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Regex for certain words causes Spaces

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1

For instance i'm trying to search this string

"this is a search LLC which can end up having spaces"

using the below regex, it's working fine but when I match and then remove it's causes a bunch of white spaces, so I want to limit the number the white space to just 1, how could I go about adding that?

(?i)(?<=|^)LLC|end|having(?=|$)

this is a search LLC which can end up having spaces

this is a search which can up spaces

public static String removeValuesByRegex(String input, Pattern pattern, String replaceWith){

    String result;



    Matcher matcher = pattern.matcher(input);



    return result = matcher.replaceAll(replaceWith).trim();

}

Then in my test class im doing

String keywords = 'LLC|end|Having';

Pattern pattern = Pattern.compile('(?i)(?<= |^)'|' + keyWords + ''|(?= |$)');



String stringResult = UtilString.removeValuesByRegex('This is a LLC and General Partnership Test ', pattern, '');

apex regular-expressions

share|improve this question

asked 1 hour ago

EricSSHEricSSH

3,64211749

add a comment | 

1

For instance i'm trying to search this string

"this is a search LLC which can end up having spaces"

using the below regex, it's working fine but when I match and then remove it's causes a bunch of white spaces, so I want to limit the number the white space to just 1, how could I go about adding that?

(?i)(?<=|^)LLC|end|having(?=|$)

this is a search LLC which can end up having spaces

this is a search which can up spaces

public static String removeValuesByRegex(String input, Pattern pattern, String replaceWith){

    String result;



    Matcher matcher = pattern.matcher(input);



    return result = matcher.replaceAll(replaceWith).trim();

}

Then in my test class im doing

String keywords = 'LLC|end|Having';

Pattern pattern = Pattern.compile('(?i)(?<= |^)'|' + keyWords + ''|(?= |$)');



String stringResult = UtilString.removeValuesByRegex('This is a LLC and General Partnership Test ', pattern, '');

apex regular-expressions

share|improve this question

asked 1 hour ago

EricSSHEricSSH

3,64211749

add a comment | 

For instance i'm trying to search this string

"this is a search LLC which can end up having spaces"

using the below regex, it's working fine but when I match and then remove it's causes a bunch of white spaces, so I want to limit the number the white space to just 1, how could I go about adding that?

(?i)(?<=|^)LLC|end|having(?=|$)

this is a search LLC which can end up having spaces

this is a search which can up spaces

public static String removeValuesByRegex(String input, Pattern pattern, String replaceWith){

    String result;



    Matcher matcher = pattern.matcher(input);



    return result = matcher.replaceAll(replaceWith).trim();

}

Then in my test class im doing

String keywords = 'LLC|end|Having';

Pattern pattern = Pattern.compile('(?i)(?<= |^)'|' + keyWords + ''|(?= |$)');



String stringResult = UtilString.removeValuesByRegex('This is a LLC and General Partnership Test ', pattern, '');

apex regular-expressions

share|improve this question

asked 1 hour ago

EricSSHEricSSH

3,64211749

public static String removeValuesByRegex(String input, Pattern pattern, String replaceWith){

    String result;



    Matcher matcher = pattern.matcher(input);



    return result = matcher.replaceAll(replaceWith).trim();

}

String keywords = 'LLC|end|Having';

Pattern pattern = Pattern.compile('(?i)(?<= |^)'|' + keyWords + ''|(?= |$)');



String stringResult = UtilString.removeValuesByRegex('This is a LLC and General Partnership Test ', pattern, '');

share|improve this question

asked 1 hour ago

EricSSHEricSSH

3,64211749

share|improve this question

asked 1 hour ago

EricSSHEricSSH

3,64211749

asked 1 hour ago

EricSSHEricSSH

3,64211749

asked 1 hour ago

EricSSHEricSSH

3,64211749

1 Answer
1

active

oldest

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3

If you want to remove duplicate spacing, I recommend you call normalizeSpace on the output:

String result = MyClass.myMethod(input, pattern, '').normalizeSpace();

Note from the documentation:

normalizeSpace()

Returns the current String with leading, trailing, and repeating white space characters removed.

share|improve this answer

answered 1 hour ago

Adrian Larson♦Adrian Larson

109k19115246

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks, I missed that in the docs
  
  – EricSSH
  1 hour ago
  

  
  
  
  

add a comment | 

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3

If you want to remove duplicate spacing, I recommend you call normalizeSpace on the output:

String result = MyClass.myMethod(input, pattern, '').normalizeSpace();

Note from the documentation:

normalizeSpace()

Returns the current String with leading, trailing, and repeating white space characters removed.

share|improve this answer

answered 1 hour ago

Adrian Larson♦Adrian Larson

109k19115246

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks, I missed that in the docs
  
  – EricSSH
  1 hour ago
  

  
  
  
  

add a comment | 

3

If you want to remove duplicate spacing, I recommend you call normalizeSpace on the output:

String result = MyClass.myMethod(input, pattern, '').normalizeSpace();

Note from the documentation:

normalizeSpace()

Returns the current String with leading, trailing, and repeating white space characters removed.

share|improve this answer

answered 1 hour ago

Adrian Larson♦Adrian Larson

109k19115246

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks, I missed that in the docs
  
  – EricSSH
  1 hour ago
  

  
  
  
  

add a comment | 

If you want to remove duplicate spacing, I recommend you call normalizeSpace on the output:

String result = MyClass.myMethod(input, pattern, '').normalizeSpace();

Note from the documentation:

normalizeSpace()

Returns the current String with leading, trailing, and repeating white space characters removed.

share|improve this answer

answered 1 hour ago

Adrian Larson♦Adrian Larson

109k19115246

String result = MyClass.myMethod(input, pattern, '').normalizeSpace();

share|improve this answer

answered 1 hour ago

Adrian Larson♦Adrian Larson

109k19115246

answered 1 hour ago

Adrian Larson♦Adrian Larson

109k19115246

answered 1 hour ago

Adrian Larson♦Adrian Larson

109k19115246