Factory method pattern as type guard for classes with trait

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Factory method pattern as type guard for classes with trait














0












$begingroup$


I want to accept an eloquent model with a trait in some method. I can't type hint it, so I created guard class with factory method and using it for type checking. Is there code smell?



class SearchableModel extends Model
{
use Searchable;

public static function from(Searchable $searchable) :IlluminateDatabaseEloquentModel
{
return $searchable;
}

}

public function someMethod(Searchable $model) {
$model = SearchableModel::from($model);
$model->search('term');
}


P.S. My motivation is using static analysis









share







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    0












    $begingroup$


    I want to accept an eloquent model with a trait in some method. I can't type hint it, so I created guard class with factory method and using it for type checking. Is there code smell?



    class SearchableModel extends Model
    {
    use Searchable;

    public static function from(Searchable $searchable) :IlluminateDatabaseEloquentModel
    {
    return $searchable;
    }

    }

    public function someMethod(Searchable $model) {
    $model = SearchableModel::from($model);
    $model->search('term');
    }


    P.S. My motivation is using static analysis









    share







    New contributor




    matchish is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$















      0












      0








      0





      $begingroup$


      I want to accept an eloquent model with a trait in some method. I can't type hint it, so I created guard class with factory method and using it for type checking. Is there code smell?



      class SearchableModel extends Model
      {
      use Searchable;

      public static function from(Searchable $searchable) :IlluminateDatabaseEloquentModel
      {
      return $searchable;
      }

      }

      public function someMethod(Searchable $model) {
      $model = SearchableModel::from($model);
      $model->search('term');
      }


      P.S. My motivation is using static analysis









      share







      New contributor




      matchish is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      I want to accept an eloquent model with a trait in some method. I can't type hint it, so I created guard class with factory method and using it for type checking. Is there code smell?



      class SearchableModel extends Model
      {
      use Searchable;

      public static function from(Searchable $searchable) :IlluminateDatabaseEloquentModel
      {
      return $searchable;
      }

      }

      public function someMethod(Searchable $model) {
      $model = SearchableModel::from($model);
      $model->search('term');
      }


      P.S. My motivation is using static analysis







      laravel factory-method type-safety trait





      share







      New contributor




      matchish is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.










      share







      New contributor




      matchish is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.








      share



      share






      New contributor




      matchish is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      asked 36 secs ago









      matchishmatchish

      1014




      1014




      New contributor




      matchish is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      New contributor





      matchish is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      matchish is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






















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