodes as tags (blue)
for (let q = 0; q < graphFactory.getPinnedNodes().length; q++) {
htmlNodes = htmlNodes + '<li><a href="#">' + graphFactory.getPinnedNodes()[q] + '</a></li>';
}
htmlNodes = htmlNodes + '<div class="tagsend"></div></ul>';
$('#pinnednodeslist').html(htmlNodes);
Basically I create a <ul> of class tags, add some li elements with a specific tag each, and then render it into the #pinnednodeslist element.
As you can see, the number of <li> elements might change, depending on the number of getPinnedNodes or getNotFoundNodes, so I wonder if I have to reconstruct this html every time or if there is a more efficient way to do that...
Maybe a better way is that I don't have to mix so much HTML with my code?
For instance, I was thinking to leave all the elements there and just make them invisible, simply adding a class to show them and the html content to display within... But maybe you know of some other better way to do that?
javascript jquery interface
edited 6 mins ago
Jamal♦
30.6k11121227
asked 20 hours ago
Dmitry ParanyushkinDmitry Paranyushkin
1062
New contributor
Dmitry Paranyushkin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Currently when the user selects some tags in my app I generate them in a function, like this:
// Show tags that are currently used in search
var htmlNodes = '<ul class="tags">';
// If no pinned nodes, reset not found nodes
if (graphFactory.existPinnedNodes() == false) {
graphFactory.updateNotFoundNodes();
}
// Add not found nodes as tags (gray)
for (let x = 0; x < graphFactory.getNotFoundNodes().length; x++) {
htmlNodes = htmlNodes + '<li><a class="notfound" href="#">' + graphFactory.getNotFoundNodes()[x] + '</a></li>';
}
// Add pinned nodes as tags (blue)
for (let q = 0; q < graphFactory.getPinnedNodes().length; q++) {
htmlNodes = htmlNodes + '<li><a href="#">' + graphFactory.getPinnedNodes()[q] + '</a></li>';
}
htmlNodes = htmlNodes + '<div class="tagsend"></div></ul>';
$('#pinnednodeslist').html(htmlNodes);
Basically I create a <ul> of class tags, add some li elements with a specific tag each, and then render it into the #pinnednodeslist element.
As you can see, the number of <li> elements might change, depending on the number of getPinnedNodes or getNotFoundNodes, so I wonder if I have to reconstruct this html every time or if there is a more efficient way to do that...
Maybe a better way is that I don't have to mix so much HTML with my code?
For instance, I was thinking to leave all the elements there and just make them invisible, simply adding a class to show them and the html content to display within... But maybe you know of some other better way to do that?
javascript jquery interface
edited 6 mins ago
Jamal♦
30.6k11121227
asked 20 hours ago
Dmitry ParanyushkinDmitry Paranyushkin
1062
New contributor
Dmitry Paranyushkin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Currently when the user selects some tags in my app I generate them in a function, like this:
// Show tags that are currently used in search
var htmlNodes = '<ul class="tags">';
// If no pinned nodes, reset not found nodes
if (graphFactory.existPinnedNodes() == false) {
graphFactory.updateNotFoundNodes();
}
// Add not found nodes as tags (gray)
for (let x = 0; x < graphFactory.getNotFoundNodes().length; x++) {
htmlNodes = htmlNodes + '<li><a class="notfound" href="#">' + graphFactory.getNotFoundNodes()[x] + '</a></li>';
}
// Add pinned nodes as tags (blue)
for (let q = 0; q < graphFactory.getPinnedNodes().length; q++) {
htmlNodes = htmlNodes + '<li><a href="#">' + graphFactory.getPinnedNodes()[q] + '</a></li>';
}
htmlNodes = htmlNodes + '<div class="tagsend"></div></ul>';
$('#pinnednodeslist').html(htmlNodes);
Basically I create a <ul> of class tags, add some li elements with a specific tag each, and then render it into the #pinnednodeslist element.
As you can see, the number of <li> elements might change, depending on the number of getPinnedNodes or getNotFoundNodes, so I wonder if I have to reconstruct this html every time or if there is a more efficient way to do that...
Maybe a better way is that I don't have to mix so much HTML with my code?
For instance, I was thinking to leave all the elements there and just make them invisible, simply adding a class to show them and the html content to display within... But maybe you know of some other better way to do that?
javascript jquery interface
javascript jquery interface
edited 6 mins ago
Jamal♦
30.6k11121227
asked 20 hours ago
Dmitry ParanyushkinDmitry Paranyushkin
1062
New contributor
Dmitry Paranyushkin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 6 mins ago
Jamal♦
30.6k11121227
asked 20 hours ago
Dmitry ParanyushkinDmitry Paranyushkin
1062
New contributor
Dmitry Paranyushkin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 6 mins ago
Jamal♦
30.6k11121227
edited 6 mins ago
Jamal♦
30.6k11121227
edited 6 mins ago
Jamal♦
30.6k11121227
30.6k11121227
asked 20 hours ago
Dmitry ParanyushkinDmitry Paranyushkin
1062
New contributor
Dmitry Paranyushkin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 20 hours ago
Dmitry ParanyushkinDmitry Paranyushkin
1062
asked 20 hours ago
Dmitry ParanyushkinDmitry Paranyushkin
1062
1062
New contributor
Dmitry Paranyushkin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Dmitry Paranyushkin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Dmitry Paranyushkin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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