Moving plot labelScale Insetted Characters to PlotImagePadding or other means of getting whitespace when the...
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Moving plot label
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$begingroup$
I am trying to place the plot title somewhere neat, to the left of x=0.
Plot[1/(1 + Exp[-x]), {x, -10, 10},
PlotLabel ->
Framed@Pane[
"F (x)=!(*FractionBox[(1), (1 + *SuperscriptBox[(e),
(-x)])])", Alignment -> Right]]
I tried this but it's still sticking at the top of figure, any help appreciated!
plotting
asked 46 mins ago
rodger_kicksrodger_kicks
365
$endgroup$
add a comment |
$begingroup$
I am trying to place the plot title somewhere neat, to the left of x=0.
Plot[1/(1 + Exp[-x]), {x, -10, 10},
PlotLabel ->
Framed@Pane[
"F (x)=!(*FractionBox[(1), (1 + *SuperscriptBox[(e),
(-x)])])", Alignment -> Right]]
I tried this but it's still sticking at the top of figure, any help appreciated!
plotting
asked 46 mins ago
rodger_kicksrodger_kicks
365
$endgroup$
add a comment |
$begingroup$
I am trying to place the plot title somewhere neat, to the left of x=0.
Plot[1/(1 + Exp[-x]), {x, -10, 10},
PlotLabel ->
Framed@Pane[
"F (x)=!(*FractionBox[(1), (1 + *SuperscriptBox[(e),
(-x)])])", Alignment -> Right]]
I tried this but it's still sticking at the top of figure, any help appreciated!
plotting
asked 46 mins ago
rodger_kicksrodger_kicks
365
$endgroup$
I am trying to place the plot title somewhere neat, to the left of x=0.
Plot[1/(1 + Exp[-x]), {x, -10, 10},
PlotLabel ->
Framed@Pane[
"F (x)=!(*FractionBox[(1), (1 + *SuperscriptBox[(e),
(-x)])])", Alignment -> Right]]
I tried this but it's still sticking at the top of figure, any help appreciated!
plotting
plotting
asked 46 mins ago
rodger_kicksrodger_kicks
365
asked 46 mins ago
rodger_kicksrodger_kicks
365
asked 46 mins ago
rodger_kicksrodger_kicks
365
asked 46 mins ago
rodger_kicksrodger_kicks
365
asked 46 mins ago
rodger_kicksrodger_kicks
365
365
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
You can use Inset[] to add it to the graphics, instead it being a label:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
Epilog ->
Inset[Framed@
Pane["F (x)=!(*FractionBox[(1), (1 +
*SuperscriptBox[(e), (-x)])])", Alignment -> Right],
{-1.5, 1}, {1, 1}]]
FWIW, I rather prefer the look of TraditionalForm in this:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
Epilog -> Inset[Framed@
Pane[HoldForm[F[x] == 1/(1 + E^-x)], Alignment -> Right],
{-1.5, 1}, {1, 1}]]
answered 28 mins ago
Michael E2Michael E2
149k12200479
$endgroup$
add a comment |
$begingroup$
You can wrap your label with another Framed with the options FrameStyle -> None and FrameMargins -> {{0, rightmargin}, {0,0}} with your choice of rightmargin:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
PlotLabel -> Framed[Framed[Pane[HoldForm[F[x] = 1/(1 + E^-x)],
Alignment -> Right]],
FrameStyle -> None, FrameMargins -> {{0, Scaled[.1]}, {0, 0}}]]
Use FrameMargins -> {{0, Scaled[.14]}, {0, Scaled[.05]}} to get
answered 37 mins ago
kglrkglr
188k10204422
$endgroup$
$begingroup$
Isn't theTraditionalFormunnecessary? (It's applied by default here, I think.)
$endgroup$
– Michael E2
14 mins ago
$begingroup$
Thank you @MichaelE2; good point.
$endgroup$
– kglr
9 mins ago
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You can use Inset[] to add it to the graphics, instead it being a label:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
Epilog ->
Inset[Framed@
Pane["F (x)=!(*FractionBox[(1), (1 +
*SuperscriptBox[(e), (-x)])])", Alignment -> Right],
{-1.5, 1}, {1, 1}]]
FWIW, I rather prefer the look of TraditionalForm in this:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
Epilog -> Inset[Framed@
Pane[HoldForm[F[x] == 1/(1 + E^-x)], Alignment -> Right],
{-1.5, 1}, {1, 1}]]
answered 28 mins ago
Michael E2Michael E2
149k12200479
$endgroup$
add a comment |
$begingroup$
You can use Inset[] to add it to the graphics, instead it being a label:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
Epilog ->
Inset[Framed@
Pane["F (x)=!(*FractionBox[(1), (1 +
*SuperscriptBox[(e), (-x)])])", Alignment -> Right],
{-1.5, 1}, {1, 1}]]
FWIW, I rather prefer the look of TraditionalForm in this:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
Epilog -> Inset[Framed@
Pane[HoldForm[F[x] == 1/(1 + E^-x)], Alignment -> Right],
{-1.5, 1}, {1, 1}]]
answered 28 mins ago
Michael E2Michael E2
149k12200479
$endgroup$
add a comment |
$begingroup$
You can use Inset[] to add it to the graphics, instead it being a label:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
Epilog ->
Inset[Framed@
Pane["F (x)=!(*FractionBox[(1), (1 +
*SuperscriptBox[(e), (-x)])])", Alignment -> Right],
{-1.5, 1}, {1, 1}]]
FWIW, I rather prefer the look of TraditionalForm in this:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
Epilog -> Inset[Framed@
Pane[HoldForm[F[x] == 1/(1 + E^-x)], Alignment -> Right],
{-1.5, 1}, {1, 1}]]
answered 28 mins ago
Michael E2Michael E2
149k12200479
$endgroup$
You can use Inset[] to add it to the graphics, instead it being a label:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
Epilog ->
Inset[Framed@
Pane["F (x)=!(*FractionBox[(1), (1 +
*SuperscriptBox[(e), (-x)])])", Alignment -> Right],
{-1.5, 1}, {1, 1}]]
FWIW, I rather prefer the look of TraditionalForm in this:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
Epilog -> Inset[Framed@
Pane[HoldForm[F[x] == 1/(1 + E^-x)], Alignment -> Right],
{-1.5, 1}, {1, 1}]]
answered 28 mins ago
Michael E2Michael E2
149k12200479
answered 28 mins ago
Michael E2Michael E2
149k12200479
answered 28 mins ago
Michael E2Michael E2
149k12200479
answered 28 mins ago
Michael E2Michael E2
149k12200479
149k12200479
add a comment |
add a comment |
$begingroup$
You can wrap your label with another Framed with the options FrameStyle -> None and FrameMargins -> {{0, rightmargin}, {0,0}} with your choice of rightmargin:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
PlotLabel -> Framed[Framed[Pane[HoldForm[F[x] = 1/(1 + E^-x)],
Alignment -> Right]],
FrameStyle -> None, FrameMargins -> {{0, Scaled[.1]}, {0, 0}}]]
Use FrameMargins -> {{0, Scaled[.14]}, {0, Scaled[.05]}} to get
answered 37 mins ago
kglrkglr
188k10204422
$endgroup$
$begingroup$
Isn't theTraditionalFormunnecessary? (It's applied by default here, I think.)
$endgroup$
– Michael E2
14 mins ago
$begingroup$
Thank you @MichaelE2; good point.
$endgroup$
– kglr
9 mins ago
add a comment |
$begingroup$
You can wrap your label with another Framed with the options FrameStyle -> None and FrameMargins -> {{0, rightmargin}, {0,0}} with your choice of rightmargin:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
PlotLabel -> Framed[Framed[Pane[HoldForm[F[x] = 1/(1 + E^-x)],
Alignment -> Right]],
FrameStyle -> None, FrameMargins -> {{0, Scaled[.1]}, {0, 0}}]]
Use FrameMargins -> {{0, Scaled[.14]}, {0, Scaled[.05]}} to get
answered 37 mins ago
kglrkglr
188k10204422
$endgroup$
$begingroup$
Isn't theTraditionalFormunnecessary? (It's applied by default here, I think.)
$endgroup$
– Michael E2
14 mins ago
$begingroup$
Thank you @MichaelE2; good point.
$endgroup$
– kglr
9 mins ago
add a comment |
$begingroup$
You can wrap your label with another Framed with the options FrameStyle -> None and FrameMargins -> {{0, rightmargin}, {0,0}} with your choice of rightmargin:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
PlotLabel -> Framed[Framed[Pane[HoldForm[F[x] = 1/(1 + E^-x)],
Alignment -> Right]],
FrameStyle -> None, FrameMargins -> {{0, Scaled[.1]}, {0, 0}}]]
Use FrameMargins -> {{0, Scaled[.14]}, {0, Scaled[.05]}} to get
answered 37 mins ago
kglrkglr
188k10204422
$endgroup$
You can wrap your label with another Framed with the options FrameStyle -> None and FrameMargins -> {{0, rightmargin}, {0,0}} with your choice of rightmargin:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
PlotLabel -> Framed[Framed[Pane[HoldForm[F[x] = 1/(1 + E^-x)],
Alignment -> Right]],
FrameStyle -> None, FrameMargins -> {{0, Scaled[.1]}, {0, 0}}]]
Use FrameMargins -> {{0, Scaled[.14]}, {0, Scaled[.05]}} to get
answered 37 mins ago
kglrkglr
188k10204422
edited 8 mins ago
answered 37 mins ago
kglrkglr
188k10204422
answered 37 mins ago
kglrkglr
188k10204422
answered 37 mins ago
kglrkglr
188k10204422
188k10204422
$begingroup$
Isn't theTraditionalFormunnecessary? (It's applied by default here, I think.)
$endgroup$
– Michael E2
14 mins ago
$begingroup$
Thank you @MichaelE2; good point.
$endgroup$
– kglr
9 mins ago
add a comment |
$begingroup$
Isn't theTraditionalFormunnecessary? (It's applied by default here, I think.)
$endgroup$
– Michael E2
14 mins ago
$begingroup$
Thank you @MichaelE2; good point.
$endgroup$
– kglr
9 mins ago
$begingroup$
Isn't the
TraditionalForm unnecessary? (It's applied by default here, I think.)$endgroup$
– Michael E2
14 mins ago
$begingroup$
Isn't the
TraditionalForm unnecessary? (It's applied by default here, I think.)$endgroup$
– Michael E2
14 mins ago
$begingroup$
Thank you @MichaelE2; good point.
$endgroup$
– kglr
9 mins ago
$begingroup$
Thank you @MichaelE2; good point.
$endgroup$
– kglr
9 mins ago
add a comment |
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