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Starting index at zero
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$begingroup$
In order to start an index at zero, I found N. Abbasi is quite convenient. For instance,
(Note that in the original code by Abbasi, one of under scores _ in Notation[] was missing.)
However, with this method, we need to define these notations for each symbol.
I'd like to use any symbols with subscripts, like "a" in the above pic. with the same definition.
Any help is appreciated! Thanks in advance.
list-manipulation
asked 3 hours ago
Like TinaLike Tina
211
New contributor
Like Tina is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$
add a comment |
$begingroup$
In order to start an index at zero, I found N. Abbasi is quite convenient. For instance,
(Note that in the original code by Abbasi, one of under scores _ in Notation[] was missing.)
However, with this method, we need to define these notations for each symbol.
I'd like to use any symbols with subscripts, like "a" in the above pic. with the same definition.
Any help is appreciated! Thanks in advance.
list-manipulation
asked 3 hours ago
Like TinaLike Tina
211
New contributor
Like Tina is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
In order to start an index at zero, I found N. Abbasi is quite convenient. For instance,
(Note that in the original code by Abbasi, one of under scores _ in Notation[] was missing.)
However, with this method, we need to define these notations for each symbol.
I'd like to use any symbols with subscripts, like "a" in the above pic. with the same definition.
Any help is appreciated! Thanks in advance.
list-manipulation
asked 3 hours ago
Like TinaLike Tina
211
New contributor
Like Tina is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
In order to start an index at zero, I found N. Abbasi is quite convenient. For instance,
(Note that in the original code by Abbasi, one of under scores _ in Notation[] was missing.)
However, with this method, we need to define these notations for each symbol.
I'd like to use any symbols with subscripts, like "a" in the above pic. with the same definition.
Any help is appreciated! Thanks in advance.
list-manipulation
list-manipulation
asked 3 hours ago
Like TinaLike Tina
211
New contributor
Like Tina is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 3 hours ago
Like TinaLike Tina
211
New contributor
Like Tina is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 3 hours ago
Like TinaLike Tina
211
New contributor
Like Tina is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 3 hours ago
Like TinaLike Tina
211
asked 3 hours ago
Like TinaLike Tina
211
211
New contributor
Like Tina is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Like Tina is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Like Tina is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
1 Answer
1
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votes
$begingroup$
There's no need to use the Notation package to achieve the same behavior. For example:
SetAttributes[Subscript, HoldFirst];
Subscript[a_, i_Integer?NonNegative] := a[[i+1]]
Then:
a = {"Alice", "Bob"};
Subscript[a, 0]
Subscript[a, 1]
"Alice"
"Bob"
or an image:
answered 3 hours ago
Carl WollCarl Woll
69.1k392178
$endgroup$
$begingroup$
Thanks a lot! Your answer solved this perfectly! Hope this to be convenient for many users.
$endgroup$
– Like Tina
2 hours ago
add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
There's no need to use the Notation package to achieve the same behavior. For example:
SetAttributes[Subscript, HoldFirst];
Subscript[a_, i_Integer?NonNegative] := a[[i+1]]
Then:
a = {"Alice", "Bob"};
Subscript[a, 0]
Subscript[a, 1]
"Alice"
"Bob"
or an image:
answered 3 hours ago
Carl WollCarl Woll
69.1k392178
$endgroup$
$begingroup$
Thanks a lot! Your answer solved this perfectly! Hope this to be convenient for many users.
$endgroup$
– Like Tina
2 hours ago
add a comment |
$begingroup$
There's no need to use the Notation package to achieve the same behavior. For example:
SetAttributes[Subscript, HoldFirst];
Subscript[a_, i_Integer?NonNegative] := a[[i+1]]
Then:
a = {"Alice", "Bob"};
Subscript[a, 0]
Subscript[a, 1]
"Alice"
"Bob"
or an image:
answered 3 hours ago
Carl WollCarl Woll
69.1k392178
$endgroup$
$begingroup$
Thanks a lot! Your answer solved this perfectly! Hope this to be convenient for many users.
$endgroup$
– Like Tina
2 hours ago
add a comment |
$begingroup$
There's no need to use the Notation package to achieve the same behavior. For example:
SetAttributes[Subscript, HoldFirst];
Subscript[a_, i_Integer?NonNegative] := a[[i+1]]
Then:
a = {"Alice", "Bob"};
Subscript[a, 0]
Subscript[a, 1]
"Alice"
"Bob"
or an image:
answered 3 hours ago
Carl WollCarl Woll
69.1k392178
$endgroup$
There's no need to use the Notation package to achieve the same behavior. For example:
SetAttributes[Subscript, HoldFirst];
Subscript[a_, i_Integer?NonNegative] := a[[i+1]]
Then:
a = {"Alice", "Bob"};
Subscript[a, 0]
Subscript[a, 1]
"Alice"
"Bob"
or an image:
answered 3 hours ago
Carl WollCarl Woll
69.1k392178
answered 3 hours ago
Carl WollCarl Woll
69.1k392178
answered 3 hours ago
Carl WollCarl Woll
69.1k392178
answered 3 hours ago
Carl WollCarl Woll
69.1k392178
69.1k392178
$begingroup$
Thanks a lot! Your answer solved this perfectly! Hope this to be convenient for many users.
$endgroup$
– Like Tina
2 hours ago
add a comment |
$begingroup$
Thanks a lot! Your answer solved this perfectly! Hope this to be convenient for many users.
$endgroup$
– Like Tina
2 hours ago
$begingroup$
Thanks a lot! Your answer solved this perfectly! Hope this to be convenient for many users.
$endgroup$
– Like Tina
2 hours ago
$begingroup$
Thanks a lot! Your answer solved this perfectly! Hope this to be convenient for many users.
$endgroup$
– Like Tina
2 hours ago
add a comment |
Like Tina is a new contributor. Be nice, and check out our Code of Conduct.
Like Tina is a new contributor. Be nice, and check out our Code of Conduct.
Like Tina is a new contributor. Be nice, and check out our Code of Conduct.
Like Tina is a new contributor. Be nice, and check out our Code of Conduct.
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